The strength of the magnetic field inside a solenoid is affected by the number of turns per unit length and the current flowing through it, as well as the length of the solenoid.

The magnetic field strength inside a solenoid is directly proportional to the current flowing through it.

Magnetic field B = μ₀ * (N/L) * I = (4π x 10^-7 Tm/A) * (200/0.5) * 2 = 0.8 T.

The magnetic field inside a solenoid is given by B = μ₀ * (N/L) * I. Assuming N/L = 1 for simplicity, B = μ₀ * I = 4π × 10^-7 T*m/A * 5 A = 0.5 T.

Using conservation of energy, the potential energy mgh converts to kinetic energy. For a solid cone, the final speed at the bottom is v = √(2gh).

For a solid cone rolling down an incline, the potential energy at height h is converted into translational and rotational kinetic energy, leading to PE = 2KE.

The moment of inertia of a solid cone about its axis is I = (1/10)mR^2.

The solid cylinder has a smaller moment of inertia compared to the hollow cylinder, thus it will have a greater speed at the bottom.

The solid cylinder has a lower moment of inertia, thus it accelerates faster and reaches the ground first.

The solid cylinder has a smaller moment of inertia compared to the hollow cylinder, thus it accelerates faster and reaches the bottom first.

The solid cylinder reaches the bottom first because it has a smaller moment of inertia compared to the hollow cylinder.

Using conservation of energy, potential energy at the top equals kinetic energy at the bottom. The speed v at the bottom is v = √(2gh).

At the bottom, total kinetic energy = translational + rotational. For a solid cylinder, the ratio of translational to total kinetic energy is 2:1.

For a solid cylinder, the ratio of translational kinetic energy to total kinetic energy is 2/5.

At the bottom, total mechanical energy is converted into kinetic energy, which is the sum of translational and rotational kinetic energy. For a solid cylinder, 2/3 of the energy is kinetic.

Using conservation of energy, potential energy at the top equals kinetic energy at the bottom. For a solid cylinder, v = √(3gh/2).

Using conservation of energy, potential energy converts to kinetic energy. For a solid cylinder, v = √(2gh).

The solid sphere will hit the ground first because it has a smaller moment of inertia, allowing it to roll down faster.

The solid sphere will have a greater linear speed because it has a smaller moment of inertia, allowing it to convert more potential energy into translational kinetic energy.

The solid sphere reaches the bottom first because it has a lower moment of inertia, allowing it to convert more potential energy into translational kinetic energy.

The solid sphere will have a greater translational speed because it has a smaller moment of inertia.

The solid sphere has a smaller moment of inertia compared to the hollow sphere, allowing it to accelerate faster down the incline.

The solid sphere has a smaller moment of inertia compared to the hollow sphere, allowing it to accelerate faster down the incline.

Total angular momentum L = Iω, where I = (2/5)MR^2 for a solid sphere.

The moment of inertia of a solid sphere about its center is I = 2/5 MR^2.

The moment of inertia of a solid sphere about an axis through its center is I = 2/5 MR^2.

The acceleration of the center of mass of a rolling object is given by a = g sin(θ) / (1 + k^2/r^2). For a solid sphere, k^2/r^2 = 2/5, thus a = g sin(θ) / (1 + 2/5) = g sin(θ) / (7/5) = (5/7)g sin(θ).

Using conservation of energy, potential energy at the top = kinetic energy at the bottom. The total kinetic energy is the sum of translational and rotational kinetic energy. Thus, v = √(5gh/7).

Using conservation of energy, potential energy at the top = kinetic energy at the bottom. The total kinetic energy is the sum of translational and rotational kinetic energy. Thus, mgh = (1/2)mv^2 + (1/5)mv^2, leading to v = √(10gh/7).

Using conservation of energy, potential energy at the top = kinetic energy at the bottom. For a solid sphere, v = √(5gh/7). Thus, speed at the bottom is √(3gh).