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In a circuit with a 12V battery and two 4Ω resistors in series, what is the curr
In a circuit with a 12V battery and two 4Ω resistors in series, what is the current flowing through the circuit? (2023)
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In a circuit with a 12V battery and two 4Ω resistors in series, what is the current flowing through the circuit? (2023)
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Total resistance R = 4Ω + 4Ω = 8Ω. Current I = V/R = 12V/8Ω = 1.5A.
Questions & Step-by-step Solutions
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Q: In a circuit with a 12V battery and two 4Ω resistors in series, what is the current flowing through the circuit? (2023)
Solution:
Total resistance R = 4Ω + 4Ω = 8Ω. Current I = V/R = 12V/8Ω = 1.5A.
Steps: 6
Show Steps
Step 1: Identify the voltage of the battery, which is 12V.
Step 2: Identify the resistance of each resistor, which is 4Ω.
Step 3: Since the resistors are in series, add their resistances together: 4Ω + 4Ω = 8Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 12V / 8Ω.
Step 6: Calculate the current: 12V divided by 8Ω equals 1.5A.
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