What is the freezing point depression of a solution containing 2 moles of KCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol)

1 question

1 item

Q: What is the freezing point depression of a solution containing 2 moles of KCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol)

Solution: Freezing point depression = i * Kf * m = 3 * 1.86 * 2 = 11.16 °C.

Steps: 7

Step 1: Identify the formula for freezing point depression, which is ΔTf = i * Kf * m.
Step 2: Determine the van 't Hoff factor (i) for KCl. Since KCl dissociates into 2 ions (K+ and Cl-), i = 3.
Step 3: Identify the Kf value for water, which is given as 1.86 °C kg/mol.
Step 4: Identify the number of moles of KCl in the solution, which is given as 2 moles.
Step 5: Calculate the freezing point depression using the formula: ΔTf = i * Kf * m = 3 * 1.86 * 2.
Step 6: Perform the multiplication: 3 * 1.86 = 5.58, then 5.58 * 2 = 11.16 °C.
Step 7: Conclude that the freezing point depression of the solution is 11.16 °C.