Q. For a system of particles, the moment of inertia is calculated as the sum of the products of mass and the square of the distance from the axis of rotation. This is known as:
A.
Parallel Axis Theorem
B.
Perpendicular Axis Theorem
C.
Rotational Dynamics
D.
Angular Momentum
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Solution
This is known as the Parallel Axis Theorem, which states that I = Σ(m_i * r_i^2).
Correct Answer: A — Parallel Axis Theorem
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Q. For a system of particles, the moment of inertia is calculated by summing which of the following?
A.
Masses only
B.
Distances only
C.
Mass times distance squared
D.
Mass times distance
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Solution
The moment of inertia is calculated by summing the products of mass and the square of the distance from the axis of rotation.
Correct Answer: C — Mass times distance squared
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Q. For a system of particles, the total moment of inertia is calculated by which of the following?
A.
Sum of individual moments
B.
Product of mass and distance
C.
Sum of mass times distance squared
D.
Average of individual moments
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Solution
The total moment of inertia for a system of particles is the sum of each particle's moment of inertia, I_total = Σ(m_i * r_i^2).
Correct Answer: C — Sum of mass times distance squared
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Q. For a system of particles, the total moment of inertia is calculated by which of the following methods?
A.
Adding individual moments of inertia
B.
Multiplying total mass by average distance
C.
Using the parallel axis theorem
D.
Using the perpendicular axis theorem
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Solution
The total moment of inertia for a system of particles is calculated by adding the individual moments of inertia.
Correct Answer: A — Adding individual moments of inertia
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Q. For a thin circular ring of mass M and radius R, what is the moment of inertia about an axis perpendicular to its plane through its center?
A.
MR^2
B.
1/2 MR^2
C.
2/3 MR^2
D.
1/3 MR^2
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Solution
The moment of inertia of a thin circular ring about an axis through its center and perpendicular to its plane is I = MR^2.
Correct Answer: A — MR^2
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Q. For a toroidal solenoid with N turns and radius R carrying current I, what is the magnetic field inside the toroid?
A.
μ₀NI/2πR
B.
μ₀NI/R
C.
μ₀NI/4πR
D.
μ₀NI/2R
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Solution
The magnetic field inside a toroid is given by B = μ₀NI/2πR.
Correct Answer: B — μ₀NI/R
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Q. For a uniformly charged sphere of radius R and total charge Q, what is the electric field at a distance r from the center where r > R?
A.
Q/(4πε₀r²)
B.
0
C.
Q/(4πε₀R²)
D.
Q/(4πε₀r)
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Solution
For r > R, the electric field behaves as if all the charge were concentrated at the center, given by E = Q/(4πε₀r²).
Correct Answer: A — Q/(4πε₀r²)
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Q. For a zero-order reaction, how does the concentration of reactants change over time? (2020)
A.
Linearly
B.
Exponentially
C.
Quadratically
D.
Logarithmically
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Solution
In a zero-order reaction, the concentration of reactants decreases linearly with time.
Correct Answer: A — Linearly
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Q. For a zero-order reaction, how does the rate change with concentration?
A.
Increases linearly
B.
Decreases linearly
C.
Remains constant
D.
Increases exponentially
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Solution
In a zero-order reaction, the rate is constant and does not depend on the concentration of reactants.
Correct Answer: C — Remains constant
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Q. For a zero-order reaction, how does the rate change with respect to concentration?
A.
Increases linearly
B.
Decreases linearly
C.
Remains constant
D.
Increases exponentially
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Solution
In a zero-order reaction, the rate is constant and does not depend on the concentration of the reactants.
Correct Answer: C — Remains constant
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Q. For a zero-order reaction, if the initial concentration is 0.5 M and the rate constant is 0.1 M/s, how long will it take to reach 0.2 M? (2021)
A.
3 s
B.
5 s
C.
2 s
D.
4 s
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Solution
For a zero-order reaction, t = [A₀ - A] / k. Here, t = (0.5 - 0.2) / 0.1 = 3 s.
Correct Answer: D — 4 s
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Q. For a zero-order reaction, if the initial concentration is 0.5 M and the rate constant is 0.1 M/s, how long will it take to reach 0 M? (2019)
A.
5 s
B.
10 s
C.
15 s
D.
20 s
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Solution
For a zero-order reaction, t = [A₀] / k. Here, t = 0.5 M / 0.1 M/s = 5 s.
Correct Answer: B — 10 s
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Q. For an electron in a 3d orbital, what are the possible values of l?
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Solution
For d orbitals, the azimuthal quantum number l = 2.
Correct Answer: C — 2
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Q. For an electron in a 3d orbital, what are the possible values of m_l?
A.
-2, -1, 0, 1, 2
B.
-1, 0, 1
C.
0, 1
D.
0, 1, 2
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Solution
For l=2 (d orbital), m_l can take values from -l to +l, which are -2, -1, 0, 1, 2.
Correct Answer: A — -2, -1, 0, 1, 2
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Q. For an electron in a 3p orbital, what are the possible values of m_l?
A.
-1, 0, +1
B.
0, +1, +2
C.
-2, -1, 0
D.
0, -1, -2
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Solution
For a p orbital, l=1, so m_l can take values -1, 0, +1.
Correct Answer: A — -1, 0, +1
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Q. For an electron in a 3p orbital, what are the possible values of m_s?
A.
-1/2, +1/2
B.
0, +1
C.
1, 2
D.
-1, 0, +1
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Solution
The spin quantum number (m_s) can take values of -1/2 and +1/2.
Correct Answer: A — -1/2, +1/2
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Q. For an electron in a 3p orbital, what are the possible values of the magnetic quantum number (m_l)?
A.
-1, 0, +1
B.
0, +1, +2
C.
-2, -1, 0
D.
1, 2, 3
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Solution
For a p orbital (l=1), m_l can take values -1, 0, +1.
Correct Answer: A — -1, 0, +1
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Q. For an electron in a 5d orbital, what are the possible values of m_l?
A.
-2, -1, 0, 1, 2
B.
-3, -2, -1, 0, 1, 2, 3
C.
0, 1, 2
D.
-1, 0, 1
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Solution
For l=2 (d orbital), m_l can take values from -2 to +2, which are -2, -1, 0, 1, 2.
Correct Answer: A — -2, -1, 0, 1, 2
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Q. For an ideal gas, if the temperature is increased, what happens to the RMS speed?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Depends on the gas
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Solution
The RMS speed increases with temperature as v_rms = sqrt(3RT/M) shows that it is directly proportional to the square root of temperature T.
Correct Answer: A — Increases
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Q. For an ideal gas, if the volume is halved while keeping the temperature constant, what happens to the pressure?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
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Solution
According to Boyle's law, for a given mass of gas at constant temperature, the pressure is inversely proportional to the volume. Halving the volume will double the pressure.
Correct Answer: B — It doubles
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Q. For an ideal gas, the equation of state is given by:
A.
PV = nRT
B.
PV = NkT
C.
PV = mRT
D.
PV = kT
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Solution
The equation of state for an ideal gas is given by PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
Correct Answer: A — PV = nRT
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Q. For an ideal gas, the work done during an isobaric process is given by which formula? (2022)
A.
W = PΔV
B.
W = nRT
C.
W = ΔU + Q
D.
W = 0
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Solution
In an isobaric process, the work done is calculated using the formula W = PΔV, where P is pressure and ΔV is the change in volume.
Correct Answer: A — W = PΔV
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Q. For an ideal gas, which equation relates pressure, volume, and temperature?
A.
PV = nRT
B.
PV = nR
C.
PV = RT
D.
PV = nT
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Solution
The ideal gas law is given by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
Correct Answer: A — PV = nRT
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Q. For an ideal gas, which law relates pressure, volume, and temperature? (2023) 2023
A.
Boyle's Law
B.
Charles's Law
C.
Ideal Gas Law
D.
Avogadro's Law
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Solution
The Ideal Gas Law (PV = nRT) relates pressure (P), volume (V), and temperature (T) for an ideal gas.
Correct Answer: C — Ideal Gas Law
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Q. For an ideal gas, which of the following equations is correct?
A.
PV = nRT
B.
PV = nR/T
C.
PV = nT/R
D.
PV = nRT^2
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Solution
The ideal gas law is expressed as PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
Correct Answer: A — PV = nRT
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Q. For an ideal gas, which of the following is true at constant temperature?
A.
PV = nRT
B.
P1V1 = P2V2
C.
P/T = constant
D.
V/T = constant
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Solution
At constant temperature, Boyle's law states that the product of pressure and volume (PV) is constant, hence P1V1 = P2V2.
Correct Answer: B — P1V1 = P2V2
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Q. For an ideal solution, if the mole fraction of the solvent is 0.75, what is the vapor pressure of the solution if the vapor pressure of the pure solvent is 100 mmHg?
A.
75 mmHg
B.
100 mmHg
C.
25 mmHg
D.
50 mmHg
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Solution
According to Raoult's Law, the vapor pressure of the solution is 0.75 * 100 mmHg = 75 mmHg.
Correct Answer: A — 75 mmHg
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Q. For an infinite plane sheet of charge with surface charge density σ, what is the electric field at a point near the sheet?
A.
σ/2ε₀
B.
σ/ε₀
C.
0
D.
σ/4πε₀
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Solution
Using Gauss's law, the electric field due to an infinite plane sheet of charge is E = σ/2ε₀ on either side of the sheet.
Correct Answer: A — σ/2ε₀
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Q. For an infinite plane sheet of charge with surface charge density σ, what is the electric field at any point?
A.
σ/2ε₀
B.
σ/ε₀
C.
0
D.
σ/4πε₀
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Solution
The electric field due to an infinite plane sheet of charge is constant and given by E = σ/2ε₀ on either side of the sheet.
Correct Answer: A — σ/2ε₀
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Q. For destructive interference to occur in a thin film, the path difference must be equal to:
A.
nλ/2 (n is an integer)
B.
nλ (n is an integer)
C.
λ/4
D.
λ/2
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Solution
Destructive interference occurs when the path difference is an odd multiple of λ/2 (i.e., (2n+1)λ/2).
Correct Answer: A — nλ/2 (n is an integer)
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