Q. What is the focal length of a concave lens with a focal point at -15 cm?
A.
15 cm
B.
-15 cm
C.
30 cm
D.
-30 cm
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Solution
The focal length of a concave lens is negative, so it is -15 cm.
Correct Answer: B — -15 cm
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Q. What is the focal length of a concave lens with a power of -2 diopters?
A.
-0.5 m
B.
0.5 m
C.
-2 m
D.
2 m
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Solution
Power (P) = 1/focal length (f). Therefore, f = 1/P = 1/(-2) = -0.5 m.
Correct Answer: A — -0.5 m
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Q. What is the focal length of a concave mirror if an object is placed at a distance of 30 cm from the mirror and the image is formed at a distance of 15 cm from the mirror?
A.
10 cm
B.
15 cm
C.
20 cm
D.
25 cm
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Solution
Using the mirror formula, 1/f = 1/v + 1/u. Here, v = -15 cm (real image) and u = -30 cm (object distance). Thus, 1/f = 1/(-15) + 1/(-30) = -1/10, so f = -10 cm.
Correct Answer: A — 10 cm
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Q. What is the focal length of a concave mirror if an object placed 30 cm in front of it produces an image at 10 cm in front of the mirror?
A.
5 cm
B.
10 cm
C.
15 cm
D.
20 cm
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Solution
Using the mirror formula 1/f = 1/v + 1/u, where u = -30 cm and v = -10 cm, we find f = 15 cm.
Correct Answer: C — 15 cm
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Q. What is the focal length of a concave mirror if an object placed at a distance of 30 cm produces an image at a distance of 15 cm?
A.
10 cm
B.
15 cm
C.
20 cm
D.
25 cm
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Solution
Using the mirror formula, 1/f = 1/v + 1/u; here, v = -15 cm (real image) and u = -30 cm. Thus, 1/f = 1/(-15) + 1/(-30) = -1/10, so f = 10 cm.
Correct Answer: A — 10 cm
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Q. What is the focal length of a convex lens if it forms a real image at a distance of 30 cm when the object is placed at 15 cm from the lens?
A.
10 cm
B.
15 cm
C.
20 cm
D.
25 cm
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Solution
Using the lens formula 1/f = 1/v - 1/u, where v = 30 cm and u = -15 cm, we find f = 20 cm.
Correct Answer: C — 20 cm
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Q. What is the focal length of a lens if it forms a virtual image at a distance of 12 cm when the object is placed at 8 cm?
A.
-24 cm
B.
-12 cm
C.
12 cm
D.
24 cm
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Solution
Using the lens formula, we find the focal length to be -12 cm.
Correct Answer: B — -12 cm
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Q. What is the focal length of a lens if it forms a virtual image at a distance of 15 cm when the object is placed at 10 cm?
A.
-30 cm
B.
30 cm
C.
15 cm
D.
10 cm
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Solution
Using the lens formula 1/f = 1/v - 1/u, we have 1/f = 1/(-15) - 1/(-10) = -1/15 + 1/10 = -1/30, thus f = -30 cm.
Correct Answer: A — -30 cm
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Q. What is the focal length of a lens if it forms an image at infinity when the object is placed at 30 cm?
A.
30 cm
B.
15 cm
C.
60 cm
D.
20 cm
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Solution
For the image to be at infinity, the focal length must be equal to the object distance, hence f = 60 cm.
Correct Answer: C — 60 cm
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Q. What is the focal length of a lens that forms a virtual image at a distance of 20 cm when the object is placed at 10 cm?
A.
5 cm
B.
10 cm
C.
15 cm
D.
20 cm
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Solution
Using the lens formula, 1/f = 1/v - 1/u. Here, v = -20 cm (virtual image), u = -10 cm. Solving gives f = 5 cm.
Correct Answer: A — 5 cm
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Q. What is the focal length of a plano-convex lens with a radius of curvature of 30 cm?
A.
15 cm
B.
30 cm
C.
45 cm
D.
60 cm
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Solution
Using the lens maker's formula for a plano-convex lens, f = R/2 = 30 cm / 2 = 30 cm.
Correct Answer: B — 30 cm
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Q. What is the force between two point charges of +2μC and -3μC separated by a distance of 0.5m in vacuum?
A.
-1.08 N
B.
-0.72 N
C.
1.08 N
D.
0.72 N
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Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (9 × 10^9) * |2 × 10^-6 * -3 × 10^-6| / (0.5)^2 = -1.08 N.
Correct Answer: A — -1.08 N
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Q. What is the force experienced by a charge q in an electric field E?
A.
F = qE
B.
F = E/q
C.
F = q/E
D.
F = q + E
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Solution
The force experienced by a charge q in an electric field E is given by F = qE.
Correct Answer: A — F = qE
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Q. What is the force experienced by a charge q moving with velocity v in a magnetic field B at an angle θ?
A.
qvB
B.
qvB sin(θ)
C.
qvB cos(θ)
D.
qvB tan(θ)
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Solution
The magnetic force on a charge moving in a magnetic field is given by F = qvB sin(θ), where θ is the angle between the velocity and the magnetic field.
Correct Answer: B — qvB sin(θ)
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Q. What is the force experienced by a charge q moving with velocity v in a magnetic field B?
A.
qvB
B.
qvB sin(θ)
C.
qvB cos(θ)
D.
qvB tan(θ)
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Solution
The force experienced by a charge q moving with velocity v in a magnetic field B is given by the Lorentz force law: F = q(v × B), which can be expressed as F = qvB sin(θ), where θ is the angle between the velocity and the magnetic field.
Correct Answer: B — qvB sin(θ)
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Q. What is the force experienced by a current-carrying conductor placed in a magnetic field?
A.
Electromotive force
B.
Lorentz force
C.
Centripetal force
D.
Gravitational force
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Solution
The force experienced by a current-carrying conductor in a magnetic field is known as the Lorentz force.
Correct Answer: B — Lorentz force
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Q. What is the force on a charge q moving with velocity v in a magnetic field B?
A.
qvB
B.
qvBsinθ
C.
qvBcosθ
D.
qB
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Solution
The force on a charge moving in a magnetic field is given by F = qvBsinθ, where θ is the angle between v and B.
Correct Answer: B — qvBsinθ
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Q. What is the force required to keep a 15 kg object moving at a constant velocity?
A.
0 N
B.
15 N
C.
150 N
D.
None of the above
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Solution
According to Newton's first law, no net force is required to maintain constant velocity.
Correct Answer: A — 0 N
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Q. What is the formula for calculating kinetic energy?
A.
KE = mv²
B.
KE = 1/2 mv²
C.
KE = mgh
D.
KE = 1/2 mgh
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Solution
The formula for calculating kinetic energy is KE = 1/2 mv², where m is mass and v is velocity.
Correct Answer: B — KE = 1/2 mv²
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Q. What is the formula for calculating the frequency of a wave?
A.
f = 1/T
B.
f = λ/T
C.
f = v/λ
D.
f = vT
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Solution
The frequency of a wave is calculated using the formula f = 1/T, where T is the period of the wave.
Correct Answer: A — f = 1/T
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Q. What is the formula for calculating the magnetic force on a charged particle moving in a magnetic field?
A.
F = qE
B.
F = qvBsinθ
C.
F = mv^2/r
D.
F = qvE
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Solution
The magnetic force on a charged particle is given by F = qvBsinθ, where q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between v and B.
Correct Answer: B — F = qvBsinθ
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Q. What is the formula for calculating the potential energy of an object at height h?
A.
PE = mgh
B.
PE = 1/2 mv²
C.
PE = mv²
D.
PE = mgh²
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Solution
The potential energy of an object at height h is calculated using the formula PE = mgh, where m is mass, g is gravitational acceleration, and h is height.
Correct Answer: A — PE = mgh
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Q. What is the formula for calculating the total power in a series RLC circuit?
A.
P = VI
B.
P = I^2R
C.
P = V^2/R
D.
P = VI cos(φ)
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Solution
The total power in a series RLC circuit is given by P = VI cos(φ), where φ is the phase angle.
Correct Answer: D — P = VI cos(φ)
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Q. What is the formula for calculating the total power in an AC circuit with a power factor?
A.
P = VI
B.
P = VI cos(φ)
C.
P = VI sin(φ)
D.
P = V^2/R
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Solution
The total power in an AC circuit is given by P = VI cos(φ), where φ is the phase angle.
Correct Answer: B — P = VI cos(φ)
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Q. What is the formula for calculating the work done by a force?
A.
W = Fd
B.
W = F/v
C.
W = F/t
D.
W = mv
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Solution
The work done by a force is calculated using the formula W = Fd, where F is the force and d is the distance moved in the direction of the force.
Correct Answer: A — W = Fd
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Q. What is the formula for gravitational potential energy?
A.
PE = mgh
B.
PE = 1/2 mv²
C.
PE = mv
D.
PE = mgh²
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Solution
Gravitational potential energy is calculated using the formula PE = mgh, where m is mass, g is acceleration due to gravity, and h is height.
Correct Answer: A — PE = mgh
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Q. What is the formula for the angular position of the first minimum in a double-slit diffraction pattern?
A.
d sin(θ) = mλ
B.
d sin(θ) = (m + 1/2)λ
C.
d sin(θ) = (m - 1/2)λ
D.
d sin(θ) = 2mλ
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Solution
The angular position of the first minimum in a double-slit diffraction pattern is given by d sin(θ) = mλ, where m = 1 for the first minimum.
Correct Answer: A — d sin(θ) = mλ
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Q. What is the formula for the angular position of the m-th order maximum in a double-slit experiment?
A.
d sin θ = mλ
B.
d cos θ = mλ
C.
d tan θ = mλ
D.
d = mλ/sin θ
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Solution
The correct formula for the angular position of the m-th order maximum is d sin θ = mλ.
Correct Answer: A — d sin θ = mλ
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Q. What is the formula for the equivalent resistance in a balanced Wheatstone bridge?
A.
R_eq = (P + Q)
B.
C.
(R + S)
D.
R_eq = P + Q + R + S
.
R_eq = P
.
.
Q + R
.
.
S
.
R_eq = (P*R)/(Q + S)
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Solution
The equivalent resistance in a balanced Wheatstone bridge can be calculated using the parallel formula.
Correct Answer: A — R_eq = (P + Q)
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Q. What is the formula for the equivalent resistance of two resistors R1 and R2 in series?
A.
R_eq = R1 + R2
B.
R_eq = R1 * R2 / (R1 + R2)
C.
R_eq = R1 - R2
D.
R_eq = R1 / R2
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Solution
The equivalent resistance of two resistors in series is simply the sum of their resistances: R_eq = R1 + R2.
Correct Answer: A — R_eq = R1 + R2
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