Nitrogen deficiency leads to chlorosis, which is the yellowing of leaves due to insufficient chlorophyll production.

Nitrogen deficiency leads to chlorosis, which is the yellowing of leaves due to insufficient chlorophyll production.

The context suggests that the community is actively working to adapt to climate change, which aligns with collaborating on sustainable solutions.

The context suggests that the community's resilience is a positive trait, indicating a commitment to sustainability.

The sentence implies that the community's resilience is linked to collective action, making option 1 the most logical completion.

The word 'reflection' fits best in the context, as it indicates that their resilience is a manifestation of their values.

The context suggests that the community is actively working towards sustainability despite challenges, which aligns with 'resilient'.

The word 'meticulous' fits best as it indicates careful and precise planning, contrasting with the negative connotations of the other options.

f(x) is a polynomial function, which is differentiable everywhere, including at x = 1.

The left limit is 0 and the right limit is undefined. Thus, f(x) is not continuous at x = 0.

At x = 1, f(1) = 3, but lim x->1- f(x) = 1 and lim x->1+ f(x) = 2. Thus, it is not continuous.

Both sides equal 2 at x = 1, hence it is continuous.

The left-hand derivative is -1 and the right-hand derivative is 1. Since they are not equal, f(x) is not differentiable at x = 1.

The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan⁻¹(|(m1 - m2) / (1 + m1*m2)|) = tan⁻¹(5/3), which is approximately 90 degrees.

The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan^(-1) |(m1 - m2)/(1 + m1*m2)| = tan^(-1)(5/4) which is approximately 60 degrees.

The area is given by the integral from 0 to 1 of (x - x^3) dx. This evaluates to [x^2/2 - x^4/4] from 0 to 1 = (1/2 - 1/4) = 1/4.

The area enclosed is found by integrating from -2 to 2: ∫(from -2 to 2) (4 - x^2) dx = [4x - x^3/3] from -2 to 2 = (8 - 8/3) - (-8 + 8/3) = 16/3.

Area = 1/2 * base * height = 1/2 * 4 * 3 = 6.

The area under the curve y = 1/x from x = 1 to x = 2 is given by ∫(from 1 to 2) (1/x) dx = [ln(x)] from 1 to 2 = ln(2) - ln(1) = ln(2).

The area under the curve y = e^x from 0 to 1 is given by ∫(from 0 to 1) e^x dx = [e^x] from 0 to 1 = e - 1.

The coefficient of x^2 is C(4,2) * (3)^2 * (-4)^2 = 6 * 9 * 16 = 864.

The coefficient of x^2 is C(6,2) * (3)^2 * (-4)^4 = 15 * 9 * 256 = 34560.

The coefficient of x^2 is C(6,2)(-2)^4 = 15 * 16 = 240.

The coefficient of x^4 is given by 6C4 * (2)^4 * (-3)^2 = 15 * 16 * 9 = 2160.

The coefficient of x^5 in (3x - 4)^7 is C(7, 5) * (3)^5 * (-4)^2 = 21 * 243 * 16 = 68016.

The lines are perpendicular if 2h = a + b, which leads to h^2 = -ab.

The lines are parallel if the discriminant of the quadratic equation is zero, which leads to the condition h^2 = ab.

For the lines to be coincident, the discriminant must be zero, i.e., b^2 - 4ac = 0.

The lines are perpendicular if the condition a + b = 0 holds true.

The limit as x approaches 0 does not exist, hence f(x) is not continuous at x = 0.