Q. A dipole consists of two charges +q and -q separated by a distance d. What is the dipole moment?
A.
qd
B.
q/d
C.
q^2d
D.
q/d^2
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Solution
The dipole moment p = q * d.
Correct Answer: A — qd
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Q. A dipole consists of two charges +q and -q separated by a distance d. What is the expression for the dipole moment?
A.
qd
B.
q/d
C.
q^2d
D.
q/d^2
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Solution
The dipole moment p is defined as p = q * d.
Correct Answer: A — qd
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Q. A dipole consists of two equal and opposite charges separated by a distance 'd'. What is the dipole moment? (2023)
A.
qd
B.
q/d
C.
q^2d
D.
qd^2
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Solution
The dipole moment (p) is defined as p = qd, where q is the charge and d is the separation distance.
Correct Answer: A — qd
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Q. A dipole consists of two equal and opposite charges separated by a distance of 0.1m. What is the dipole moment if each charge is 1μC?
A.
1 × 10^-7 C m
B.
1 × 10^-6 C m
C.
1 × 10^-5 C m
D.
1 × 10^-4 C m
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Solution
Dipole moment p = q * d = (1 × 10^-6 C) * (0.1 m) = 1 × 10^-7 C m.
Correct Answer: B — 1 × 10^-6 C m
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Q. A dipole consists of two equal and opposite charges separated by a distance. What happens to the dipole moment if the distance is doubled?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Dipole moment p = q * d, if d is doubled, p also doubles.
Correct Answer: A — It doubles
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Q. A dipole is placed in a uniform electric field. What is the torque experienced by the dipole? (2023)
A.
pE
B.
pE sin(θ)
C.
pE cos(θ)
D.
Zero
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Solution
The torque (τ) experienced by a dipole in a uniform electric field is given by τ = pE sin(θ), where p is the dipole moment and θ is the angle between p and E.
Correct Answer: B — pE sin(θ)
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Q. A dipole moment is defined as the product of charge and the distance between the charges. What is the dipole moment of a dipole consisting of charges +2μC and -2μC separated by 0.1m?
A.
4 × 10^-7 C m
B.
2 × 10^-7 C m
C.
2 × 10^-6 C m
D.
4 × 10^-6 C m
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Solution
Dipole moment p = q * d = (2 × 10^-6 C) * (0.1 m) = 2 × 10^-7 C m.
Correct Answer: A — 4 × 10^-7 C m
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Q. A dipole moment p is placed in a uniform electric field E. What is the torque experienced by the dipole?
A.
pE
B.
pE sin θ
C.
pE cos θ
D.
0
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Solution
Torque τ = p × E = pE sin θ, where θ is the angle between p and E.
Correct Answer: B — pE sin θ
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Q. A disc of mass M and radius R is rotating about its axis with an angular velocity ω. What is the angular momentum of the disc?
A.
(1/2)MR^2ω
B.
MR^2ω
C.
MRω
D.
(1/4)MR^2ω
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Solution
Angular momentum L = Iω, where I = (1/2)MR^2 for a disc.
Correct Answer: A — (1/2)MR^2ω
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Q. A disc of radius R and mass M is rotating about its axis with an angular velocity ω. What is the moment of inertia of the disc? (2020)
A.
(1/2)MR²
B.
(1/3)MR²
C.
MR²
D.
(1/4)MR²
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Solution
The moment of inertia of a solid disc about its central axis is given by I = (1/2)MR².
Correct Answer: A — (1/2)MR²
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Q. A disc of radius R and mass M is rotating about its axis with an angular velocity ω. What is its rotational kinetic energy? (2020)
A.
(1/2)Iω²
B.
(1/2)Mω²
C.
Iω
D.
Mω²
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Solution
Rotational kinetic energy K.E. = (1/2)Iω². For a disc, I = (1/2)MR², thus K.E. = (1/4)MR²ω².
Correct Answer: A — (1/2)Iω²
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Q. A disc of radius R and mass M is rotating about its axis with an angular velocity ω. What is the kinetic energy of the disc?
A.
(1/2)Iω^2
B.
(1/2)Mω^2
C.
Iω
D.
Mω^2
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Solution
Kinetic energy K = (1/2)Iω^2, where I = (1/2)MR^2 for a disc.
Correct Answer: A — (1/2)Iω^2
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Q. A disc of radius R and mass M is rotating about its axis with an angular velocity ω. What is its kinetic energy?
A.
(1/2)Iω^2
B.
(1/2)Mω^2
C.
(1/2)M(R^2)ω^2
D.
(1/2)(MR^2)ω^2
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Solution
The moment of inertia I of a disc about its axis is (1/2)MR^2. Therefore, the kinetic energy K.E. = (1/2)Iω^2 = (1/2)(1/2)MR^2ω^2 = (1/4)MR^2ω^2.
Correct Answer: D — (1/2)(MR^2)ω^2
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Q. A disc of radius R and mass M is rotating about its axis with an angular velocity ω. What is its angular momentum? (2020)
A.
Iω
B.
MωR²
C.
0.5MR²ω
D.
MR²ω
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Solution
The moment of inertia I of a disc about its axis is (1/2)MR². Therefore, angular momentum L = Iω = (1/2)MR²ω.
Correct Answer: A — Iω
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Q. A disc rolls without slipping on a horizontal surface. If its radius is R and it rolls with a linear speed v, what is its angular speed?
A.
v/R
B.
2v/R
C.
v/2R
D.
v^2/R
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Solution
The relationship between linear speed and angular speed for rolling without slipping is ω = v/R.
Correct Answer: A — v/R
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Q. A discount of 10% is given on a product that costs $500. If the product is then sold for $450, what is the actual discount given?
A.
$50
B.
$45
C.
$40
D.
$55
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Solution
Actual Discount = Marked Price - Selling Price = 500 - 450 = $50.
Correct Answer: A — $50
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Q. A discount of 10% on a marked price results in a selling price of $90. What is the marked price? (2023)
A.
$100
B.
$110
C.
$120
D.
$130
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Solution
Let the marked price be x. Selling Price = Marked Price - Discount = x - 0.1x = 0.9x. Thus, 0.9x = 90, so x = 100.
Correct Answer: A — $100
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Q. A discount of 15% is given on a product that costs $120. What is the final price after the discount?
A.
$102
B.
$108
C.
$110
D.
$100
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Solution
Discount = 15% of $120 = $120 * 0.15 = $18. Final Price = $120 - $18 = $102.
Correct Answer: B — $108
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Q. A discount of 15% on a marked price results in a selling price of $255. What was the marked price?
A.
$300
B.
$280
C.
$270
D.
$250
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Solution
Let the marked price be x. After a 15% discount, the selling price is 0.85x. Setting this equal to $255 gives 0.85x = $255, so x = $255 / 0.85 = $300.
Correct Answer: A — $300
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Q. A discount of 25% on a product results in a selling price of $150. What was the original price? (2023)
A.
$175
B.
$200
C.
$225
D.
$250
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Solution
Let the original price be x. Then, Selling Price = x - (25% of x) = 150 => 0.75x = 150 => x = 200.
Correct Answer: B — $200
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Q. A disk and a ring of the same mass and radius are released from rest at the same height. Which one reaches the ground first?
A.
Disk
B.
Ring
C.
Both reach at the same time
D.
Depends on the surface
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Solution
The disk has a lower moment of inertia compared to the ring, thus it reaches the ground first.
Correct Answer: A — Disk
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Q. A disk and a ring of the same mass and radius are rolling down an incline. Which will reach the bottom first?
A.
Disk
B.
Ring
C.
Both will reach at the same time
D.
Depends on the angle of incline
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Solution
The disk has a smaller moment of inertia compared to the ring, hence it will reach the bottom first.
Correct Answer: A — Disk
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Q. A disk and a ring of the same mass and radius are rolling down an incline. Which one will have a greater translational speed at the bottom?
A.
Disk
B.
Ring
C.
Both have the same speed
D.
Cannot be determined
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Solution
The disk has a lower moment of inertia than the ring, allowing it to convert more potential energy into translational kinetic energy.
Correct Answer: A — Disk
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Q. A disk and a ring of the same mass and radius are rolling down the same incline. Which one has a greater acceleration? (2019)
A.
Disk
B.
Ring
C.
Both have the same acceleration
D.
It depends on the mass
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Solution
The disk has a smaller moment of inertia than the ring, resulting in greater acceleration down the incline.
Correct Answer: A — Disk
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Q. A disk and a ring of the same mass and radius are rolling without slipping down an incline. Which one will have a greater translational speed at the bottom?
A.
Disk
B.
Ring
C.
Both have the same speed
D.
Depends on the incline
Show solution
Solution
The disk has a lower moment of inertia than the ring, allowing it to convert more potential energy into translational kinetic energy.
Correct Answer: A — Disk
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Q. A disk and a ring of the same mass and radius are rolling without slipping. Which one will reach the bottom of an incline first?
A.
Disk
B.
Ring
C.
Both will reach at the same time
D.
Depends on the angle of incline
Show solution
Solution
The disk will reach the bottom first because it has a smaller moment of inertia compared to the ring.
Correct Answer: A — Disk
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Q. A disk is rotating with an angular velocity of 10 rad/s. If it experiences a constant angular acceleration of 2 rad/s², what will be its angular velocity after 5 seconds?
A.
20 rad/s
B.
10 rad/s
C.
30 rad/s
D.
15 rad/s
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Solution
Using the formula ω = ω₀ + αt, we have ω = 10 + 2*5 = 20 rad/s.
Correct Answer: A — 20 rad/s
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Q. A disk of radius R and mass M is rotating about its axis with an angular velocity ω. What is its angular momentum?
A.
(1/2)MR^2ω
B.
MR^2ω
C.
Mω
D.
(1/4)MR^2ω
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Solution
Angular momentum L = Iω, where I = (1/2)MR^2 for a disk.
Correct Answer: A — (1/2)MR^2ω
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Q. A disk of radius R and mass M is rotating about its axis with an angular velocity ω. What is its kinetic energy?
A.
(1/2)Mω^2R^2
B.
(1/2)Iω^2
C.
(1/2)Mω^2
D.
Mω^2R
Show solution
Solution
The moment of inertia I of a disk about its axis is (1/2)MR^2. Therefore, the kinetic energy K.E. = (1/2)Iω^2 = (1/2)(1/2)MR^2ω^2 = (1/4)MR^2ω^2.
Correct Answer: B — (1/2)Iω^2
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Q. A disk of radius R and mass M is rotating about its axis with an angular velocity ω. What is the angular momentum of the disk?
A.
(1/2)MR^2ω
B.
MR^2ω
C.
(1/4)MR^2ω
D.
(3/2)MR^2ω
Show solution
Solution
Angular momentum L = Iω = (1/2)MR^2ω, where I = (1/2)MR^2 for a disk.
Correct Answer: A — (1/2)MR^2ω
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