Q. A force of 10 N is applied to a 2 kg object at rest. What is the final velocity of the object after 5 seconds?
A.
2 m/s
B.
5 m/s
C.
10 m/s
D.
15 m/s
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Solution
Using F = ma, a = F/m = 10 N / 2 kg = 5 m/s². Final velocity v = u + at = 0 + 5 * 5 = 25 m/s.
Correct Answer: B — 5 m/s
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Q. A force of 10 N is applied to a 2 kg object. What is the net force acting on the object if it is also experiencing a frictional force of 4 N?
A.
6 N
B.
10 N
C.
14 N
D.
4 N
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Solution
Net force = applied force - frictional force = 10 N - 4 N = 6 N.
Correct Answer: A — 6 N
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Q. A force of 10 N is applied to a 2 kg object. What is the object's acceleration?
A.
5 m/s²
B.
10 m/s²
C.
2 m/s²
D.
20 m/s²
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Solution
Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².
Correct Answer: A — 5 m/s²
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Q. A force of 10 N is applied to a 2 kg object. What is the resulting acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we have a = F/m = 10 N / 2 kg = 5 m/s².
Correct Answer: A — 2 m/s²
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Q. A force of 10 N is applied to an object, causing it to accelerate at 2 m/s². What is the mass of the object? (2020)
A.
5 kg
B.
10 kg
C.
15 kg
D.
20 kg
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Solution
Using F = ma, mass m = F/a = 10 N / 2 m/s² = 5 kg.
Correct Answer: A — 5 kg
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Q. A force of 10 N is applied to move a box 5 m across a floor. What is the work done on the box?
A.
10 J
B.
20 J
C.
50 J
D.
5 J
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Solution
Work done = Force × Distance = 10 N × 5 m = 50 J
Correct Answer: B — 20 J
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Q. A force of 10 N is applied to move a box 5 m across a floor. What is the work done by the force?
A.
10 J
B.
20 J
C.
50 J
D.
5 J
Show solution
Solution
Work done = Force × Distance = 10 N × 5 m = 50 J
Correct Answer: B — 20 J
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Q. A force of 10 N is applied to move a box 5 m along a horizontal surface. What is the work done by the force? (2021)
A.
20 J
B.
50 J
C.
10 J
D.
5 J
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Solution
Work done = Force × Distance = 10 N × 5 m = 50 J
Correct Answer: B — 50 J
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Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done? (2021)
A.
10 J
B.
20 J
C.
50 J
D.
5 J
Show solution
Solution
Work done = Force × Distance = 10 N × 5 m = 50 J
Correct Answer: B — 20 J
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Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done by the force?
A.
10 J
B.
20 J
C.
50 J
D.
5 J
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Solution
Work done (W) = Force (F) × Distance (d) × cos(θ). Here, θ = 0° (force and displacement are in the same direction). W = 10 N × 5 m × cos(0°) = 10 N × 5 m = 50 J.
Correct Answer: B — 20 J
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Q. A force of 10 N is applied to move an object 5 m. What is the work done? (2023)
A.
50 J
B.
10 J
C.
5 J
D.
20 J
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Solution
Work done = Force × Distance = 10 N × 5 m = 50 J.
Correct Answer: A — 50 J
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Q. A force of 100 N is applied to a 50 kg object. What is the acceleration of the object? (2022)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Acceleration = Force / Mass = 100 N / 50 kg = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A force of 100 N is applied to a 50 kg object. What is the resulting acceleration? (2023)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, a = F/m = 100 N / 50 kg = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A force of 15 N is applied at an angle of 30° to the horizontal while moving an object 4 m. What is the work done by the force?
A.
30 J
B.
60 J
C.
90 J
D.
120 J
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Solution
Work done = F × d × cos(θ) = 15 N × 4 m × cos(30°) = 15 N × 4 m × (√3/2) = 60 J.
Correct Answer: C — 90 J
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Q. A force of 15 N is applied at an angle of 30° to the horizontal. What is the horizontal component of the force? (2020)
A.
7.5 N
B.
12.99 N
C.
15 N
D.
10 N
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Solution
Horizontal component = F × cos(θ) = 15 N × cos(30°) = 15 N × √3/2 ≈ 12.99 N.
Correct Answer: B — 12.99 N
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Q. A force of 15 N is applied at an angle of 60 degrees to a lever arm of 1 m. What is the torque?
A.
7.5 Nm
B.
12.5 Nm
C.
15 Nm
D.
25 Nm
Show solution
Solution
Torque = Force × Distance × sin(θ) = 15 N × 1 m × sin(60°) = 15 N × 1 m × (√3/2) = 12.5 Nm.
Correct Answer: B — 12.5 Nm
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Q. A force of 15 N is applied at an angle of 60 degrees to the horizontal while moving an object 4 m. What is the work done?
A.
30 J
B.
60 J
C.
45 J
D.
75 J
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Solution
Work Done = F * d * cos(θ) = 15 N * 4 m * cos(60°) = 30 J
Correct Answer: C — 45 J
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Q. A force of 15 N is applied to a 3 kg mass. What is the resulting acceleration? (2023)
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
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Solution
Using F = ma, acceleration a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A force of 15 N is applied to a 3 kg object. What is the net force acting on the object if it is also experiencing a frictional force of 5 N?
A.
10 N
B.
15 N
C.
20 N
D.
5 N
Show solution
Solution
Net force = applied force - frictional force = 15 N - 5 N = 10 N.
Correct Answer: A — 10 N
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Q. A force of 15 N is applied to a 3 kg object. What is the object's acceleration?
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A force of 15 N is applied to a 3 kg object. What is the resulting acceleration?
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A force of 15 N is applied to a 5 kg object. What is the object's acceleration?
A.
3 m/s²
B.
2 m/s²
C.
1 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer: A — 3 m/s²
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Q. A force of 15 N is applied to move an object 3 m at an angle of 60 degrees to the horizontal. What is the work done by the force?
A.
15 J
B.
20 J
C.
30 J
D.
45 J
Show solution
Solution
Work done = F × d × cos(θ) = 15 N × 3 m × cos(60°) = 15 N × 3 m × 0.5 = 22.5 J.
Correct Answer: C — 30 J
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Q. A force of 15 N is applied to move an object 4 m in the direction of the force. What is the work done?
A.
30 J
B.
60 J
C.
75 J
D.
90 J
Show solution
Solution
Work done = Force × Distance = 15 N × 4 m = 60 J.
Correct Answer: D — 90 J
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Q. A force of 20 N is applied at an angle of 30 degrees to the lever arm of 1 m. What is the torque about the pivot?
A.
10 Nm
B.
17.32 Nm
C.
20 Nm
D.
5 Nm
Show solution
Solution
Torque = Force × Distance × sin(30°) = 20 N × 1 m × 0.5 = 10 Nm.
Correct Answer: B — 17.32 Nm
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Q. A force of 20 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?
A.
10 Nm
B.
20 Nm
C.
30 Nm
D.
40 Nm
Show solution
Solution
Torque = Force × Distance × sin(θ) = 20 N × 2 m × sin(60°) = 20 N × 2 m × (√3/2) = 20√3 Nm.
Correct Answer: B — 20 Nm
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Q. A force of 20 N is applied at an angle of 60 degrees to a lever arm of length 0.5 m. What is the torque about the pivot?
A.
5 Nm
B.
10 Nm
C.
8.66 Nm
D.
17.32 Nm
Show solution
Solution
Torque (τ) = F × r × sin(θ) = 20 N × 0.5 m × sin(60°) = 20 N × 0.5 m × (√3/2) = 8.66 Nm.
Correct Answer: C — 8.66 Nm
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Q. A force of 20 N is applied at an angle of 60 degrees to the lever arm of length 2 m. What is the torque about the pivot?
A.
10 Nm
B.
20 Nm
C.
17.32 Nm
D.
34.64 Nm
Show solution
Solution
Torque (τ) = F × r × sin(θ) = 20 N × 2 m × sin(60°) = 20 × 2 × (√3/2) = 20√3 Nm ≈ 34.64 Nm.
Correct Answer: C — 17.32 Nm
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Q. A force of 20 N is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?
A.
40 J
B.
80 J
C.
20 J
D.
60 J
Show solution
Solution
Work done (W) = F × d × cos(θ) = 20 N × 4 m × cos(60°) = 20 × 4 × 0.5 = 40 J.
Correct Answer: B — 80 J
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Q. A force of 25 N is applied at an angle of 30 degrees to the horizontal while moving an object 10 m. What is the work done?
A.
100 J
B.
125 J
C.
150 J
D.
175 J
Show solution
Solution
Work done = Force × Distance × cos(θ) = 25 N × 10 m × cos(30°) = 216.5 J.
Correct Answer: B — 125 J
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