If two resistors of 4Ω and 12Ω are connected in series, what is the total voltage across them if the current flowing is 2A? (2020)

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Q: If two resistors of 4Ω and 12Ω are connected in series, what is the total voltage across them if the current flowing is 2A? (2020)

Solution: Total resistance R = 4Ω + 12Ω = 16Ω. Voltage V = I * R = 2A * 16Ω = 32V.

Steps: 6

Step 1: Identify the resistors. We have two resistors: one is 4Ω and the other is 12Ω.
Step 2: Calculate the total resistance when resistors are in series. Add the resistances together: 4Ω + 12Ω = 16Ω.
Step 3: Identify the current flowing through the circuit. The current is given as 2A.
Step 4: Use Ohm's Law to find the total voltage. Ohm's Law states that Voltage (V) = Current (I) * Resistance (R).
Step 5: Substitute the values into the formula: V = 2A * 16Ω.
Step 6: Calculate the total voltage: 2A * 16Ω = 32V.