Q. What is the gravitational force between two 1 kg masses placed 1 meter apart? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-11 N
B.
1.67 × 10^-10 N
C.
6.67 × 10^-10 N
D.
0 N
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Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer: A — 6.67 × 10^-11 N
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Q. What is the gravitational force between two objects of mass 5 kg and 10 kg separated by a distance of 2 m? (G = 6.67 × 10^-11 N m²/kg²)
A.
1.67 × 10^-10 N
B.
1.25 × 10^-10 N
C.
1.00 × 10^-10 N
D.
2.00 × 10^-10 N
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Solution
Using the formula F = G * (m1 * m2) / r², we have F = (6.67 × 10^-11) * (5 * 10) / (2²) = 1.67 × 10^-10 N.
Correct Answer: A — 1.67 × 10^-10 N
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Q. What is the gravitational force between two objects of mass m1 and m2 separated by a distance r? (2021)
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
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Solution
The gravitational force is given by Newton's law of gravitation: F = G * (m1 * m2) / r^2.
Correct Answer: A — G * (m1 * m2) / r^2
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Q. What is the gravitational potential energy of a 10 kg mass at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
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Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 10 m = 981 J.
Correct Answer: D — 1000 J
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Q. What is the gravitational potential energy of a 10 kg mass at a height of 5 m? (2019)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
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Solution
Gravitational potential energy (PE) = m * g * h = 10 kg * 9.81 m/s² * 5 m = 490.5 J.
Correct Answer: B — 100 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
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Solution
Gravitational potential energy (PE) is given by the formula PE = mgh. Here, PE = 10 kg * 9.8 m/s² * 10 m = 980 J, which rounds to approximately 1000 J.
Correct Answer: B — 200 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 5 m? (g = 9.8 m/s²)
A.
49 J
B.
98 J
C.
245 J
D.
490 J
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Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, m = 10 kg, g = 9.8 m/s², and h = 5 m. PE = 10 * 9.8 * 5 = 490 J.
Correct Answer: B — 98 J
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Q. What is the gravitational potential energy of a 2 kg object at a height of 10 m? (2023)
A.
20 J
B.
15 J
C.
10 J
D.
25 J
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Solution
Gravitational potential energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer: A — 20 J
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Q. What is the gravitational potential energy of a 5 kg object at a height of 10 m?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
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Solution
Gravitational potential energy (PE) = m * g * h = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer: B — 100 J
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Q. What is the heat required to raise the temperature of 2 kg of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C) (2022)
A.
9000 J
B.
18000 J
C.
36000 J
D.
4500 J
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Solution
Heat required Q = mcΔT = (2000 g)(0.9 J/g°C)(50°C) = 90000 J.
Correct Answer: B — 18000 J
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Q. What is the impedance of a circuit with a resistance of 4 ohms and a reactance of 3 ohms? (2021)
A.
5 ohms
B.
7 ohms
C.
1 ohm
D.
12 ohms
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Solution
Impedance Z = √(R² + X²) = √(4² + 3²) = √(16 + 9) = √25 = 5 ohms.
Correct Answer: A — 5 ohms
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Q. What is the impedance of a circuit with a resistance of 4Ω and a reactance of 3Ω? (2020)
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Solution
Impedance Z = √(R² + X²) = √(4² + 3²) = √(16 + 9) = √25 = 5Ω.
Correct Answer: A — 5Ω
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Q. What is the impedance of a circuit with a resistor of 10Ω and an inductor of 0.1 H at a frequency of 50 Hz? (2022)
A.
10Ω
B.
15.71Ω
C.
20Ω
D.
5Ω
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Solution
Impedance Z = √(R² + (XL)²), where XL = 2πfL = 31.42Ω. Thus, Z = √(10² + 31.42²) = 15.71Ω.
Correct Answer: B — 15.71Ω
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Q. What is the impedance of a circuit with a resistor of 10Ω and an inductor of 0.1H at a frequency of 50Hz? (2022)
A.
10Ω
B.
15.71Ω
C.
20Ω
D.
25Ω
Show solution
Solution
Impedance Z = √(R² + (XL)²), where XL = 2πfL = 31.42Ω. Thus, Z = √(10² + 31.42²) = 15.71Ω.
Correct Answer: B — 15.71Ω
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Q. What is the impedance of a circuit with a resistor of 4Ω and a capacitor of 2μF at a frequency of 50Hz? (2020)
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Solution
Impedance Z = √(R² + (1/(ωC))²) where ω = 2πf. Here, R = 4Ω, C = 2μF, f = 50Hz. Calculate Z.
Correct Answer: C — 6Ω
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Q. What is the impedance of a circuit with a resistor of 4Ω and an inductor of 3Ω at resonance? (2022)
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Solution
At resonance, the impedance is equal to the resistance, which is 4Ω.
Correct Answer: C — 4Ω
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Q. What is the impedance of a series circuit containing a resistor (R) and an inductor (L) at angular frequency ω? (2020)
A.
R
B.
√(R² + (ωL)²)
C.
R + jωL
D.
R + L
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Solution
The impedance Z in a series R-L circuit is given by Z = √(R² + (ωL)²).
Correct Answer: B — √(R² + (ωL)²)
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Q. What is the impedance of a series circuit containing a resistor (R) and an inductor (L) at a frequency (f)? (2020)
A.
R
B.
√(R² + (2πfL)²)
C.
R + 2πfL
D.
R - 2πfL
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Solution
The impedance Z in a series RL circuit is given by Z = √(R² + (2πfL)²).
Correct Answer: B — √(R² + (2πfL)²)
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Q. What is the kinetic energy of a 3 kg object moving at a speed of 4 m/s? (2022)
A.
24 J
B.
12 J
C.
6 J
D.
48 J
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Solution
Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 24 J.
Correct Answer: B — 12 J
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Q. What is the kinetic energy of a 4 kg object moving at a speed of 3 m/s? (2015)
A.
18 J
B.
12 J
C.
24 J
D.
36 J
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Solution
Kinetic Energy (KE) = 0.5 × mass × velocity² = 0.5 × 4 kg × (3 m/s)² = 18 J.
Correct Answer: B — 12 J
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Q. What is the latent heat of fusion if 2000 J of energy is required to melt 0.5 kg of ice? (2021)
A.
2000 J/kg
B.
4000 J/kg
C.
1000 J/kg
D.
500 J/kg
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Solution
Latent heat of fusion (L) = Q / m = 2000 J / 0.5 kg = 4000 J/kg.
Correct Answer: A — 2000 J/kg
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Q. What is the latent heat of fusion of ice if 80 calories are required to melt 20 grams of ice? (2020)
A.
40 cal/g
B.
60 cal/g
C.
80 cal/g
D.
100 cal/g
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Solution
Latent heat of fusion (L_f) = Q / m = 80 cal / 20 g = 4 cal/g.
Correct Answer: C — 80 cal/g
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Q. What is the latent heat of fusion of ice if 80 g of ice at 0°C melts to water at 0°C, absorbing 3360 J of heat? (2022)
A.
40 J/g
B.
60 J/g
C.
80 J/g
D.
100 J/g
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Solution
Latent heat of fusion (L) = Q/m = 3360 J / 80 g = 42 J/g.
Correct Answer: C — 80 J/g
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Q. What is the latent heat of vaporization if 500 g of water at 100°C is converted to steam at the same temperature, absorbing 2260 kJ of heat? (2023)
A.
2260 J/g
B.
450 J/g
C.
334 J/g
D.
1000 J/g
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Solution
Latent heat of vaporization (L) = Q / m = 2260 kJ / 500 g = 4.52 kJ/g = 2260 J/g.
Correct Answer: A — 2260 J/g
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Q. What is the latent heat of vaporization of water if 540 J of energy is required to convert 100 g of water at 100°C to steam? (2021)
A.
540 J/g
B.
54 J/g
C.
5.4 J/g
D.
0.54 J/g
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Solution
Latent heat of vaporization (L) = Q/m = 540 J / 100 g = 5.4 J/g.
Correct Answer: A — 540 J/g
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Q. What is the magnetic field at a distance r from a long straight wire carrying current I? (2020)
A.
μ₀I/(2πr)
B.
μ₀I/(4πr)
C.
μ₀I/(πr)
D.
μ₀I/(8πr)
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Solution
The magnetic field around a long straight wire is given by B = (μ₀I)/(2πr).
Correct Answer: A — μ₀I/(2πr)
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Q. What is the magnetic field at the center of a circular loop carrying current? (2022)
A.
Zero
B.
Directly proportional to current
C.
Inversely proportional to radius
D.
Both A and B
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Solution
The magnetic field at the center of a circular loop carrying current is directly proportional to the current and inversely proportional to the radius.
Correct Answer: B — Directly proportional to current
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Q. What is the magnetic field inside a long solenoid when it carries a current? (2023)
A.
Zero
B.
Uniform and directed along the axis
C.
Varies with distance
D.
Depends on the temperature
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Solution
The magnetic field inside a long solenoid is uniform and directed along the axis of the solenoid when it carries a current.
Correct Answer: B — Uniform and directed along the axis
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Q. What is the magnetic field inside a long solenoid when the current is flowing through it? (2023)
A.
Zero
B.
Uniform and parallel
C.
Concentric circles
D.
Radial
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Solution
The magnetic field inside a long solenoid is uniform and parallel to the axis of the solenoid.
Correct Answer: B — Uniform and parallel
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Q. What is the magnetic field inside a long solenoid when the current is steady? (2023)
A.
Zero
B.
Uniform and parallel to the axis
C.
Varies with distance
D.
Depends on the temperature
Show solution
Solution
The magnetic field inside a long solenoid is uniform and parallel to the axis of the solenoid when the current is steady.
Correct Answer: B — Uniform and parallel to the axis
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