A tuning fork produces a sound wave of frequency 440 Hz. What is the period of this sound wave?
Practice Questions
1 question
Q1
A tuning fork produces a sound wave of frequency 440 Hz. What is the period of this sound wave?
0.00227 s
0.00455 s
0.005 s
0.01 s
The period T is the reciprocal of frequency f. T = 1/f = 1/440 Hz = 0.00227 s.
Questions & Step-by-step Solutions
1 item
Q
Q: A tuning fork produces a sound wave of frequency 440 Hz. What is the period of this sound wave?
Solution: The period T is the reciprocal of frequency f. T = 1/f = 1/440 Hz = 0.00227 s.
Steps: 6
Step 1: Understand that frequency (f) is how many times something happens in one second. In this case, the tuning fork produces 440 sound waves every second.
Step 2: Know that the period (T) is the time it takes for one complete wave to pass a point. It is the opposite of frequency.
Step 3: Use the formula for period, which is T = 1/f. This means you take 1 and divide it by the frequency.
Step 4: Substitute the frequency into the formula. Here, f = 440 Hz, so T = 1/440.
Step 5: Calculate the value. 1 divided by 440 equals approximately 0.00227 seconds.
Step 6: Conclude that the period of the sound wave is 0.00227 seconds.
