Q. A material is said to be elastic if it:
A.
Returns to its original shape after deformation
B.
Can be permanently deformed
C.
Breaks under stress
D.
Has a high tensile strength
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Solution
A material is considered elastic if it returns to its original shape after the removal of the applied stress.
Correct Answer: A — Returns to its original shape after deformation
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Q. A material is subjected to a tensile stress of 100 MPa and experiences a strain of 0.002. What is its Young's modulus?
A.
50 GPa
B.
100 GPa
C.
200 GPa
D.
500 GPa
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Solution
Young's modulus (Y) = Stress / Strain = 100 MPa / 0.002 = 50 GPa.
Correct Answer: B — 100 GPa
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Q. A material with a Poisson's ratio of 0.5 is considered to be:
A.
Perfectly elastic
B.
Perfectly plastic
C.
Incompressible
D.
Brittle
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Solution
A Poisson's ratio of 0.5 indicates that the material is incompressible.
Correct Answer: C — Incompressible
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Q. A meal contains 15 grams of fat, 30 grams of carbohydrates, and 10 grams of protein. How many total calories does this meal provide? (Fat = 9 cal/g, Carbohydrates = 4 cal/g, Protein = 4 cal/g) (2021)
A.
200 calories
B.
250 calories
C.
300 calories
D.
350 calories
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Solution
Total calories = (15g * 9) + (30g * 4) + (10g * 4) = 135 + 120 + 40 = 295 calories.
Correct Answer: C — 300 calories
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Q. A meal contains 20 grams of fat. How many calories does this contribute to the meal? (Fat = 9 cal/g) (2021)
A.
180
B.
160
C.
200
D.
220
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Solution
Calories from fat = 20g * 9 cal/g = 180 calories.
Correct Answer: A — 180
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Q. A meal contains 40 grams of fat. If each gram of fat provides 9 calories, how many calories are derived from fat in this meal? (2023)
A.
320 calories
B.
360 calories
C.
400 calories
D.
450 calories
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Solution
Calories from fat = 40g * 9 = 360 calories.
Correct Answer: B — 360 calories
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Q. A meal contains 800 calories, with 40% from carbohydrates, 30% from proteins, and 30% from fats. How many calories are from carbohydrates?
A.
240 calories
B.
320 calories
C.
400 calories
D.
480 calories
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Solution
40% of 800 calories = 0.40 * 800 = 320 calories.
Correct Answer: B — 320 calories
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Q. A measurement of 15.5 m has a relative error of 0.03. What is the absolute error?
A.
0.465 m
B.
0.5 m
C.
0.3 m
D.
0.45 m
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Solution
Absolute error = Relative error * Measured value = 0.03 * 15.5 m = 0.465 m.
Correct Answer: A — 0.465 m
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Q. A measurement of 30 m has an error of ±0.1 m. What is the true value if the measurement is taken as the average?
A.
30.1 m
B.
30 m
C.
29.9 m
D.
30.05 m
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Solution
True value is taken as the average of the measured value and the error, which is (30 + 29.9) / 2 = 30.05 m.
Correct Answer: D — 30.05 m
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Q. A measurement of a physical quantity is reported as 25.0 ± 0.5 units. What is the total uncertainty if this quantity is multiplied by 3?
A.
1.5 units
B.
0.5 units
C.
1.0 units
D.
2.0 units
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Solution
Total uncertainty = 3 * 0.5 = 1.5 units.
Correct Answer: A — 1.5 units
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Q. A measurement of length is recorded as 12.3 cm with an uncertainty of ±0.1 cm. What is the relative error in the measurement?
A.
0.0081
B.
0.008
C.
0.01
D.
0.1
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Solution
Relative error = (absolute error / measured value) = 0.1 / 12.3 = 0.0081.
Correct Answer: B — 0.008
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Q. A measurement of length is recorded as 5.0 cm with an uncertainty of ±0.1 cm. What is the relative error in this measurement?
A.
0.02
B.
0.01
C.
0.005
D.
0.1
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Solution
Relative error = (absolute error / measured value) = 0.1 / 5.0 = 0.02 or 2%.
Correct Answer: B — 0.01
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Q. A merchant bought a batch of goods for $500 and sold them for $600. If he had given a discount of 10% on the selling price, what would be his profit?
A.
$50
B.
$60
C.
$70
D.
$40
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Solution
Selling Price after discount = 600 - 10% of 600 = 600 - 60 = 540. Profit = 540 - 500 = 40.
Correct Answer: A — $50
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Q. A merchant bought a batch of goods for $500 and sold them for $600. What is the profit in dollars and the profit percentage?
A.
$100, 20%
B.
$100, 25%
C.
$150, 30%
D.
$200, 40%
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Solution
Profit = Selling Price - Cost Price = $600 - $500 = $100. Profit Percentage = (Profit / Cost Price) * 100 = ($100 / $500) * 100 = 20%.
Correct Answer: A — $100, 20%
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Q. A merchant bought a batch of goods for $500 and sold them for $600. What is the profit percentage?
A.
20%
B.
25%
C.
30%
D.
15%
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Solution
Profit = Selling Price - Cost Price = $600 - $500 = $100. Profit percentage = (Profit/Cost Price) * 100 = ($100/$500) * 100 = 20%.
Correct Answer: B — 25%
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Q. A merchant bought a batch of goods for $600 and sold them at a total of $720. What is the profit percentage? (2023)
A.
15%
B.
20%
C.
25%
D.
30%
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Solution
Profit = Selling Price - Cost Price = 720 - 600 = 120. Profit Percentage = (120/600) * 100 = 20%.
Correct Answer: B — 20%
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Q. A merchant bought a bicycle for $500 and sold it for $450. What is the loss percentage?
A.
10%
B.
15%
C.
20%
D.
5%
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Solution
Loss = Cost Price - Selling Price = $500 - $450 = $50. Loss Percentage = (Loss/Cost Price) * 100 = ($50/$500) * 100 = 10%.
Correct Answer: A — 10%
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Q. A merchant sells a product for $500, which is a 20% profit over the cost price. What is the cost price?
A.
$400
B.
$450
C.
$480
D.
$500
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Solution
Let the cost price be x. Selling Price = x + 20% of x = 500. Thus, 1.2x = 500, so x = $400.
Correct Answer: A — $400
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Q. A metal block of mass 2 kg at 100°C is placed in 1 kg of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.2 J/g°C, Specific heat of metal = 0.9 J/g°C)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
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Solution
Using conservation of energy: m1*c1*(T1-Tf) = m2*c2*(Tf-T2). Solving gives Tf = 50°C.
Correct Answer: C — 50°C
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Q. A metal rod is heated at one end. If the temperature at the heated end is 100°C and the other end is at 20°C, what is the temperature gradient along the rod?
A.
80°C/m
B.
20°C/m
C.
10°C/m
D.
5°C/m
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Solution
Temperature gradient = (T_hot - T_cold) / Length. Assuming length is 8 m, gradient = (100°C - 20°C) / 8 m = 10°C/m.
Correct Answer: C — 10°C/m
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Q. A metal rod of length 1 m and cross-sectional area 1 cm² is heated at one end. If the temperature difference between the ends is 100°C, what is the rate of heat transfer through the rod? (Thermal conductivity of the metal = 200 W/m°C)
A.
200 W
B.
400 W
C.
600 W
D.
800 W
Show solution
Solution
Using Fourier's law: Q/t = kA(ΔT/L) = 200 W/m°C * 0.0001 m² * (100°C/1 m) = 200 W.
Correct Answer: A — 200 W
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Q. A military base has 120 soldiers. If 30% of them are on leave, how many soldiers are present? (2019)
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Solution
Soldiers on leave = 30% of 120 = 0.3 × 120 = 36. Present = 120 - 36 = 84.
Correct Answer: B — 80
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Q. A military base has a rectangular area of 200 m by 150 m. What is the area of the base? (2019)
A.
30000 m²
B.
25000 m²
C.
20000 m²
D.
15000 m²
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Solution
Area = Length × Width = 200 m × 150 m = 30000 m²
Correct Answer: B — 25000 m²
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Q. A military base is located 150 km from the city. If a vehicle travels at 75 km/h, how long will it take to reach the base? (2019)
A.
1.5 hours
B.
2 hours
C.
2.5 hours
D.
3 hours
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Solution
Time = Distance / Speed = 150 km / 75 km/h = 2 hours
Correct Answer: B — 2 hours
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Q. A military base requires 2000 liters of fuel per day. How much fuel is needed for 10 days? (2022)
A.
15000 liters
B.
18000 liters
C.
20000 liters
D.
22000 liters
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Solution
Total Fuel = Daily Requirement × Number of Days = 2000 liters/day × 10 days = 20000 liters
Correct Answer: C — 20000 liters
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Q. A military exercise requires 3 hours of training per day for 5 days. How many total hours of training are required? (2023)
A.
10 hours
B.
12 hours
C.
15 hours
D.
18 hours
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Solution
Total Training Hours = 3 hours/day × 5 days = 15 hours
Correct Answer: D — 18 hours
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Q. A military operation requires 500 liters of fuel. If one tank can carry 125 liters, how many tanks are needed? (2019)
A.
2 tanks
B.
3 tanks
C.
4 tanks
D.
5 tanks
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Solution
Number of tanks = Total fuel / Fuel per tank = 500 liters / 125 liters/tank = 4 tanks.
Correct Answer: C — 4 tanks
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Q. A mixture consists of 40% red paint and 60% blue paint. If 5 liters of blue paint is added, what will be the new percentage of red paint if the total volume becomes 25 liters?
A.
20%
B.
25%
C.
30%
D.
35%
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Solution
Initial red paint = 40% of 20 liters = 8 liters. New total = 25 liters. New percentage of red = (8/25) * 100 = 32%.
Correct Answer: B — 25%
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Q. A mixture contains 15% alcohol and 85% water. If 20 liters of the mixture is taken, how much alcohol is present?
A.
2 liters
B.
3 liters
C.
4 liters
D.
5 liters
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Solution
Alcohol = 15% of 20 liters = 0.15 * 20 = 3 liters.
Correct Answer: B — 3 liters
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Q. A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of the mixture is taken, how much of substance Y is there?
A.
8 liters
B.
2 liters
C.
4 liters
D.
6 liters
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Solution
80% of 10 liters = 0.80 * 10 = 8 liters of substance Y.
Correct Answer: A — 8 liters
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