Physics
Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. Assuming no heat loss to the surroundings, what is the final temperature of the system? (Specific heat of water = 4.18 kJ/kg°C, specific heat of metal = 0.9 kJ/kg°C) (2020)
A.
25°C
B.
30°C
C.
35°C
D.
40°C
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Solution
Using the principle of conservation of energy, set heat lost by metal equal to heat gained by water to find the final temperature.
Correct Answer: C — 35°C
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Q. A 10 kg block is pushed with a force of 50 N. What is its acceleration? (2023)
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
15 m/s²
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Solution
Using Newton's second law, F = ma, we have a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A 100 g piece of metal at 100°C is placed in 200 g of water at 20°C. What will be the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.5 J/g°C) (2023)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
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Solution
Using the heat transfer equation, we can find the final temperature to be 50°C.
Correct Answer: C — 50°C
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Q. A 100 W bulb is used for 5 hours. How much energy does it consume? (2016)
A.
500 Wh
B.
1000 Wh
C.
200 Wh
D.
250 Wh
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Solution
Energy consumed = Power × Time = 100 W × 5 h = 500 Wh.
Correct Answer: A — 500 Wh
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Q. A 1000 kg car is moving at a speed of 15 m/s. What is its kinetic energy?
A.
112,500 J
B.
75,000 J
C.
50,000 J
D.
25,000 J
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Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (15 m/s)² = 112,500 J.
Correct Answer: A — 112,500 J
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Q. A 12 kg object is pushed with a force of 36 N. What is its acceleration? (2023)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using F = ma, we find a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer: C — 3 m/s²
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Q. A 12V battery is connected to a resistor of 4Ω. What is the current flowing through the circuit? (2022)
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Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3A.
Correct Answer: A — 2A
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Q. A 15 kg object is dropped from a height. What is the force acting on it due to gravity? (2023)
A.
15 N
B.
30 N
C.
45 N
D.
150 N
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Solution
Using F = mg, where g = 9.8 m/s², we have F = 15 kg * 9.8 m/s² = 147 N, which rounds to 150 N.
Correct Answer: B — 30 N
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Q. A 15 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²) (2021)
A.
588 J
B.
5880 J
C.
392 J
D.
294 J
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Solution
Work = mgh = 15 kg * 9.8 m/s² * 4 m = 588 J.
Correct Answer: A — 588 J
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Q. A 2 kg block of metal at 100°C is placed in 1 kg of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.9 J/g°C) (2021)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
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Solution
Using the heat transfer equation, the final temperature can be calculated to be 50°C.
Correct Answer: C — 50°C
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Q. A 20 kg cart is pulled with a force of 80 N. What is the acceleration of the cart? (2023)
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
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Solution
Using F = ma, we find a = F/m = 80 N / 20 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. A 25 kg object is acted upon by a force of 100 N. What is its acceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we find a = F/m = 100 N / 25 kg = 4 m/s².
Correct Answer: D — 5 m/s²
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Q. A 5 kg object is dropped from a height of 10 m. What is its potential energy at the top? (g = 9.8 m/s²)
A.
490 J
B.
98 J
C.
50 J
D.
100 J
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Solution
Potential Energy = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer: A — 490 J
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Q. A 50 kg object is moving with a velocity of 5 m/s. What is its momentum? (2023)
A.
100 kg·m/s
B.
150 kg·m/s
C.
200 kg·m/s
D.
250 kg·m/s
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Solution
Momentum p = mv = 50 kg * 5 m/s = 250 kg·m/s.
Correct Answer: A — 100 kg·m/s
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Q. A 50 kg object is pulled with a force of 200 N. What is its acceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we find a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer: D — 5 m/s²
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Q. A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Take g = 10 m/s²) (2023)
A.
1 s
B.
2 s
C.
3 s
D.
4 s
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Solution
Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.
Correct Answer: B — 2 s
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Q. A ball is thrown upwards with a velocity of 20 m/s. How high will it go before coming to rest? (2023)
A.
10 m
B.
20 m
C.
30 m
D.
40 m
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Solution
Using the formula h = v²/(2g), where g = 10 m/s², h = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer: C — 30 m
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Q. A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)
A.
11.25 m
B.
15 m
C.
22.5 m
D.
30 m
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Solution
Using the formula: height = (initial velocity^2) / (2 * g), where g = 9.8 m/s². Height = (15^2) / (2 * 9.8) = 11.25 m.
Correct Answer: A — 11.25 m
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Q. A ball is thrown vertically upwards with a speed of 20 m/s. How high will it go? (g = 10 m/s²) (2023)
A.
10 m
B.
20 m
C.
30 m
D.
40 m
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Solution
Using the formula h = v²/(2g), we have h = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer: B — 20 m
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Q. A block of mass 2 kg is placed on a frictionless surface and is pushed with a force of 10 N. What is its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
20 m/s²
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Solution
Using Newton's second law, F = ma. Here, F = 10 N and m = 2 kg. Therefore, a = F/m = 10/2 = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A block of mass 2 kg is sliding down a frictionless incline of height 5 m. What is its speed at the bottom of the incline?
A.
10 m/s
B.
5 m/s
C.
20 m/s
D.
15 m/s
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Solution
Using conservation of energy, potential energy at the top = kinetic energy at the bottom. mgh = 0.5mv². Thus, v = sqrt(2gh) = sqrt(2 * 9.81 * 5) = 10 m/s.
Correct Answer: A — 10 m/s
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Q. A car accelerates from rest at a rate of 2 m/s². What is its speed after 5 seconds? (2023)
A.
5 m/s
B.
10 m/s
C.
15 m/s
D.
20 m/s
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Solution
Using the formula v = u + at, where u = 0, a = 2 m/s², and t = 5 s, we get v = 0 + 2 * 5 = 10 m/s.
Correct Answer: B — 10 m/s
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Q. A car moving at 30 m/s applies brakes and comes to a stop in 6 seconds. What is the distance covered during braking? (2023)
A.
90 m
B.
120 m
C.
150 m
D.
180 m
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Solution
Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.
Correct Answer: B — 120 m
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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the kinetic energy gained?
A.
200,000 J
B.
100,000 J
C.
50,000 J
D.
20,000 J
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Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (20 m/s)² = 200,000 J.
Correct Answer: B — 100,000 J
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Q. A charge of +4 µC is placed in a uniform electric field of strength 500 N/C. What is the work done in moving the charge 0.2 m in the direction of the field?
A.
400 J
B.
200 J
C.
100 J
D.
50 J
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Solution
W = F * d = (E * q) * d = (500 N/C * 4 × 10^-6 C) * 0.2 m = 0.4 J.
Correct Answer: B — 200 J
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Q. A charged particle moves in a magnetic field. What is the path of the particle? (2019)
A.
Straight line
B.
Circular
C.
Elliptical
D.
Parabolic
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Solution
A charged particle moving in a magnetic field experiences a force that is perpendicular to its velocity, resulting in circular motion.
Correct Answer: B — Circular
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Q. A circuit has a 9V battery and two resistors of 3Ω and 6Ω in series. What is the current flowing through the circuit? (2022)
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Solution
Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V / 9Ω = 1A.
Correct Answer: B — 2A
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Q. A circuit has a resistance of 10Ω and a reactance of 5Ω. What is the impedance? (2020)
A.
5Ω
B.
10Ω
C.
√125Ω
D.
√(10² + 5²)Ω
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Solution
The impedance Z = √(R² + X²) = √(10² + 5²) = √125Ω.
Correct Answer: D — √(10² + 5²)Ω
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Q. A current-carrying conductor experiences a force in a magnetic field. What is the direction of this force? (2020)
A.
Parallel to the field
B.
Opposite to the field
C.
Perpendicular to both current and field
D.
In the direction of current
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Solution
According to Fleming's left-hand rule, the force on a current-carrying conductor in a magnetic field is perpendicular to both the current and the magnetic field.
Correct Answer: C — Perpendicular to both current and field
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Q. A cyclist accelerates at 3 m/s² for 4 seconds. What is the final velocity if the initial velocity is 2 m/s? (2023)
A.
10 m/s
B.
11 m/s
C.
14 m/s
D.
20 m/s
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Solution
Using v = u + at, we have v = 2 m/s + (3 m/s² * 4 s) = 2 + 12 = 14 m/s.
Correct Answer: B — 11 m/s
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