NH3 has four electron pairs (three bonding pairs and one lone pair), giving it a tetrahedral electron pair geometry.

SF6 has six bonding pairs and no lone pairs, resulting in an octahedral electron pair geometry.

Chlorine ion (Cl-) has gained an electron, resulting in the configuration 1s2 2s2 2p6.

Oxygen has 8 electrons. The electronic configuration is 1s2 2s2 2p4.

Sodium has 11 electrons, and its configuration is 1s2 2s2 2p6 3s1.

Sodium ion (Na+) has lost one electron, resulting in the configuration 1s2 2s2 2p6.

Chlorine (Cl) has 17 electrons, so its configuration is 1s2 2s2 2p6 3s2 3p5.

Iron (Fe) has the configuration [Ar] 4s2 3d6.

Oxygen has 8 electrons, and its electronic configuration is 1s2 2s2 2p4.

The electronic configuration of potassium (K) is 1s² 2s² 2p⁶ 3s¹.

Chloride ion has gained one electron, making its configuration 1s2 2s2 2p6 3s2 3p6.

The electronic configuration of Rutherfordium (atomic number 104) is [Rn] 5f14 6d4.

The element with atomic number 12 is magnesium (Mg), and its electronic configuration is [Ne] 3s2.

The element with atomic number 15 is phosphorus (P), and its electronic configuration is [Ne] 3s2 3p3.

Chlorine (Cl) has the configuration 1s2 2s2 2p6 3s2 3p5.

The element with atomic number 20 is Calcium, which has the configuration [Ar] 4s2.

The element with atomic number 26 is iron (Fe), and its electronic configuration is [Ar] 4s2 3d6.

Copper (Cu) has the configuration [Ar] 4s2 3d9.

The electronic configuration of Zinc (atomic number 30) is [Ar] 4s2 3d10.

The electronic configuration of Lanthanum (atomic number 57) is [Xe] 6s2.

Iron (Fe) has 26 electrons, and its electronic configuration is [Ar] 4s2 3d6.

Nitrogen has 7 electrons, and its electronic configuration is 1s2 2s2 2p3.

The potassium ion (K+) loses one electron, resulting in the configuration 1s2 2s2 2p6.

Sodium ion (Na+) has lost one electron, resulting in the configuration 1s2 2s2 2p6.

Converting percentages to moles gives C: 40/12 = 3.33, H: 6.7/1 = 6.7, O: 53.3/16 = 3.33. The simplest ratio is 1:2:1, giving the empirical formula CH2O.

Convert percentages to grams (assume 100 g total): 40 g C, 6.7 g H, 53.3 g O. Convert to moles: C=3.33, H=6.67, O=3.33. The simplest ratio is 1:2:1, giving CH2O.

The empirical formula is the simplest whole number ratio, which is CH2O.

The empirical formula is the simplest whole number ratio of the elements in a compound. For glucose, it is CH2O.

The standard enthalpy of formation of CO2 is -393.5 kJ/mol.

The formation of water from hydrogen and oxygen is an exothermic reaction, resulting in a negative enthalpy change.