If the electric potential at point A is 5 V and at point B is 15 V, what is the work done by the electric field in moving a charge of 2 C from A to B?
Practice Questions
1 question
Q1
If the electric potential at point A is 5 V and at point B is 15 V, what is the work done by the electric field in moving a charge of 2 C from A to B?
-20 J
20 J
10 J
30 J
Work done W = Q(V_B - V_A) = 2 C * (15 V - 5 V) = 20 J.
Questions & Step-by-step Solutions
1 item
Q
Q: If the electric potential at point A is 5 V and at point B is 15 V, what is the work done by the electric field in moving a charge of 2 C from A to B?
Solution: Work done W = Q(V_B - V_A) = 2 C * (15 V - 5 V) = 20 J.
Steps: 8
Step 1: Identify the electric potential at point A, which is 5 V.
Step 2: Identify the electric potential at point B, which is 15 V.
Step 3: Calculate the difference in electric potential between point B and point A by subtracting V_A from V_B: 15 V - 5 V.
Step 4: The result of the subtraction is 10 V (this is the change in electric potential).
Step 5: Identify the charge being moved, which is 2 C.
Step 6: Use the formula for work done by the electric field: W = Q * (V_B - V_A).
Step 7: Substitute the values into the formula: W = 2 C * 10 V.
Step 8: Calculate the work done: 2 C * 10 V = 20 J.
