Q. A wire has a resistance of 12 Ω and is made of a material with a resistivity of 3 x 10^-6 Ω·m. If the length of the wire is 4 m, what is its cross-sectional area?
A.
0.5 mm²
B.
1 mm²
C.
2 mm²
D.
3 mm²
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Solution
A = ρ * (L / R) = 3 x 10^-6 * (4 / 12) = 1 mm².
Correct Answer: B — 1 mm²
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Q. A wire has a resistance of 12 Ω. If it is stretched to double its length, what will be the new resistance assuming uniform cross-section?
A.
24 Ω
B.
48 Ω
C.
12 Ω
D.
6 Ω
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Solution
Resistance R is proportional to length; if length doubles, resistance also doubles to 24 Ω.
Correct Answer: A — 24 Ω
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Q. A wire has a resistance of 5 Ω at 20°C. If the temperature coefficient of resistivity is 0.004/°C, what will be its resistance at 100°C?
A.
5.4 Ω
B.
6.4 Ω
C.
7.4 Ω
D.
8.4 Ω
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Solution
R = R0(1 + α(T - T0)) = 5(1 + 0.004(100 - 20)) = 6.4 Ω.
Correct Answer: B — 6.4 Ω
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Q. A wire made of material A has a resistivity of 1.5 x 10^-8 Ω·m, while material B has a resistivity of 3.0 x 10^-8 Ω·m. If both wires have the same dimensions, which wire will have a higher resistance?
A.
Wire A
B.
Wire B
C.
Both have the same resistance
D.
Cannot be determined
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Solution
Resistance is directly proportional to resistivity; hence, wire B with higher resistivity will have higher resistance.
Correct Answer: B — Wire B
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Q. A wire made of material A has twice the length and half the cross-sectional area of a wire made of material B. If the resistivity of A is ρ, what is the resistance of wire A in terms of the resistance of wire B?
A.
2R
B.
4R
C.
R/2
D.
R/4
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Solution
Resistance R = ρ(L/A). For wire A, R_A = ρ(2L/(A/2)) = 4ρ(L/A) = 4R_B.
Correct Answer: B — 4R
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Q. A wire of length 10 m and cross-sectional area 2 mm² has a resistance of 3 Ω. What is the resistivity of the material?
A.
1.5 x 10^-6 Ω·m
B.
3 x 10^-6 Ω·m
C.
6 x 10^-6 Ω·m
D.
1.5 x 10^-5 Ω·m
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Solution
Resistivity ρ = R * (A / L) = 3 * (2 x 10^-6 / 10) = 1.5 x 10^-6 Ω·m.
Correct Answer: A — 1.5 x 10^-6 Ω·m
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Q. A wire of length L and cross-sectional area A is stretched by a force F. If the Young's modulus of the material is Y, what is the extension of the wire?
A.
F * L / (A * Y)
B.
A * Y * L / F
C.
F * A / (Y * L)
D.
Y * L / (F * A)
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Solution
The extension of the wire can be calculated using the formula: extension = (F * L) / (A * Y).
Correct Answer: A — F * L / (A * Y)
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Q. A wire of length L and cross-sectional area A is stretched by a force F. What is the expression for the elongation ΔL?
A.
ΔL = FL / (AE)
B.
ΔL = AE / (FL)
C.
ΔL = EFL / A
D.
ΔL = A / (FL)
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Solution
The elongation ΔL of a wire is given by ΔL = FL / (AE), where E is Young's modulus.
Correct Answer: A — ΔL = FL / (AE)
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Q. A wire of length L and cross-sectional area A is stretched by a force F. What is the expression for the elongation of the wire?
A.
ΔL = (F * L) / (A * Y)
B.
ΔL = (Y * F) / (A * L)
C.
ΔL = (A * Y) / (F * L)
D.
ΔL = (F * A) / (Y * L)
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Solution
The elongation ΔL of a wire is given by ΔL = (F * L) / (A * Y), where Y is Young's modulus.
Correct Answer: A — ΔL = (F * L) / (A * Y)
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Q. According to Ampere's Law, the line integral of the magnetic field B around a closed path is equal to what?
A.
Zero
B.
The product of permeability and current
C.
The product of permittivity and charge
D.
The electric field times the area
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Solution
Ampere's Law states that the line integral of the magnetic field B around a closed path is equal to μ₀ times the total current I enclosed by the path.
Correct Answer: B — The product of permeability and current
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Q. According to Ampere's Law, the line integral of the magnetic field B around a closed loop is equal to what?
A.
0
B.
μ₀ times the total current through the loop
C.
μ₀ times the total charge
D.
None of the above
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Solution
Ampere's Law states ∮B·dl = μ₀I_enc, where I_enc is the enclosed current.
Correct Answer: B — μ₀ times the total current through the loop
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Q. According to Ampere's Law, what is the line integral of the magnetic field around a closed loop equal to?
A.
0
B.
μ₀ times the total current through the loop
C.
μ₀ times the total charge
D.
None of the above
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Solution
Ampere's Law states that the line integral of B around a closed loop is μ₀ times the total current through the loop.
Correct Answer: B — μ₀ times the total current through the loop
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Q. According to Ampere's Law, what is the magnetic field inside a long straight conductor carrying current I?
A.
Zero
B.
μ₀I/2πr
C.
μ₀I/4πr
D.
μ₀I/πr
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Solution
Inside a long straight conductor, the magnetic field is zero because the contributions from all parts of the conductor cancel out.
Correct Answer: A — Zero
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Q. According to Charles's Law, how does the volume of a gas change with temperature at constant pressure?
A.
V ∝ T
B.
V ∝ 1/T
C.
V + T = constant
D.
VT = constant
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Solution
Charles's Law states that the volume of a gas is directly proportional to its absolute temperature at constant pressure, expressed as V ∝ T.
Correct Answer: A — V ∝ T
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Q. According to Charles's Law, what happens to the volume of a gas when the temperature increases at constant pressure?
A.
Volume decreases
B.
Volume remains constant
C.
Volume increases
D.
Volume becomes zero
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Solution
Charles's Law states that the volume of a gas is directly proportional to its absolute temperature at constant pressure, meaning that as temperature increases, volume also increases.
Correct Answer: C — Volume increases
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Q. According to Faraday's law, the induced EMF in a circuit is directly proportional to what?
A.
The rate of change of magnetic flux
B.
The strength of the magnetic field
C.
The resistance of the circuit
D.
The length of the conductor
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Solution
Faraday's law states that the induced EMF is directly proportional to the rate of change of magnetic flux through the circuit.
Correct Answer: A — The rate of change of magnetic flux
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Q. According to Faraday's law, the induced EMF in a circuit is proportional to what?
A.
The rate of change of magnetic flux
B.
The strength of the magnetic field
C.
The resistance of the circuit
D.
The length of the conductor
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Solution
Faraday's law states that the induced EMF is directly proportional to the rate of change of magnetic flux through the circuit.
Correct Answer: A — The rate of change of magnetic flux
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Q. According to Kirchhoff's Current Law, if three currents enter a junction as 2A, 3A, and 1A, what is the total current leaving the junction?
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Solution
According to Kirchhoff's Current Law, total current entering = total current leaving. 2A + 3A + 1A = 6A.
Correct Answer: B — 5A
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Q. According to Kirchhoff's Current Law, if three currents enter a junction as 2A, 3A, and 4A, what is the total current leaving the junction?
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Solution
According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Total entering = 2A + 3A + 4A = 9A.
Correct Answer: D — 9A
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Q. According to Kirchhoff's Current Law, if three currents enter a junction as 2A, 3A, and 4A, what is the current leaving the junction?
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Solution
According to Kirchhoff's Current Law, the sum of currents entering a junction equals the sum of currents leaving. Therefore, I_out = 2A + 3A + 4A = 9A.
Correct Answer: D — 9A
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Q. According to Kirchhoff's Current Law, if three currents entering a junction are 2A, 3A, and 5A, what is the total current leaving the junction?
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Solution
According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Therefore, total current leaving = 2A + 3A + 5A = 10A.
Correct Answer: A — 10A
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Q. According to Kirchhoff's Voltage Law, the sum of the potential differences around any closed loop in a circuit must equal what?
A.
Zero
B.
The total current
C.
The total resistance
D.
The total power
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Solution
Kirchhoff's Voltage Law states that the sum of the electrical potential differences (voltage) around any closed circuit is zero.
Correct Answer: A — Zero
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Q. According to Kirchhoff's Voltage Law, the sum of the potential differences around any closed loop in a circuit is equal to what?
A.
Zero
B.
The total current
C.
The total resistance
D.
The total power
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Solution
Kirchhoff's Voltage Law states that the sum of the electromotive forces and potential differences in any closed loop is zero.
Correct Answer: A — Zero
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Q. According to Newton's third law, if object A exerts a force on object B, what does object B do?
A.
Exerts a greater force on A
B.
Exerts an equal and opposite force on A
C.
Exerts no force
D.
Exerts a lesser force on A
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Solution
Newton's third law states that for every action, there is an equal and opposite reaction.
Correct Answer: B — Exerts an equal and opposite force on A
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Q. According to the Biot-Savart Law, the magnetic field dB at a point due to a current element Idl is proportional to which of the following?
A.
Idl
B.
sin(θ)
C.
1/r^2
D.
Both Idl and sin(θ)
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Solution
The magnetic field dB is proportional to Idl and sin(θ), where θ is the angle between the current element and the line connecting the current element to the point of interest.
Correct Answer: D — Both Idl and sin(θ)
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Q. According to the kinetic theory of gases, the pressure exerted by a gas is due to:
A.
the gravitational force on the gas
B.
the collisions of gas molecules with the walls of the container
C.
the temperature of the gas
D.
the volume of the gas
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Solution
The pressure exerted by a gas is due to the collisions of gas molecules with the walls of the container, which transfers momentum to the walls.
Correct Answer: B — the collisions of gas molecules with the walls of the container
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Q. According to the kinetic theory, the pressure exerted by a gas is due to which of the following?
A.
The weight of the gas molecules.
B.
The collisions of gas molecules with the walls of the container.
C.
The temperature of the gas.
D.
The volume of the gas.
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Solution
The pressure of a gas is caused by the collisions of gas molecules with the walls of the container, which exert force on the walls.
Correct Answer: B — The collisions of gas molecules with the walls of the container.
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Q. According to the kinetic theory, the pressure exerted by a gas is due to:
A.
Gravitational force
B.
Molecular collisions with the walls
C.
Temperature of the gas
D.
Volume of the gas
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Solution
The pressure exerted by a gas is due to the collisions of gas molecules with the walls of the container.
Correct Answer: B — Molecular collisions with the walls
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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground?
A.
4 s
B.
5 s
C.
6 s
D.
8 s
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Solution
Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Solving for t gives t = sqrt(2h/g) = sqrt(2*80/9.8) ≈ 4.04 s, approximately 4 s.
Correct Answer: B — 5 s
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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Assume g = 10 m/s²)
A.
4 s
B.
5 s
C.
6 s
D.
8 s
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Solution
Using the formula: h = 0.5 * g * t². 80 = 0.5 * 10 * t². Solving gives t² = 16, so t = 4 s.
Correct Answer: B — 5 s
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