If the speed of a satellite is doubled, the orbital radius will decrease by a factor of four, as orbital speed is inversely proportional to the square root of the radius.

If the speed of a satellite is doubled, the radius of its orbit decreases by a factor of four due to the relationship between speed and radius in circular motion.

Increasing the speed of a satellite in a circular orbit will cause its orbit to become elliptical.

The gravitational force is inversely proportional to the square of the distance; halving the radius increases the force by a factor of four.

Orbital speed (v) = √(GM/r). As r increases, v decreases.

Orbital speed v = √(GM/r). If r is tripled, v decreases by a factor of √3.

Speed (v) = √(g*r) = √(9.8 m/s² * 7000 * 1000 m) = 7.9 km/s.

Centripetal acceleration a_c = v²/r = (7.9 km/s)² / (7000 km) = 0.00063 km/s² = 6.3 m/s².

Gravitational force ∝ 1/r². If radius is doubled, force becomes 1/(2²) = 1/4.

Increasing the speed of a satellite in a circular orbit will cause it to move into an elliptical orbit.

As the satellite moves to a higher orbit, its distance from the Earth increases, leading to an increase in gravitational potential energy.

Angular momentum L = mvr, where v is the orbital speed and r is the radius of the orbit.

All the given expressions represent the centripetal force acting on the satellite in different forms.

The gravitational potential energy of a satellite in orbit is negative due to the attractive force of gravity.

The orbital speed of a satellite is given by v = sqrt(G * M / r), where M is the mass of the Earth.

The orbital speed of a satellite is given by v = sqrt(G * M / r), where M is the mass of the Earth.

For a satellite in a stable orbit, the gravitational force provides the necessary centripetal force, hence they are equal.

The orbital speed can be calculated using the formula v = √(GM/r). For a height of 300 km, the speed is approximately 7.9 km/s.

A polar orbit allows the satellite to pass over the entire surface of the Earth as the planet rotates beneath it.

The gravitational acceleration experienced by a satellite at a height of 500 km is approximately 8.7 m/s².

5% of 200 students = 0.05 * 200 = 10 students receive the scholarship.

Each student receives = $10,000 / 5 = $2000.

Each student receives = $5000 / 5 = $1000.

Tax amount = 15% of $1200 = $180. Amount received after tax = $1200 - $180 = $1020.

Number of students receiving trophy = 10% of 200 = 0.1 * 200 = 20.

Total score = 85 + 90 + 95 = 270.

Area of a semicircle = (1/2) × πr². Radius = 7 cm. Area = (1/2) × 3.14 × (7)² = 76.96 cm².

Area of a semicircle = (1/2) × πr². Radius = 7 cm. Area = (1/2) × 3.14 × (7)² = (1/2) × 3.14 × 49 = 76.96 cm², which rounds to 77 cm².

Area of a semicircle = (1/2) × πr². Radius = 7 cm. Area = (1/2) × 3.14 × (7)² = 76.96 cm².

Radius = 7 cm. Area of semicircle = (1/2) × πr² = (1/2) × (22/7) × (7)² = 77 cm².