Q. A train is moving at 72 km/h and passes a platform in 20 seconds. What is the length of the platform if the train is 180 meters long?
A.
200 m
B.
300 m
C.
400 m
D.
500 m
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Solution
Speed of train = 72 km/h = 20 m/s. Time = 20 s. Distance = Speed × Time = 20 m/s × 20 s = 400 m. Length of platform = 400 m - 180 m = 220 m.
Correct Answer: B — 300 m
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Q. A train is moving at 72 km/h and passes a platform in 30 seconds. What is the length of the platform if the train is 200 meters long?
A.
200 m
B.
300 m
C.
400 m
D.
500 m
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Solution
Speed in m/s = 72 * (1000/3600) = 20 m/s. Distance = Speed × Time = 20 m/s × 30 s = 600 m. Length of platform = 600 m - 200 m = 400 m.
Correct Answer: B — 300 m
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Q. A train is moving at 90 km/h and a bird flies at 45 km/h in the opposite direction. What is the speed of the bird relative to the train?
A.
135 km/h
B.
45 km/h
C.
90 km/h
D.
135 km/h
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Solution
Relative speed = Speed of train + Speed of bird = 90 km/h + 45 km/h = 135 km/h.
Correct Answer: A — 135 km/h
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Q. A train leaves a station and travels at 90 km/h. Another train leaves the same station 30 minutes later and travels at 120 km/h. How far from the station will they meet?
A.
90 km
B.
120 km
C.
150 km
D.
180 km
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Solution
Let the distance be d. Time taken by first train = d/90. Time taken by second train = d/120. Setting up the equation gives d = 150 km.
Correct Answer: C — 150 km
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Q. A train leaves a station at 70 km/h. Another train leaves the same station 30 minutes later at 90 km/h. How far from the station will they meet?
A.
70 km
B.
90 km
C.
100 km
D.
110 km
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Solution
Let the distance be d. Time taken by first train = d/70, second train = d/90. They meet when d/70 = d/90 + 0.5. Solving gives d = 100 km.
Correct Answer: C — 100 km
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Q. A train leaves a station at 80 km/h and another train leaves the same station 30 minutes later at 100 km/h. How far from the station will they meet?
A.
100 km
B.
120 km
C.
150 km
D.
180 km
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Solution
Let the time taken by the first train be t hours. Distance = speed * time. 80t = 100(t - 0.5). Solving gives t = 2 hours, so distance = 80 * 2 = 160 km.
Correct Answer: B — 120 km
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Q. A train moving at 72 km/h overtakes a man walking at 6 km/h in the same direction. How fast does the train appear to be moving to the man?
A.
66 km/h
B.
72 km/h
C.
78 km/h
D.
84 km/h
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Solution
Relative speed = Speed of train - Speed of man = 72 km/h - 6 km/h = 66 km/h.
Correct Answer: A — 66 km/h
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Q. A train moving at 72 km/h passes a man walking at 6 km/h in the same direction. How fast does the train appear to be moving to the man?
A.
66 km/h
B.
72 km/h
C.
78 km/h
D.
84 km/h
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Solution
Relative speed = Speed of train - Speed of man = 72 km/h - 6 km/h = 66 km/h.
Correct Answer: A — 66 km/h
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Q. A train moving at 72 km/h passes a platform 300 m long. How long does it take to cross the platform completely?
A.
10 seconds
B.
15 seconds
C.
20 seconds
D.
25 seconds
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Solution
Total distance = Length of train + Length of platform. If length of train is L, time = (L + 300)/20 m/s. Assuming L = 300 m, time = (300 + 300)/20 = 30 seconds.
Correct Answer: B — 15 seconds
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Q. A train moving at a speed of 72 km/h applies brakes and comes to a stop in 5 seconds. What is the acceleration of the train?
A.
-4 m/s²
B.
-2 m/s²
C.
-3 m/s²
D.
-1 m/s²
Show solution
Solution
First, convert speed to m/s: 72 km/h = 20 m/s. Using a = (v - u)/t = (0 - 20)/5 = -4 m/s².
Correct Answer: A — -4 m/s²
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Q. A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 seconds. What is the magnitude of its acceleration?
A.
-3 m/s²
B.
-2 m/s²
C.
-1 m/s²
D.
-4 m/s²
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Solution
First, convert speed to m/s: 60 km/h = 60/3.6 = 16.67 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 16.67) / 5 = -3.33 m/s², approximately -3 m/s².
Correct Answer: A — -3 m/s²
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Q. A train moving with a speed of 72 km/h applies brakes and comes to a stop in 10 seconds. What is the acceleration of the train?
A.
-2 m/s²
B.
-3 m/s²
C.
-4 m/s²
D.
-5 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 10 = -2 m/s².
Correct Answer: B — -3 m/s²
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Q. A train moving with a speed of 72 km/h applies brakes and comes to a stop in 10 seconds. What is the magnitude of its acceleration?
A.
-2 m/s²
B.
-3 m/s²
C.
-4 m/s²
D.
-5 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 10 = -2 m/s².
Correct Answer: C — -4 m/s²
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Q. A train of mass 1000 kg is moving with a velocity of 36 km/h. What is its kinetic energy?
A.
500 J
B.
1000 J
C.
1800 J
D.
2000 J
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Solution
First convert velocity to m/s: 36 km/h = 10 m/s. K.E. = (1/2)mv² = (1/2)(1000 kg)(10 m/s)² = 50000 J.
Correct Answer: C — 1800 J
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Q. A train travels 120 km at a uniform speed. If it takes 2 hours to complete the journey, what is the speed of the train?
A.
50 km/h
B.
60 km/h
C.
70 km/h
D.
80 km/h
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Solution
Speed = distance / time = 120 km / 2 h = 60 km/h.
Correct Answer: B — 60 km/h
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Q. A train travels at a speed of 72 km/h. How far will it travel in 30 minutes?
A.
12 km
B.
18 km
C.
24 km
D.
36 km
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Solution
Distance = speed × time = 72 km/h × 0.5 h = 36 km.
Correct Answer: B — 18 km
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Q. A train travels at a speed of 72 km/h. How long will it take to cover a distance of 180 km?
A.
2 hours
B.
2.5 hours
C.
3 hours
D.
3.5 hours
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Solution
Time = distance / speed. Convert speed to m/s: 72 km/h = 20 m/s. Time = 180 km / 72 km/h = 2.5 hours.
Correct Answer: C — 3 hours
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Q. A train travels at a speed of 90 km/h and a car at 60 km/h. If they start from the same point and travel in the same direction, how far apart will they be after 1 hour?
A.
30 km
B.
20 km
C.
10 km
D.
40 km
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Solution
Relative speed = 90 - 60 = 30 km/h. Distance apart after 1 hour = 30 km.
Correct Answer: A — 30 km
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Q. A transformer operates on the principle of electromagnetic induction. If the primary coil has 100 turns and the secondary coil has 50 turns, what is the relationship between the primary and secondary voltages?
A.
V_primary = 2 * V_secondary
B.
V_primary = 0.5 * V_secondary
C.
V_primary = V_secondary
D.
V_primary = 4 * V_secondary
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Solution
The voltage ratio in a transformer is given by the turns ratio. Therefore, V_primary/V_secondary = N_primary/N_secondary = 100/50 = 2, which means V_primary = 2 * V_secondary.
Correct Answer: A — V_primary = 2 * V_secondary
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Q. A transformer operates on the principle of electromagnetic induction. What is the primary function of a transformer?
A.
To increase voltage
B.
To decrease voltage
C.
To convert AC to DC
D.
To store energy
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Solution
A transformer is designed to increase or decrease the voltage in an AC circuit through electromagnetic induction, depending on the turns ratio of the primary and secondary coils.
Correct Answer: A — To increase voltage
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Q. A transformer operates on the principle of electromagnetic induction. What is the main purpose of a transformer?
A.
To increase or decrease voltage
B.
To store electrical energy
C.
To convert AC to DC
D.
To measure current
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Solution
A transformer is used to increase or decrease the voltage in an AC circuit based on the turns ratio of its coils.
Correct Answer: A — To increase or decrease voltage
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Q. A transformer works on the principle of:
A.
Electromagnetic induction
B.
Electrostatics
C.
Magnetic resonance
D.
Thermal conduction
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Solution
A transformer operates on the principle of electromagnetic induction, transferring energy between coils through a changing magnetic field.
Correct Answer: A — Electromagnetic induction
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Q. A tree casts a shadow of 20 m when the angle of elevation of the sun is 30 degrees. What is the height of the tree?
A.
10 m
B.
15 m
C.
20 m
D.
25 m
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Solution
Using tan(30°) = height/20, we have 1/√3 = height/20. Therefore, height = 20/√3 ≈ 11.55 m.
Correct Answer: A — 10 m
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Q. A tree casts a shadow of 20 m when the angle of elevation of the sun is 45 degrees. What is the height of the tree?
A.
10 m
B.
20 m
C.
30 m
D.
40 m
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Solution
Using tan(45°) = height/shadow, we have 1 = height/20. Therefore, height = 20 m.
Correct Answer: B — 20 m
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Q. A tree casts a shadow of 20 meters when the angle of elevation of the sun is 30 degrees. What is the height of the tree?
A.
20√3 meters
B.
10√3 meters
C.
30 meters
D.
40 meters
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Solution
Height = shadow * tan(angle) = 20 * tan(30°) = 20 * (1/√3) = 20√3 meters.
Correct Answer: A — 20√3 meters
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Q. A tree is 15 meters tall. From a point on the ground, the angle of elevation to the top of the tree is 30 degrees. How far is the point from the base of the tree?
A.
15√3 meters
B.
30 meters
C.
45 meters
D.
10 meters
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Solution
Distance = height / tan(angle) = 15 / tan(30°) = 15√3 meters.
Correct Answer: A — 15√3 meters
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Q. A tuning fork produces a sound wave of frequency 440 Hz. If the speed of sound in air is 340 m/s, what is the wavelength of the sound wave?
A.
0.77 m
B.
0.85 m
C.
0.90 m
D.
1.00 m
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Solution
Using the formula λ = v/f, we find λ = 340 m/s / 440 Hz = 0.7727 m, approximately 0.77 m.
Correct Answer: A — 0.77 m
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the period of this wave?
A.
0.00227 s
B.
0.0025 s
C.
0.0023 s
D.
0.0020 s
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Solution
The period T is the reciprocal of frequency f. T = 1/f = 1/440 Hz = 0.00227 s.
Correct Answer: A — 0.00227 s
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the period of this sound wave?
A.
0.00227 s
B.
0.00455 s
C.
0.005 s
D.
0.01 s
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Solution
The period T is the reciprocal of frequency f. T = 1/f = 1/440 Hz = 0.00227 s.
Correct Answer: B — 0.00455 s
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the wavelength of the sound wave in air at a temperature of 20°C?
A.
0.78 m
B.
0.34 m
C.
0.50 m
D.
0.25 m
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Solution
The speed of sound in air at 20°C is approximately 343 m/s. The wavelength λ is given by λ = v/f. Thus, λ = 343/440 ≈ 0.78 m.
Correct Answer: A — 0.78 m
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