What is the potential difference between two points A and B if the electric field is uniform and equal to 50 N/C, and the distance between A and B is 2m?
Practice Questions
1 question
Q1
What is the potential difference between two points A and B if the electric field is uniform and equal to 50 N/C, and the distance between A and B is 2m?
100 V
50 V
25 V
0 V
Potential difference V = E * d = 50 N/C * 2 m = 100 V.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the potential difference between two points A and B if the electric field is uniform and equal to 50 N/C, and the distance between A and B is 2m?
Solution: Potential difference V = E * d = 50 N/C * 2 m = 100 V.
Steps: 5
Step 1: Identify the electric field strength (E). In this case, E = 50 N/C.
Step 2: Identify the distance (d) between points A and B. Here, d = 2 m.
Step 3: Use the formula for potential difference (V), which is V = E * d.
Step 4: Substitute the values into the formula: V = 50 N/C * 2 m.
