Physics Syllabus (JEE Main)
Q. If the length of a side of a cube is measured as 2.5 cm with an uncertainty of 0.1 cm, what is the volume of the cube?
A.
15.625 cm³
B.
16.0 cm³
C.
16.5 cm³
D.
17.0 cm³
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Solution
Volume = side³ = (2.5 cm)³ = 15.625 cm³. Considering significant figures, it is reported as 16.0 cm³.
Correct Answer: B — 16.0 cm³
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Q. If the length of a wire is doubled while keeping the cross-sectional area constant, how does its resistance change?
A.
Remains the same
B.
Doubles
C.
Halves
D.
Quadruples
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Solution
Resistance is directly proportional to length; doubling the length doubles the resistance.
Correct Answer: B — Doubles
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Q. If the length of a wire is doubled while keeping the cross-sectional area constant, how does its Young's modulus change?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Young's modulus is a material property and does not change with the dimensions of the wire.
Correct Answer: C — It remains the same
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Q. If the length of an object is doubled, what happens to its area?
A.
It remains the same
B.
It doubles
C.
It triples
D.
It quadruples
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Solution
If the length is doubled, the area increases by a factor of four (A = length²).
Correct Answer: D — It quadruples
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Q. If the length of an object is doubled, what happens to its volume?
A.
It remains the same
B.
It doubles
C.
It triples
D.
It increases by a factor of eight
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Solution
If the length is doubled, the volume increases by a factor of 2^3 = 8, since volume is proportional to the cube of the length.
Correct Answer: D — It increases by a factor of eight
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Q. If the length of the potentiometer wire is increased while keeping the voltage constant, what will happen to the balance point when measuring a cell's EMF?
A.
It will move to a longer length.
B.
It will move to a shorter length.
C.
It will remain unchanged.
D.
It will become unstable.
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Solution
Increasing the length of the potentiometer wire while keeping the voltage constant will increase the balance point length for the same EMF.
Correct Answer: A — It will move to a longer length.
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Q. If the length of the potentiometer wire is increased, what effect does it have on the maximum measurable voltage?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
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Solution
Increasing the length of the potentiometer wire increases the maximum measurable voltage due to a larger potential gradient.
Correct Answer: A — It increases
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Q. If the lever arm is doubled while keeping the force constant, how does the torque change?
A.
It doubles
B.
It triples
C.
It remains the same
D.
It halves
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Solution
Torque is directly proportional to the lever arm; if the lever arm is doubled, the torque also doubles.
Correct Answer: A — It doubles
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Q. If the magnetic field around a closed loop is constant, what can be said about the current through the loop?
A.
It is zero
B.
It is variable
C.
It is constant
D.
It is infinite
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Solution
If the magnetic field around a closed loop is constant, the current through the loop must also be constant according to Ampere's Law.
Correct Answer: C — It is constant
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Q. If the magnetic field in a region is uniform, what is the shape of the magnetic field lines?
A.
Straight lines
B.
Curved lines
C.
Concentric circles
D.
Random
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Solution
In a uniform magnetic field, the magnetic field lines are straight and parallel.
Correct Answer: A — Straight lines
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Q. If the magnetic field strength is doubled, what happens to the force on a charged particle moving perpendicular to the field?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
The force on a charged particle is directly proportional to the magnetic field strength, so if the magnetic field strength is doubled, the force also doubles.
Correct Answer: A — It doubles
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Q. If the magnetic field strength is doubled, what happens to the induced EMF in a coil with a constant number of turns and area?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
According to Faraday's law, the induced EMF is directly proportional to the rate of change of magnetic flux, which depends on the magnetic field strength.
Correct Answer: A — It doubles
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Q. If the magnetic field strength is doubled, what happens to the magnetic force on a charged particle moving perpendicular to the field?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
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Solution
The magnetic force on a charged particle is given by F = qvB sin(θ). If the magnetic field strength B is doubled, the force F also doubles, assuming charge q and velocity v remain constant.
Correct Answer: A — Doubles
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Q. If the magnetic field through a loop is doubled while the area remains constant, what happens to the magnetic flux?
A.
Magnetic flux doubles
B.
Magnetic flux halves
C.
Magnetic flux remains the same
D.
Magnetic flux becomes zero
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Solution
Magnetic flux is given by the product of magnetic field strength and area. If the magnetic field is doubled, the magnetic flux also doubles.
Correct Answer: A — Magnetic flux doubles
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Q. If the magnetic field through a loop is increased uniformly, what happens to the induced current in the loop?
A.
It flows in the direction of the magnetic field
B.
It flows in the opposite direction to the magnetic field
C.
It remains constant
D.
It stops flowing
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Solution
According to Lenz's law, the induced current will flow in the opposite direction to oppose the increase in magnetic flux.
Correct Answer: B — It flows in the opposite direction to the magnetic field
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Q. If the magnetic field through a loop is increasing at a constant rate, what can be said about the induced current?
A.
It is constant
B.
It is increasing
C.
It is decreasing
D.
It is zero
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Solution
If the magnetic field is increasing at a constant rate, the induced EMF is also increasing, which means the induced current is increasing.
Correct Answer: B — It is increasing
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Q. If the mass of a satellite is doubled while keeping its orbital radius constant, what happens to the gravitational force acting on it?
A.
It doubles.
B.
It remains the same.
C.
It halves.
D.
It quadruples.
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Solution
The gravitational force acting on the satellite will double if its mass is doubled, as gravitational force is directly proportional to mass.
Correct Answer: A — It doubles.
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Q. If the mass of a simple harmonic oscillator is doubled while keeping the spring constant the same, how does the period change?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Cannot be determined
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Solution
The period T = 2π√(m/k). If m is doubled, T increases.
Correct Answer: A — Increases
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Q. If the mass of an object is 10 kg and it is located at a point where the gravitational potential is -30 J/kg, what is the gravitational potential energy of the object?
A.
-300 J
B.
-30 J
C.
300 J
D.
30 J
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Solution
Gravitational potential energy U = m * V = 10 * (-30) = -300 J.
Correct Answer: A — -300 J
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Q. If the mass of an object is 5 kg and it is at a height of 10 m above the ground, what is its gravitational potential energy?
A.
50 J
B.
100 J
C.
500 J
D.
0 J
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Solution
Gravitational potential energy U = mgh = 5 * 10 * 10 = 500 J.
Correct Answer: B — 100 J
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Q. If the mass of an object is doubled, how does its gravitational potential energy change at a constant height?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
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Solution
The gravitational potential energy U = mgh will double if the mass m is doubled at constant height h.
Correct Answer: B — It doubles
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Q. If the mass of an object is halved and the distance from the center of the Earth is doubled, what happens to the gravitational potential energy?
A.
It remains the same.
B.
It doubles.
C.
It halves.
D.
It quadruples.
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Solution
Gravitational potential energy is directly proportional to mass and inversely proportional to distance, so it halves.
Correct Answer: C — It halves.
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Q. If the mass of an object is halved, how does its gravitational potential energy change at a constant height?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It becomes zero
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Solution
The gravitational potential energy U = mgh is directly proportional to the mass, so if the mass is halved, the potential energy also halves.
Correct Answer: B — It halves
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Q. If the mass of an object is measured as 10.0 kg with an uncertainty of ±0.2 kg, what is the percentage error in the mass measurement?
A.
2%
B.
0.2%
C.
0.5%
D.
1%
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Solution
Percentage error = (absolute error / measured value) * 100 = (0.2 / 10.0) * 100 = 2%.
Correct Answer: D — 1%
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Q. If the mass of an object is measured as 10.0 kg with an uncertainty of ±0.2 kg, what is the percentage error?
A.
2%
B.
0.2%
C.
0.02%
D.
0.5%
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Solution
Percentage error = (absolute error / measured value) * 100 = (0.2 / 10.0) * 100 = 2%.
Correct Answer: A — 2%
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Q. If the mass of an object is measured as 50 kg with an uncertainty of ±0.5 kg, what is the percentage error in the mass measurement?
A.
1%
B.
0.1%
C.
0.5%
D.
2%
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Solution
Percentage error = (absolute error / measured value) * 100 = (0.5 / 50) * 100 = 1%.
Correct Answer: A — 1%
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Q. If the mass of an object is tripled, how does its gravitational potential energy change at a constant height?
A.
It triples
B.
It doubles
C.
It remains the same
D.
It increases by a factor of nine
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Solution
Gravitational potential energy U = mgh, so if mass is tripled, U also triples.
Correct Answer: A — It triples
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Q. If the mass of an object is tripled, how does the gravitational potential energy change for a constant height?
A.
It triples
B.
It doubles
C.
It halves
D.
It remains the same
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Solution
Gravitational potential energy is directly proportional to mass, so it triples.
Correct Answer: A — It triples
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Q. If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational acceleration at the surface of the Earth?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
11 m/s²
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Solution
Using g = G * M / R², where G = 6.67 x 10^-11 N m²/kg², M = 6 x 10^24 kg, and R = 6.4 x 10^6 m, we find g ≈ 9.8 m/s².
Correct Answer: A — 9.8 m/s²
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Q. If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational force on a 1 kg mass at the surface?
A.
9.8 N
B.
6.67 N
C.
10 N
D.
8.9 N
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Solution
Using F = G * (m1 * m2) / r^2, F = (6.67 x 10^-11) * (6 x 10^24 * 1) / (6.4 x 10^6)^2 = 9.8 N.
Correct Answer: A — 9.8 N
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