The focal length (f) of a mirror is given by f = R/2. For a convex mirror, R is positive, so f = 20 cm / 2 = 10 cm.

According to Ohm's Law, if the resistance (R) is doubled and the voltage (V) remains constant, the current (I) will be halved (I = V/R).

Using Raoult's Law: P_solution = X_solvent * P_solvent. X_solvent = P_solution / P_solvent = 80/100 = 0.8, thus X_solute = 1 - X_solvent = 0.2.

Relative lowering of vapor pressure = (P° - P) / P° = (100 - 80) / 100 = 0.2.

The peak voltage (V_peak) is calculated as V_peak = V_rms × √2 = 100 V × √2 ≈ 141.42 V.

Inductive reactance (X_L) is given by X_L = V/I. Here, X_L = 100 V / 2 A = 50 Ω.

The electric fields due to both charges at the midpoint cancel each other out, resulting in a net electric field of 0 N/C.

Total resistance R = 4Ω + 12Ω = 16Ω. Voltage V = I * R = 2A * 16Ω = 32V.

Using the formula for parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/4 + 1/6 = 5/12, R_eq = 12/5 = 2.4Ω.

In series, R_total = R1 + R2 = 5Ω + 10Ω = 15Ω.

In a body-centered cubic (BCC) structure, there are 2 atoms per unit cell (1 from the center and 1 from the corners).

Activation energy is the minimum energy required to initiate a chemical reaction.

Power P = V^2/R = 5^2/10 = 25/10 = 2.5W.

Total resistance R = 10Ω + 5Ω = 15Ω. Voltage V = I * R = 2A * 15Ω = 30V.

Total resistance R = 4Ω + 4Ω = 8Ω. Current I = V/R = 12V/8Ω = 1.5A.

The voltage drop across the resistor is equal to the battery voltage, which is 15V.

The total resistance is 15Ω. The current I = V/R = 15V/15Ω = 1A. Voltage drop across 10Ω = I * R = 1A * 10Ω = 10V.

Power (P) can be calculated using P = V^2 / R. Here, P = 24V^2 / 6Ω = 96W.

Power P = V^2/R = 24^2/8 = 576/8 = 72 W.

Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V/9Ω = 1A.

Using Ohm's Law, R = V/I = 24V / 6A = 4Ω.

In a circuit with an inductor, the current increases gradually due to the inductor's opposition to changes in current.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

According to Ohm's law, I = V/R. If R is doubled, I will be halved.

Using Ohm's Law, R = V / I = 24V / 3A = 8Ω.

According to Ohm's law, if V is tripled, I will also triple.

Removing a reactant will shift the equilibrium to the left to produce more reactants, according to Le Chatelier's principle.

According to the first law of thermodynamics, if the internal energy increases, it implies that either work is done on the system or heat is added to the system.

According to the first law of thermodynamics, if the internal energy increases, it implies that heat is added to the system and/or work is done on the system.