Physics
Q. What is the formula for the total impedance in a parallel RLC circuit? (2023)
A.
1/Z = 1/Z1 + 1/Z2 + 1/Z3
B.
Z = R + jX
C.
Z = R
D.
.
X
.
Z = R + jωL - j/(ωC)
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Solution
The total impedance in a parallel circuit is given by 1/Z = 1/Z1 + 1/Z2 + 1/Z3.
Correct Answer: A — 1/Z = 1/Z1 + 1/Z2 + 1/Z3
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Q. What is the frequency of a pendulum that completes 30 oscillations in 60 seconds? (2017)
A.
0.5 Hz
B.
1 Hz
C.
2 Hz
D.
3 Hz
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Solution
Frequency f = number of oscillations / time = 30 / 60 = 0.5 Hz.
Correct Answer: B — 1 Hz
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Q. What is the frequency of a sound wave with a period of 0.01 seconds? (2014)
A.
100 Hz
B.
200 Hz
C.
50 Hz
D.
10 Hz
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Solution
Frequency = 1/Period = 1/0.01 s = 100 Hz.
Correct Answer: A — 100 Hz
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Q. What is the frequency of a tuning fork that vibrates 256 times in 2 seconds? (2019)
A.
128 Hz
B.
256 Hz
C.
512 Hz
D.
64 Hz
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Solution
Frequency (f) = Number of vibrations / Time = 256 / 2 = 128 Hz.
Correct Answer: A — 128 Hz
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Q. What is the frequency of a wave with a period of 0.01 s? (2020)
A.
100 Hz
B.
50 Hz
C.
200 Hz
D.
10 Hz
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Solution
Frequency f = 1/T = 1/0.01 s = 100 Hz.
Correct Answer: A — 100 Hz
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Q. What is the frequency of a wave with a period of 0.1 s? (2020)
A.
10 Hz
B.
5 Hz
C.
20 Hz
D.
15 Hz
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Solution
Frequency f = 1/T = 1/0.1 s = 10 Hz.
Correct Answer: A — 10 Hz
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Q. What is the frequency of a wave with a period of 0.2 seconds?
A.
5 Hz
B.
10 Hz
C.
20 Hz
D.
50 Hz
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Solution
Frequency (f) is the reciprocal of the period (T). Therefore, f = 1/T = 1/0.2 s = 5 Hz.
Correct Answer: B — 10 Hz
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Q. What is the frequency of a wave with a period of 0.5 seconds? (2019)
A.
2 Hz
B.
1 Hz
C.
0.5 Hz
D.
4 Hz
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Solution
Frequency (f) = 1/Period (T) = 1/0.5 s = 2 Hz.
Correct Answer: A — 2 Hz
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Q. What is the frequency of a wave with a speed of 300 m/s and a wavelength of 3 m? (2023)
A.
100 Hz
B.
150 Hz
C.
200 Hz
D.
250 Hz
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Solution
Frequency (f) = speed (v) / wavelength (λ) = 300 m/s / 3 m = 100 Hz.
Correct Answer: B — 150 Hz
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Q. What is the frequency of a wave with a wavelength of 2 m and a speed of 340 m/s?
A.
170 Hz
B.
340 Hz
C.
85 Hz
D.
420 Hz
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Solution
Frequency (f) is given by the formula f = speed / wavelength. Here, f = 340 m/s / 2 m = 170 Hz.
Correct Answer: A — 170 Hz
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Q. What is the gravitational field strength at a distance of 10 m from a mass of 100 kg? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-10 N/kg
B.
6.67 × 10^-9 N/kg
C.
6.67 × 10^-8 N/kg
D.
6.67 × 10^-7 N/kg
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Solution
g = G * M / r² = (6.67 × 10^-11) * (100) / (10²) = 6.67 × 10^-10 N/kg
Correct Answer: A — 6.67 × 10^-10 N/kg
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Q. What is the gravitational force acting on a 50 kg object on the surface of the Earth?
A.
490 N
B.
50 N
C.
5 N
D.
500 N
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Solution
Weight W = m * g = 50 kg * 9.8 m/s² = 490 N.
Correct Answer: A — 490 N
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Q. What is the gravitational force between two 1 kg masses placed 1 meter apart? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-11 N
B.
1.67 × 10^-10 N
C.
6.67 × 10^-10 N
D.
0 N
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Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer: A — 6.67 × 10^-11 N
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Q. What is the gravitational force between two objects of mass 5 kg and 10 kg separated by a distance of 2 m? (G = 6.67 × 10^-11 N m²/kg²)
A.
1.67 × 10^-10 N
B.
1.25 × 10^-10 N
C.
1.00 × 10^-10 N
D.
2.00 × 10^-10 N
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Solution
Using the formula F = G * (m1 * m2) / r², we have F = (6.67 × 10^-11) * (5 * 10) / (2²) = 1.67 × 10^-10 N.
Correct Answer: A — 1.67 × 10^-10 N
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Q. What is the gravitational force between two objects of mass m1 and m2 separated by a distance r? (2021)
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
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Solution
The gravitational force is given by Newton's law of gravitation: F = G * (m1 * m2) / r^2.
Correct Answer: A — G * (m1 * m2) / r^2
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Q. What is the gravitational potential energy of a 10 kg mass at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
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Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 10 m = 981 J.
Correct Answer: D — 1000 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
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Solution
Gravitational potential energy (PE) is given by the formula PE = mgh. Here, PE = 10 kg * 9.8 m/s² * 10 m = 980 J, which rounds to approximately 1000 J.
Correct Answer: B — 200 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 5 m? (g = 9.8 m/s²)
A.
49 J
B.
98 J
C.
245 J
D.
490 J
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Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, m = 10 kg, g = 9.8 m/s², and h = 5 m. PE = 10 * 9.8 * 5 = 490 J.
Correct Answer: B — 98 J
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Q. What is the gravitational potential energy of a 2 kg object at a height of 10 m? (2023)
A.
20 J
B.
15 J
C.
10 J
D.
25 J
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Solution
Gravitational potential energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer: A — 20 J
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Q. What is the gravitational potential energy of a 5 kg object at a height of 10 m?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
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Solution
Gravitational potential energy (PE) = m * g * h = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer: B — 100 J
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Q. What is the heat required to raise the temperature of 2 kg of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C) (2022)
A.
9000 J
B.
18000 J
C.
36000 J
D.
4500 J
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Solution
Heat required Q = mcΔT = (2000 g)(0.9 J/g°C)(50°C) = 90000 J.
Correct Answer: B — 18000 J
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Q. What is the impedance of a circuit with a resistance of 4 ohms and a reactance of 3 ohms? (2021)
A.
5 ohms
B.
7 ohms
C.
1 ohm
D.
12 ohms
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Solution
Impedance Z = √(R² + X²) = √(4² + 3²) = √(16 + 9) = √25 = 5 ohms.
Correct Answer: A — 5 ohms
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Q. What is the impedance of a circuit with a resistor of 10Ω and an inductor of 0.1 H at a frequency of 50 Hz? (2022)
A.
10Ω
B.
15.71Ω
C.
20Ω
D.
5Ω
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Solution
Impedance Z = √(R² + (XL)²), where XL = 2πfL = 31.42Ω. Thus, Z = √(10² + 31.42²) = 15.71Ω.
Correct Answer: B — 15.71Ω
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Q. What is the impedance of a circuit with a resistor of 4Ω and a capacitor of 2μF at a frequency of 50Hz? (2020)
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Solution
Impedance Z = √(R² + (1/(ωC))²) where ω = 2πf. Here, R = 4Ω, C = 2μF, f = 50Hz. Calculate Z.
Correct Answer: C — 6Ω
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Q. What is the impedance of a circuit with a resistor of 4Ω and an inductor of 3Ω at resonance? (2022)
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Solution
At resonance, the impedance is equal to the resistance, which is 4Ω.
Correct Answer: C — 4Ω
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Q. What is the impedance of a series circuit containing a resistor (R) and an inductor (L) at angular frequency ω? (2020)
A.
R
B.
√(R² + (ωL)²)
C.
R + jωL
D.
R + L
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Solution
The impedance Z in a series R-L circuit is given by Z = √(R² + (ωL)²).
Correct Answer: B — √(R² + (ωL)²)
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Q. What is the impedance of a series circuit containing a resistor (R) and an inductor (L) at a frequency (f)? (2020)
A.
R
B.
√(R² + (2πfL)²)
C.
R + 2πfL
D.
R - 2πfL
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Solution
The impedance Z in a series RL circuit is given by Z = √(R² + (2πfL)²).
Correct Answer: B — √(R² + (2πfL)²)
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Q. What is the kinetic energy of a 3 kg object moving at a speed of 4 m/s? (2022)
A.
24 J
B.
12 J
C.
6 J
D.
48 J
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Solution
Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 24 J.
Correct Answer: B — 12 J
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Q. What is the kinetic energy of a 4 kg object moving at a speed of 3 m/s? (2015)
A.
18 J
B.
12 J
C.
24 J
D.
36 J
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Solution
Kinetic Energy (KE) = 0.5 × mass × velocity² = 0.5 × 4 kg × (3 m/s)² = 18 J.
Correct Answer: B — 12 J
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Q. What is the latent heat of fusion of ice if 80 calories are required to melt 20 grams of ice? (2020)
A.
40 cal/g
B.
60 cal/g
C.
80 cal/g
D.
100 cal/g
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Solution
Latent heat of fusion (L_f) = Q / m = 80 cal / 20 g = 4 cal/g.
Correct Answer: C — 80 cal/g
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