Q. For the equilibrium 2A(g) ⇌ B(g) + C(g), if the volume of the container is decreased, what will happen to the equilibrium? (2020)
A.Shift to the left
B.Shift to the right
C.No change
D.Depends on temperature
Solution
Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas, which is the right side in this case.
Q. For the equilibrium reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what is the effect of decreasing the volume of the container? (2021)
A.Shift to the left
B.Shift to the right
C.No effect
D.Increase in temperature
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas, which is the right side in this case.
Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), if the volume of the container is decreased, what will happen to the equilibrium? (2021)
A.Shift to the right
B.Shift to the left
C.No change
D.Depends on the temperature
Solution
Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas, which is the right side (2 moles of SO3).
Q. For the reaction: 2A(g) + B(g) ⇌ 3C(g), if the volume of the container is decreased, what will be the effect on the equilibrium? (2022)
A.Shift to the left
B.Shift to the right
C.No change
D.Increase in temperature
Solution
Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas. Here, it shifts to the right, producing more C.
Q. For the reaction: 2A(g) + B(g) ⇌ 3C(g), what is the correct expression for the equilibrium constant Kc? (2021)
A.[C]^3 / ([A]^2[B])
B.[A]^2[B] / [C]^3
C.[C]^3 / [A]^2
D.[B] / [C]^3
Solution
The equilibrium constant Kc is given by the expression Kc = [C]^3 / ([A]^2[B]), where the concentrations are raised to the power of their coefficients.
Q. If 0.5 moles of a non-volatile solute are dissolved in 1 kg of water, what is the expected change in boiling point? (Kb for water = 0.52 °C kg/mol) (2021)
A.0.26 °C
B.0.52 °C
C.1.04 °C
D.0.78 °C
Solution
Boiling point elevation = i * Kb * m = 1 * 0.52 * 0.5 = 0.26 °C, so change = 0.52 °C.
Q. If a capacitor is charged to a voltage of 5 V and then disconnected from the battery, what happens to the charge on the capacitor if the voltage is increased to 10 V? (2023)
A.Charge increases
B.Charge decreases
C.Charge remains the same
D.Charge becomes zero
Solution
When the voltage is increased to 10 V, the charge on the capacitor increases because charge (Q) is directly proportional to voltage (V) for a given capacitance.
