The magnetic field around a long straight conductor decreases with distance. Specifically, it is inversely proportional to the distance from the conductor.

C = Q/V = 10 × 10^-6 C / 5 V = 2 × 10^-6 F = 2 µF.

Capacitive reactance Xc = 1 / (2πfC) = 1 / (2π * 60 * 10e-6) = 265.26Ω.

Xc = 1 / (2πfC) = 1 / (2π × 50 × 10 × 10^-6) = 318.31 ohms.

Using the first law of thermodynamics, ΔU = Q - W = 200 J - 50 J = 150 J.

Using the first law of thermodynamics: ΔU = Q - W = 300 J - 100 J = 200 J.

Using Ohm's law, I = V/R = 20V / 10Ω = 2A.

Using Ohm's law, I = V/R = 24V / 12Ω = 2A.

Using Ohm's law, I = V/R = 48V / 12Ω = 4A.

Using Ohm's law, I = V/R = 45V / 15Ω = 3A.

The direction of the magnetic field around a straight conductor carrying current is counterclockwise when viewed from the positive end of the conductor.

Inserting a dielectric material increases the capacitance of a capacitor by reducing the electric field within it.

Increasing capacitance increases the current in a capacitive AC circuit, as current I = V/Xc.

Increasing the current in a coil increases the magnetic field produced by the coil.

Increasing the current in a solenoid increases its magnetic field strength, as the magnetic field is directly proportional to the current.

Capacitive reactance Xc = 1/(2πfC), so increasing frequency decreases Xc.

The impedance of a capacitor decreases with increasing frequency.

The total impedance can increase or decrease depending on the relationship between R, XL, and XC as frequency changes.

Fringe separation is directly proportional to the distance from the slits to the screen. Increasing this distance increases the fringe separation.

Removing a resistor from a series circuit decreases the total resistance since the sum of the remaining resistances is less.

Efficiency = 1 - (T_c/T_h) = 1 - (300/600) = 0.5.

Efficiency = 1 - (T2/T1) = 1 - (300/500) = 0.4 or 40%.

Efficiency (η) = 1 - (T_c/T_h) = 1 - (300/600) = 0.5 or 50%.

Efficiency (η) = 1 - (T2/T1) = 1 - (300/500) = 0.4 or 40%.

The electric field (E) due to a point charge (q) at a distance (r) is given by E = k * q / r^2, where k is Coulomb's constant.

E = k * |q| / r^2 = (9 × 10^9) * (3 × 10^-6) / (0.3)^2 = 90 N/C.

V = k * q / r = (9 × 10^9) * (5 × 10^-6) / 0.4 = 112.5 V.

The electric potential (V) at a distance r from a point charge Q is given by V = kQ/r.

Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/4 = 1/2, thus R_eq = 2Ω.

Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/12 = 1/3, so R_eq = 3Ω.