Physics Syllabus (JEE Main)
Q. What is the potential energy of a system of two charges +3μC and +4μC separated by 0.2m?
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A.
0.54 J
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B.
0.72 J
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C.
0.36 J
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D.
0.18 J
Solution
U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6 * 4 × 10^-6) / 0.2 = 0.54 J.
Correct Answer: B — 0.72 J
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Q. What is the potential energy of a system of two charges +3μC and +5μC separated by 0.2m?
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A.
-6.75 J
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B.
6.75 J
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C.
0.75 J
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D.
-0.75 J
Solution
Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6) * (5 × 10^-6) / 0.2 = 6.75 J.
Correct Answer: B — 6.75 J
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Q. What is the potential energy of a system of two charges +3μC and -5μC separated by 0.3m?
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A.
-0.45 J
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B.
0.45 J
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C.
-0.15 J
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D.
0.15 J
Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9) * (3 × 10^-6) * (-5 × 10^-6) / 0.3 = -0.45 J.
Correct Answer: A — -0.45 J
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Q. What is the potential energy of a system of two charges +5μC and +10μC separated by 0.2m?
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A.
-0.225 J
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B.
0.225 J
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C.
0.45 J
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D.
0.9 J
Solution
Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (5 × 10^-6) * (10 × 10^-6) / 0.2 = 0.225 J.
Correct Answer: B — 0.225 J
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Q. What is the potential energy of a system of two charges +q and +q separated by a distance r?
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A.
0
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B.
k*q²/r
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C.
-k*q²/r
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D.
2k*q²/r
Solution
Potential energy U = k * (q1 * q2) / r = k * (q * q) / r = k*q²/r.
Correct Answer: B — k*q²/r
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Q. What is the potential energy of a system of two charges of +1μC and -1μC separated by 0.1m?
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A.
-0.09 J
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B.
0.09 J
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C.
-0.18 J
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D.
0.18 J
Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9) * (1 × 10^-6) * (-1 × 10^-6) / 0.1 = -0.09 J.
Correct Answer: A — -0.09 J
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Q. What is the potential energy of a system of two point charges +q and -q separated by a distance r?
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A.
0
-
B.
kq²/r
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C.
-kq²/r
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D.
kq/r
Solution
The potential energy U of a system of two point charges is given by U = k(q1q2)/r = -kq²/r for +q and -q.
Correct Answer: C — -kq²/r
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Q. What is the potential energy of a system of two point charges q1 and q2 separated by a distance r?
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A.
k * q1 * q2 / r
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B.
k * q1 * q2 * r
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C.
k * (q1 + q2) / r
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D.
k * (q1 - q2) / r
Solution
The potential energy U of a system of two point charges is given by U = k * q1 * q2 / r.
Correct Answer: A — k * q1 * q2 / r
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Q. What is the potential energy stored in a spring when it is compressed by a distance x?
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A.
1/2 kx
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B.
1/2 kx²
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C.
kx
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D.
kx²
Solution
The potential energy (PE) stored in a spring is given by PE = 1/2 kx², where k is the spring constant and x is the displacement.
Correct Answer: B — 1/2 kx²
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Q. What is the power consumed by a 10 ohm resistor when a current of 2 A flows through it?
-
A.
20 W
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B.
40 W
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C.
10 W
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D.
5 W
Solution
Power P = I^2 * R = (2 A)^2 * 10Ω = 4 * 10 = 40 W.
Correct Answer: B — 40 W
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Q. What is the power consumed by a 10 ohm resistor when a current of 3 A flows through it?
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A.
30 W
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B.
90 W
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C.
60 W
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D.
15 W
Solution
Power P = I^2 * R = (3 A)^2 * 10 ohms = 9 * 10 = 90 W.
Correct Answer: B — 90 W
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Q. What is the power consumed by a 10Ω resistor when a current of 2A flows through it?
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A.
20W
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B.
40W
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C.
10W
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D.
5W
Solution
Power P = I^2 * R = (2A)^2 * 10Ω = 4A^2 * 10Ω = 40W.
Correct Answer: A — 20W
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Q. What is the power consumed by a 12 V battery supplying a current of 2 A?
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A.
24 W
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B.
12 W
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C.
6 W
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D.
48 W
Solution
Power is given by P = V * I = 12 V * 2 A = 24 W.
Correct Answer: A — 24 W
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Q. What is the power consumed by a 5 ohm resistor carrying a current of 3 A?
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A.
15 W
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B.
9 W
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C.
5 W
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D.
3 W
Solution
Power P = I^2 * R = (3 A)^2 * 5 ohms = 9 * 5 = 45 W.
Correct Answer: A — 15 W
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Q. What is the power consumed by a 5 ohm resistor when a current of 2A flows through it?
-
A.
10W
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B.
20W
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C.
5W
-
D.
15W
Solution
Power P = I^2 * R = (2A)^2 * 5 ohms = 4 * 5 = 20W.
Correct Answer: B — 20W
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Q. What is the power consumed by a 5 ohm resistor when a current of 3 A flows through it?
-
A.
15 W
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B.
9 W
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C.
5 W
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D.
3 W
Solution
Power P = I^2 * R = (3 A)^2 * 5 ohms = 9 * 5 = 45 W.
Correct Answer: A — 15 W
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Q. What is the power dissipated in a 10Ω resistor carrying a current of 2A?
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A.
20W
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B.
30W
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C.
40W
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D.
50W
Solution
Power P = I^2 * R = (2A)^2 * 10Ω = 4 * 10 = 40W.
Correct Answer: A — 20W
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Q. What is the power dissipated in a 4 ohm resistor carrying a current of 3 A?
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A.
12 W
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B.
9 W
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C.
6 W
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D.
3 W
Solution
Using the power formula P = I^2 * R, we have P = (3 A)^2 * 4 ohms = 9 * 4 = 36 W.
Correct Answer: A — 12 W
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Q. What is the power dissipated in a resistor of 10 ohms carrying a current of 2 A?
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A.
20 W
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B.
10 W
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C.
5 W
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D.
40 W
Solution
Using the power formula P = I^2 * R, we have P = (2 A)^2 * 10 ohms = 4 * 10 = 40 W.
Correct Answer: A — 20 W
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Q. What is the power dissipated in a resistor of 5Ω carrying a current of 2A?
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A.
5W
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B.
10W
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C.
20W
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D.
40W
Solution
Power is given by P = I^2 * R = (2A)^2 * 5Ω = 4A^2 * 5Ω = 20W.
Correct Answer: B — 10W
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Q. What is the power dissipated in a resistor of 5Ω carrying a current of 3A?
Solution
Power P = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.
Correct Answer: A — 15W
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Q. What is the power dissipated in a resistor of 8Ω when a current of 2A flows through it?
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A.
4W
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B.
8W
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C.
16W
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D.
32W
Solution
Power P = I^2 * R = (2A)^2 * 8Ω = 4A^2 * 8Ω = 32W.
Correct Answer: C — 16W
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Q. What is the power factor in a circuit with a phase angle of 60 degrees?
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A.
0.5
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B.
0.866
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C.
1
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D.
0
Solution
The power factor is cos(60°) = 0.5.
Correct Answer: B — 0.866
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Q. What is the power factor of a circuit with a phase angle of 60 degrees?
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A.
0.5
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B.
0.866
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C.
1
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D.
0.707
Solution
The power factor (PF) is given by cos(θ). For a phase angle of 60 degrees, PF = cos(60°) = 0.5.
Correct Answer: B — 0.866
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Q. What is the power factor of an AC circuit with a phase angle of 60 degrees?
-
A.
0.5
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B.
0.866
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C.
1
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D.
0.707
Solution
The power factor (PF) is given by cos(θ). For a phase angle of 60 degrees, PF = cos(60°) = 0.5.
Correct Answer: B — 0.866
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Q. What is the power of a lens with a focal length of 50 cm?
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A.
+2 D
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B.
+1 D
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C.
-2 D
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D.
-1 D
Solution
Power (P) is given by P = 1/f (in meters). Thus, f = 50 cm = 0.5 m, so P = 1/0.5 = +2 D.
Correct Answer: A — +2 D
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Q. What is the prefix for 10^-6 in the SI system?
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A.
Milli
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B.
Micro
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C.
Nano
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D.
Pico
Solution
The prefix for 10^-6 is 'Micro'.
Correct Answer: B — Micro
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Q. What is the primary advantage of using digital signals over analog signals in communication systems?
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A.
Higher bandwidth
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B.
Less susceptibility to noise
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C.
Easier to modulate
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D.
Lower power consumption
Solution
Digital signals are less susceptible to noise, making them more reliable for communication compared to analog signals.
Correct Answer: B — Less susceptibility to noise
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Q. What is the primary application of nuclear fusion in stars?
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A.
Energy production
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B.
Nuclear weapons
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C.
Radioactive dating
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D.
Medical imaging
Solution
Nuclear fusion in stars primarily serves as a source of energy production, converting hydrogen into helium and releasing vast amounts of energy.
Correct Answer: A — Energy production
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Q. What is the primary assumption of the kinetic theory of gases regarding the motion of gas molecules?
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A.
Gas molecules are stationary.
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B.
Gas molecules move in straight lines until they collide.
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C.
Gas molecules are always in a state of vibration.
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D.
Gas molecules have a fixed volume.
Solution
The kinetic theory assumes that gas molecules move in straight lines until they collide with each other or the walls of the container.
Correct Answer: B — Gas molecules move in straight lines until they collide.
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