Physics Syllabus (JEE Main)
Q. What is the phenomenon called when light waves are restricted to vibrate in a single plane?
A.
Refraction
B.
Diffraction
C.
Polarization
D.
Interference
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Solution
The phenomenon of light waves being restricted to vibrate in a single plane is called polarization.
Correct Answer: C — Polarization
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Q. What is the phenomenon called when light waves bend around the edges of an obstacle?
A.
Reflection
B.
Refraction
C.
Diffraction
D.
Interference
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Solution
The bending of light waves around the edges of an obstacle is known as diffraction.
Correct Answer: C — Diffraction
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Q. What is the phenomenon called when sound waves bend around obstacles?
A.
Reflection
B.
Refraction
C.
Diffraction
D.
Interference
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Solution
The bending of sound waves around obstacles is known as diffraction.
Correct Answer: C — Diffraction
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Q. What is the phenomenon of diffraction primarily associated with?
A.
Reflection of light
B.
Bending of waves around obstacles
C.
Interference of waves
D.
Polarization of light
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Solution
Diffraction is the bending of waves around obstacles and the spreading of waves when they pass through small openings.
Correct Answer: B — Bending of waves around obstacles
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Q. What is the phenomenon of diffraction primarily responsible for?
A.
Bending of light around obstacles
B.
Reflection of light
C.
Refraction of light
D.
Polarization of light
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Solution
Diffraction is the bending of waves around obstacles and the spreading of waves when they pass through small openings.
Correct Answer: A — Bending of light around obstacles
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Q. What is the phenomenon of electromagnetic induction?
A.
The generation of electric current by a changing magnetic field
B.
The generation of magnetic field by a changing electric current
C.
The interaction between electric and magnetic fields
D.
The conversion of mechanical energy into electrical energy
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Solution
Electromagnetic induction refers to the generation of electric current in a conductor due to a changing magnetic field.
Correct Answer: A — The generation of electric current by a changing magnetic field
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Q. What is the phenomenon of polarization in light?
A.
The splitting of light into different colors
B.
The alignment of light waves in a particular direction
C.
The reflection of light off a surface
D.
The bending of light as it passes through a medium
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Solution
Polarization refers to the orientation of the oscillations of light waves in a particular direction.
Correct Answer: B — The alignment of light waves in a particular direction
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Q. What is the photoelectric effect primarily used for in technology?
A.
Solar panels
B.
LEDs
C.
Lasers
D.
Television screens
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Solution
The photoelectric effect is primarily used in solar panels to convert light energy into electrical energy.
Correct Answer: A — Solar panels
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Q. What is the photoelectric effect?
A.
Emission of electrons from a metal surface when light shines on it
B.
Absorption of light by a metal surface
C.
Reflection of light from a metal surface
D.
Transmission of light through a metal surface
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Solution
The photoelectric effect is the phenomenon where electrons are emitted from a metal surface when it is exposed to light of sufficient frequency.
Correct Answer: A — Emission of electrons from a metal surface when light shines on it
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Q. What is the potential at a distance of 1 m from a dipole with a dipole moment of 2 × 10^-9 C·m?
A.
0 V
B.
1 V
C.
2 V
D.
4 V
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Solution
Potential due to a dipole V = (1/4πε₀) * (p * cosθ) / r². At 1 m, it is negligible.
Correct Answer: A — 0 V
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Q. What is the potential difference across a 10 ohm resistor carrying a current of 2A?
A.
5V
B.
10V
C.
15V
D.
20V
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Solution
Using Ohm's law, V = I * R = 2A * 10 ohms = 20V.
Correct Answer: D — 20V
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Q. What is the potential difference across a 10Ω resistor if a current of 2A flows through it?
A.
5V
B.
10V
C.
20V
D.
15V
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Solution
Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.
Correct Answer: C — 20V
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Q. What is the potential difference across a 10Ω resistor if a current of 4A flows through it?
A.
20V
B.
40V
C.
10V
D.
30V
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Solution
Using Ohm's Law, V = I * R = 4A * 10Ω = 40V.
Correct Answer: A — 20V
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Q. What is the potential difference across a 5 Ω resistor carrying a current of 2 A?
A.
10 V
B.
5 V
C.
2 V
D.
0 V
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Solution
Using Ohm's law, V = I * R = 2 A * 5 Ω = 10 V.
Correct Answer: A — 10 V
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Q. What is the potential difference across the galvanometer in a balanced Wheatstone bridge?
A.
Zero
B.
Equal to the supply voltage
C.
Depends on the resistances
D.
Half of the supply voltage
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Solution
In a balanced Wheatstone bridge, the potential difference across the galvanometer is zero, indicating no current flows through it.
Correct Answer: A — Zero
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Q. What is the potential difference between two points A and B if the electric field is 5 N/C and the distance between them is 3 m?
A.
15 V
B.
5 V
C.
3 V
D.
0 V
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Solution
Potential difference V = E * d = 5 N/C * 3 m = 15 V.
Correct Answer: A — 15 V
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Q. What is the potential difference between two points A and B if the electric field is uniform and equal to 50 N/C, and the distance between A and B is 2m?
A.
100 V
B.
50 V
C.
25 V
D.
0 V
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Solution
Potential difference V = E * d = 50 N/C * 2 m = 100 V.
Correct Answer: A — 100 V
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Q. What is the potential difference between two points A and B in an electric field if the work done in moving a charge of 5μC from A to B is 0.02 J?
A.
4 V
B.
2 V
C.
10 V
D.
0.1 V
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Solution
Potential difference V = W/Q = 0.02 J / (5 × 10^-6 C) = 4000 V = 4 V.
Correct Answer: A — 4 V
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Q. What is the potential difference between two points A and B in an electric field if the work done in moving a charge of +2C from A to B is 10J?
A.
5 V
B.
10 V
C.
20 V
D.
2 V
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Solution
V = W/Q = 10 J / 2 C = 5 V.
Correct Answer: B — 10 V
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Q. What is the potential difference between two points A and B in an electric field of 200 N/C if the distance between them is 0.5 m?
A.
100 V
B.
200 V
C.
50 V
D.
25 V
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Solution
Potential difference V = E * d = 200 N/C * 0.5 m = 100 V.
Correct Answer: A — 100 V
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Q. What is the potential difference between two points A and B in an electric field if the work done in moving a charge of 5μC from A to B is 10mJ?
A.
2V
B.
5V
C.
10V
D.
20V
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Solution
Potential difference V = W/Q = 10mJ / 5μC = 10 × 10^-3 J / 5 × 10^-6 C = 2V.
Correct Answer: B — 5V
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Q. What is the potential difference between two points in a uniform electric field of strength 200 N/C separated by 3m?
A.
600 V
B.
200 V
C.
300 V
D.
400 V
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Solution
V = E * d = 200 N/C * 3 m = 600 V.
Correct Answer: A — 600 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC is 0.04 J?
A.
20 V
B.
10 V
C.
5 V
D.
2 V
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Solution
Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.
Correct Answer: A — 20 V
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Q. What is the potential difference between two points in an electric field if the work done to move a charge of 2μC is 0.04 J?
A.
20 V
B.
30 V
C.
40 V
D.
50 V
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Solution
Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20,000 V = 20 V.
Correct Answer: C — 40 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of 3 C from one point to another is 15 J?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
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Solution
Potential difference V = Work done / Charge = 15 J / 3 C = 5 V.
Correct Answer: B — 10 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC between them is 0.04 J?
A.
20 V
B.
10 V
C.
5 V
D.
2 V
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Solution
V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.
Correct Answer: A — 20 V
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Q. What is the potential difference between two points in an electric field if the work done to move a charge of 2C is 10J?
A.
5V
B.
20V
C.
2V
D.
10V
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Solution
Potential difference V = W/Q = 10J / 2C = 5V.
Correct Answer: B — 20V
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Q. What is the potential energy of a charge q placed in an electric potential V?
A.
qV
B.
q/V
C.
V/q
D.
q²V
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Solution
The potential energy U of a charge q in an electric potential V is given by U = qV.
Correct Answer: A — qV
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Q. What is the potential energy of a dipole in a uniform electric field E when it is aligned with the field?
A.
-pE
B.
0
C.
pE
D.
pE/2
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Solution
Potential energy U = -p · E. When aligned, U = -pE.
Correct Answer: A — -pE
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Q. What is the potential energy of a mass of 5 kg at a height of 10 m in a gravitational field (g = 9.8 m/s²)?
A.
490 J
B.
980 J
C.
245 J
D.
50 J
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Solution
Potential energy PE = mgh = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer: B — 980 J
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