The force on a charge in a static electric field is not determined by potential alone; it depends on the electric field, which is not given.

Work done W = q * ΔV = 3 × 10^-6 C * (600 V - 300 V) = 3 × 10^-6 * 300 = 0.9 mJ.

Distance d = V/E = 50 V / 5 N/C = 10 m.

Change in potential energy ΔU = qΔV = 3 C × (15 V - 5 V) = 30 J.

An increase in electric potential at a point generally indicates a stronger electric field, as the electric field is related to the rate of change of potential.

If the electric potential increases, the work done by the external force must increase to move the positive charge against the electric field.

The work done (W) by the electric field is given by W = q(V_A - V_B). For a unit charge, W = 10 V - 5 V = 5 J.

Potential difference (V_AB) = V_A - V_B = 15 V - 5 V = 10 V.

Work done W = Q(V_B - V_A) = 2 C * (15 V - 5 V) = 20 J.

The potential difference V_AB = V_B - V_A = 15 V - 5 V = 10 V.

If the electric potential is constant, the electric field in that region is zero, as E = -dV/dx.

The potential gradient is given as 0.6 V/m, which is the calibration value for the potentiometer.

The balancing length is calculated as L = V / (potential gradient) = 2V / 4 V/m = 0.5 m.

Concave lenses always produce virtual and erect images regardless of the object distance.

The radius of curvature (R) is twice the focal length (f). Therefore, R = 2f = 2 * 10 cm = 20 cm.

The radius of curvature (R) is twice the focal length (f). Therefore, R = 2f = 2 * 20 cm = 40 cm.

A negative focal length indicates that the lens is a concave lens.

Power (P) = 1/f (in meters). Here, f = 0.2 m, so P = 1/0.2 = +5 D.

Power (P) is given by P = 1/f (in meters). Thus, P = 1/0.25 m = +4 D.

Power is inversely proportional to focal length. If f is doubled, P = 1/f will halve.

The time period T is inversely proportional to the frequency f. If the frequency is doubled, the time period halves.

Period T = 1/f, if frequency is halved, period doubles.

Wavelength is inversely proportional to frequency; if frequency is doubled, wavelength is halved.

Wavelength is inversely proportional to frequency; if frequency is doubled, wavelength halves.

According to the wave equation v = fλ, if frequency (f) is doubled and speed (v) remains constant, the wavelength (λ) must halve.

The speed of a wave is given by the product of its frequency and wavelength (v = fλ). If the frequency is doubled, the wavelength must be halved to keep the speed constant.

The time period (T) is the reciprocal of frequency (f). T = 1/f = 1/60 Hz = 0.0167 s.

Capacitive reactance X_C = 1/(ωC) decreases as frequency increases.

The kinetic energy of the emitted electrons is given by KE = hf - φ. If the frequency is doubled, the kinetic energy increases as it is directly proportional to frequency.

A high resistance in the galvanometer increases the sensitivity of the bridge.