The gravitational potential energy of a satellite at height h is given by U = -GMm/(R+h), where R is the radius of the Earth.

The gravitational potential energy is given by the formula U = mgh.

The gravitational potential energy is given by U = -G * (m1 * m2) / r.

The gravitational potential energy is given by U = -G * (m1 * m2) / r.

Oxygen has 8 electrons, and its ground state electron configuration is 1s² 2s² 2p⁴.

Alkali metals are located in group 1 of the periodic table.

Halogens are located in group 17 of the periodic table.

The half-life is defined as the time taken for half of the radioactive sample to decay.

The half-life is defined as the time required for half of the radioactive substance to decay, which is given as 10 years.

The half-life of a radioactive substance is defined as the time taken for half of the substance to decay.

The prime factorization gives: 36 = 2^2 * 3^2, 60 = 2^2 * 3 * 5, 48 = 2^4 * 3. The HCF is 2^2 * 3 = 12.

Heat required Q = mcΔT = (2000 g)(0.9 J/g°C)(50°C) = 90000 J.

Q = m*c*ΔT = 250 g * 0.9 J/g°C * (75°C - 25°C) = 4500 J.

In hexadecimal, the decimal number 16 is represented as 10.

The Bharat Ratna is the highest civilian award in India, awarded for exceptional service towards the advancement of art, literature, and science.

Kangchenjunga is the highest peak in India, standing at 8,586 meters.

A tetrahedral shape corresponds to sp3 hybridization.

The carbon atoms in benzene are sp2 hybridized, forming a planar structure with 120-degree bond angles.

The nitrogen in a primary amine is sp3 hybridized.

Nitrogen in amines is sp3 hybridized due to the presence of three substituents and a lone pair.

In acetylene, each carbon atom is sp hybridized, forming a triple bond between them.

In CO2, the carbon atom forms two double bonds with oxygen atoms, indicating sp hybridization.

In ethylene, each carbon atom is sp2 hybridized, forming a double bond with the other carbon.

The carbon atoms in ethyne (C2H2) are sp hybridized due to the triple bond between them.

The carbon atoms in alkenes are sp2 hybridized due to the presence of a double bond.

In alkynes, the carbon atoms involved in the triple bond are sp hybridized.

The carbon atoms in benzene are sp2 hybridized, forming a planar structure with 120-degree bond angles.

The carbon atoms in ethylene (C2H4) are sp2 hybridized due to the presence of a double bond.

In ethyne, the carbon atoms are sp hybridized due to the presence of a triple bond.

The carbon atoms in the double bond of alkenes are sp2 hybridized.