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A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of th
A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of the mixture is taken, how much of substance Y is there?
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Practice Questions
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Q1
A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of the mixture is taken, how much of substance Y is there?
8 liters
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80% of 10 liters = 0.80 * 10 = 8 liters of substance Y.
Questions & Step-by-step Solutions
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Q
Q: A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of the mixture is taken, how much of substance Y is there?
Solution:
80% of 10 liters = 0.80 * 10 = 8 liters of substance Y.
Steps: 6
Show Steps
Step 1: Understand that the mixture has 20% of substance X and 80% of substance Y.
Step 2: Know that you are taking 10 liters of this mixture.
Step 3: To find out how much of substance Y is in the 10 liters, calculate 80% of 10 liters.
Step 4: Convert 80% to a decimal, which is 0.80.
Step 5: Multiply 0.80 by 10 liters: 0.80 * 10 = 8 liters.
Step 6: Conclude that there are 8 liters of substance Y in the 10 liters of mixture.
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