Q. What is the formula for the force experienced by a charged particle moving in a magnetic field?
A.
F = qvB sin(θ)
B.
F = qvB cos(θ)
C.
F = qB
D.
F = qE
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Solution
The force on a charged particle moving in a magnetic field is given by F = qvB sin(θ), where θ is the angle between the velocity and the magnetic field.
Correct Answer: A — F = qvB sin(θ)
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Q. What is the formula for the fringe separation in a double-slit experiment?
A.
λD/d
B.
d/λD
C.
D/λd
D.
λd/D
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Solution
The fringe separation (β) is given by the formula β = λD/d, where λ is the wavelength, D is the distance to the screen, and d is the distance between the slits.
Correct Answer: A — λD/d
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Q. What is the formula for the fringe width in a double-slit experiment?
A.
λD/d
B.
d/λD
C.
D/λd
D.
λd/D
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Solution
The fringe width (β) is given by the formula β = λD/d, where D is the distance from the slits to the screen and d is the distance between the slits.
Correct Answer: A — λD/d
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Q. What is the formula for the inductive reactance (X_L) in an AC circuit? (2022)
A.
X_L = 2πfL
B.
X_L = R/L
C.
X_L = 1/(2πfC)
D.
X_L = V/I
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Solution
The formula for inductive reactance is X_L = 2πfL, where f is the frequency and L is the inductance.
Correct Answer: A — X_L = 2πfL
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Q. What is the formula for the magnetic field (B) inside a solenoid?
A.
B = μ₀(nI)
B.
B = μ₀I
C.
B = μ₀(nI)/L
D.
B = μ₀I²
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Solution
The magnetic field inside a solenoid is given by B = μ₀(nI), where n is the number of turns per unit length.
Correct Answer: A — B = μ₀(nI)
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Q. What is the formula for the magnetic field at the center of a circular loop of radius r carrying a current I? (2023)
A.
B = μ₀I/2r
B.
B = μ₀I/r
C.
B = μ₀I/4r
D.
B = μ₀I/πr
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Solution
The magnetic field (B) at the center of a circular loop is given by B = μ₀I/2r.
Correct Answer: A — B = μ₀I/2r
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Q. What is the formula for the magnetic force experienced by a charged particle moving in a magnetic field?
A.
F = qE
B.
F = qvBsin(θ)
C.
F = mv^2/r
D.
F = BIL
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Solution
The magnetic force on a charged particle is given by F = qvBsin(θ), where q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.
Correct Answer: B — F = qvBsin(θ)
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Q. What is the formula for the magnetic force on a charge q moving with velocity v in a magnetic field B?
A.
F = qvB
B.
F = qvBsinθ
C.
F = qB
D.
F = qvBcosθ
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Solution
The magnetic force on a charge moving in a magnetic field is given by F = qvBsinθ, where θ is the angle between v and B.
Correct Answer: B — F = qvBsinθ
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Q. What is the formula for the magnetic force on a charged particle moving in a magnetic field?
A.
F = qE
B.
F = qvBsinθ
C.
F = mv^2/r
D.
F = qvE
Show solution
Solution
The magnetic force on a charged particle is given by F = qvBsinθ, where q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between v and B.
Correct Answer: B — F = qvBsinθ
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Q. What is the formula for the modulus of resilience?
A.
U = 1/2 * σ * ε
B.
U = σ * ε
C.
U = 1/2 * ε^2
D.
U = σ^2 / 2
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Solution
The modulus of resilience is given by U = 1/2 * σ * ε, where σ is the yield stress and ε is the yield strain.
Correct Answer: A — U = 1/2 * σ * ε
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Q. What is the formula for the resonant frequency of an RLC circuit? (2021)
A.
f = 1/(2π√(LC))
B.
f = R/(2πL)
C.
f = 1/(2πRC)
D.
f = 2π√(LC)
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Solution
The resonant frequency f of an RLC circuit is given by f = 1/(2π√(LC)).
Correct Answer: A — f = 1/(2π√(LC))
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Q. What is the formula for the total impedance in a parallel RLC circuit? (2023)
A.
1/Z = 1/Z1 + 1/Z2 + 1/Z3
B.
Z = R + jX
C.
Z = R
D.
.
X
.
Z = R + jωL - j/(ωC)
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Solution
The total impedance in a parallel circuit is given by 1/Z = 1/Z1 + 1/Z2 + 1/Z3.
Correct Answer: A — 1/Z = 1/Z1 + 1/Z2 + 1/Z3
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Q. What is the formula for the total impedance in a series RLC circuit? (2023)
A.
Z = R + j(XL - XC)
B.
Z = R + jXL + jXC
C.
Z = R + jωL
D.
Z = R + jωC
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Solution
The total impedance in a series RLC circuit is given by Z = R + j(XL - XC).
Correct Answer: A — Z = R + j(XL - XC)
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Q. What is the formula for the total power in a series RLC circuit?
A.
P = VI
B.
P = I^2R
C.
P = V^2/R
D.
P = VI cos(φ)
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Solution
The total power in a series RLC circuit is given by P = VI cos(φ), where φ is the phase angle.
Correct Answer: D — P = VI cos(φ)
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Q. What is the formula for Young's modulus?
A.
Stress/Strain
B.
Strain/Stress
C.
Force/Area
D.
Area/Force
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Solution
Young's modulus (E) is defined as the ratio of stress to strain.
Correct Answer: A — Stress/Strain
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Q. What is the formula of the compound formed between magnesium and chlorine?
A.
MgCl
B.
MgCl2
C.
Mg2Cl
D.
Mg2Cl2
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Solution
The formula of the compound formed between magnesium and chlorine is MgCl2.
Correct Answer: B — MgCl2
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Q. What is the formula of the compound formed when magnesium reacts with oxygen?
A.
MgO
B.
Mg2O3
C.
MgO2
D.
Mg3O2
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Solution
Magnesium reacts with oxygen to form magnesium oxide, which has the formula MgO.
Correct Answer: A — MgO
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Q. What is the freezing point depression constant (Kf) for water?
A.
1.86 °C kg/mol
B.
0.52 °C kg/mol
C.
2.00 °C kg/mol
D.
3.72 °C kg/mol
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Solution
The freezing point depression constant (Kf) for water is 1.86 °C kg/mol.
Correct Answer: A — 1.86 °C kg/mol
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Q. What is the freezing point depression of a solution containing 1 mol of NaCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol) (2023)
A.
1.86 °C
B.
3.72 °C
C.
2.00 °C
D.
0.93 °C
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Solution
Freezing point depression (ΔTf) = i * Kf * m. For NaCl, i = 2 (dissociates into Na+ and Cl-). m = 1 mol/kg. ΔTf = 2 * 1.86 °C kg/mol * 1 = 3.72 °C.
Correct Answer: B — 3.72 °C
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Q. What is the freezing point depression of a solution containing 1 mole of NaCl in 1 kg of water? (2022)
A.
1.86 °C
B.
3.72 °C
C.
2.52 °C
D.
0.93 °C
Show solution
Solution
Freezing point depression = i * Kf * m = 2 * 1.86 * 1 = 3.72 °C (i = 2 for NaCl).
Correct Answer: A — 1.86 °C
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Q. What is the freezing point depression of a solution containing 1 mole of solute in 1 kg of water? (Kf for water = 1.86 °C kg/mol) (2020)
A.
1.86 °C
B.
3.72 °C
C.
0.93 °C
D.
2.78 °C
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Solution
Freezing point depression = Kf * m = 1.86 °C kg/mol * 1 mol/kg = 1.86 °C.
Correct Answer: A — 1.86 °C
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Q. What is the freezing point depression of a solution containing 2 moles of KCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol)
A.
3.72 °C
B.
1.86 °C
C.
2.0 °C
D.
5.58 °C
Show solution
Solution
Freezing point depression = i * Kf * m = 3 * 1.86 * 2 = 11.16 °C.
Correct Answer: A — 3.72 °C
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Q. What is the freezing point depression of a solution containing 2 moles of KCl in 1 kg of water?
A.
-3.72 °C
B.
-1.86 °C
C.
-2.52 °C
D.
-4.0 °C
Show solution
Solution
Freezing point depression = i * Kf * m = 3 * 1.86 * 2 = 11.16 °C, so the freezing point is lowered by 3.72 °C.
Correct Answer: A — -3.72 °C
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Q. What is the freezing point depression of a solution containing 2 moles of NaCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol)
A.
3.72 °C
B.
1.86 °C
C.
2.72 °C
D.
5.72 °C
Show solution
Solution
Freezing point depression = i * Kf * m = 3 * 1.86 * 2 = 11.16 °C.
Correct Answer: A — 3.72 °C
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Q. What is the freezing point depression of a solution containing 3 moles of KCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol) (2022)
A.
5.58 °C
B.
3.72 °C
C.
1.86 °C
D.
7.44 °C
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Solution
Freezing point depression = i * Kf * m = 3 * 1.86 * 3 = 5.58 °C (i = 2 for KCl).
Correct Answer: A — 5.58 °C
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Q. What is the freezing point depression of a solution directly proportional to?
A.
The molar mass of the solute
B.
The number of solute particles
C.
The volume of the solvent
D.
The temperature of the solvent
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Solution
Freezing point depression is directly proportional to the number of solute particles in the solution.
Correct Answer: B — The number of solute particles
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Q. What is the freezing point depression of a solution if 0.5 mol of a non-volatile solute is dissolved in 1 kg of water? (Kf for water = 1.86 °C kg/mol)
A.
0.93 °C
B.
1.86 °C
C.
3.72 °C
D.
0.5 °C
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Solution
Freezing point depression = Kf * molality = 1.86 * 0.5 = 0.93 °C.
Correct Answer: A — 0.93 °C
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Q. What is the freezing point of a solution containing 0.3 mol of glucose in 1 kg of water? (K_f for water = 1.86 °C kg/mol)
A.
-0.558 °C
B.
-0.558 K
C.
-1.86 °C
D.
-1.86 K
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Solution
Freezing point depression = K_f * m = 1.86 * 0.3 = 0.558 °C; Freezing point = 0 - 0.558 = -0.558 °C
Correct Answer: A — -0.558 °C
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Q. What is the frequency of a pendulum that completes 30 oscillations in 60 seconds? (2017)
A.
0.5 Hz
B.
1 Hz
C.
2 Hz
D.
3 Hz
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Solution
Frequency f = number of oscillations / time = 30 / 60 = 0.5 Hz.
Correct Answer: B — 1 Hz
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Q. What is the frequency of a sound wave with a period of 0.01 seconds? (2014)
A.
100 Hz
B.
200 Hz
C.
50 Hz
D.
10 Hz
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Solution
Frequency = 1/Period = 1/0.01 s = 100 Hz.
Correct Answer: A — 100 Hz
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