Q. A light ray traveling in diamond (n=2.42) strikes the diamond-air interface. What is the critical angle for total internal reflection?
A.
24.4°
B.
30.0°
C.
36.0°
D.
42.0°
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Solution
Using Snell's law, sin(θc) = n2/n1 = 1.00/2.42. Thus, θc ≈ 24.4°.
Correct Answer: A — 24.4°
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Q. A light ray traveling in glass (n=1.5) strikes the glass-air interface at an angle of 30°. Will it undergo total internal reflection?
A.
Yes
B.
No
C.
Depends on the angle
D.
Not enough information
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Solution
Since sin(30°) < sin(θc) where θc = sin⁻¹(1/1.5) ≈ 41.8°, it will not undergo total internal reflection.
Correct Answer: B — No
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Q. A line graph shows the growth of a plant over 5 days. If the heights are 2 cm, 4 cm, 6 cm, 8 cm, and 10 cm, what is the growth rate per day? (2023)
A.
1 cm
B.
2 cm
C.
3 cm
D.
4 cm
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Solution
Growth rate = (10 - 2) / 4 = 2 cm per day.
Correct Answer: B — 2 cm
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Q. A line graph shows the sales of a company over five months. If the sales were 1000, 1500, 2000, 2500, and 3000 units, what was the total sales over the five months? (2023)
A.
10000
B.
12000
C.
15000
D.
20000
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Solution
Total sales = 1000 + 1500 + 2000 + 2500 + 3000 = 10000 units.
Correct Answer: B — 12000
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Q. A line segment is divided into two parts in the ratio 3:2. If the total length of the segment is 50 cm, what is the length of the longer part? (2023)
A.
30 cm
B.
20 cm
C.
25 cm
D.
15 cm
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Solution
The longer part is (3/5) * 50 = 30 cm, since the total ratio is 3 + 2 = 5.
Correct Answer: A — 30 cm
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Q. A liquid drop is formed on a surface. The angle formed between the tangent to the drop surface and the solid surface is called what?
A.
Contact angle
B.
Surface angle
C.
Tension angle
D.
Cohesion angle
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Solution
The angle formed between the tangent to the drop surface and the solid surface is known as the contact angle, which indicates the wettability of the surface.
Correct Answer: A — Contact angle
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Q. A liquid has a surface tension of 0.03 N/m. What is the height of the liquid column that can be supported by a capillary tube of radius 0.5 mm?
A.
1.2 cm
B.
2.4 cm
C.
3.6 cm
D.
4.8 cm
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Solution
Using the formula h = 2T/(ρgr), we can calculate the height of the liquid column.
Correct Answer: B — 2.4 cm
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Q. A liquid has a surface tension of 0.03 N/m. What is the pressure difference across a curved surface of radius 0.1 m?
A.
0.15 Pa
B.
0.3 Pa
C.
0.6 Pa
D.
0.9 Pa
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Solution
Using the formula ΔP = 2γ/r, ΔP = 2 × 0.03 N/m / 0.1 m = 0.6 Pa.
Correct Answer: B — 0.3 Pa
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Q. A loan of $5000 is taken at a compound interest rate of 5% per annum. What will be the total amount to be paid after 3 years?
A.
$5750
B.
$6300
C.
$6500
D.
$7000
Show solution
Solution
Using A = P(1 + r)^t, A = 5000(1 + 0.05)^3 = 5000 * 1.157625 = $5788.13, which rounds to $6500.
Correct Answer: C — $6500
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Q. A loan of $5000 is taken at a compound interest rate of 6% per annum. What will be the total amount to be paid after 3 years? (1910)
A.
$5900
B.
$6000
C.
$6100
D.
$6200
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Solution
Using A = P(1 + r)^t, we find A = 5000(1 + 0.06)^3 = 5000 * 1.191016 = $5955.08, which rounds to $6100.
Correct Answer: C — $6100
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Q. A loan of $5000 is taken at a simple interest rate of 10% per annum. How much interest will be paid after 4 years? (2000)
A.
$200
B.
$400
C.
$600
D.
$800
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Solution
Interest = Principal * Rate * Time = 5000 * 10/100 * 4 = $2000.
Correct Answer: C — $600
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Q. A loan of $8000 is taken at a compound interest rate of 7% per annum. What will be the total amount to be paid after 4 years? (2000)
A.
$10000
B.
$11000
C.
$12000
D.
$13000
Show solution
Solution
Using A = P(1 + r)^n, A = 8000(1 + 0.07)^4 = 8000 * 1.3107961 ≈ $10486.37, which rounds to $11000.
Correct Answer: B — $11000
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Q. A loan of Rs. 2000 is taken at a simple interest rate of 8% per annum. How much interest will be paid after 4 years? (2000)
A.
Rs. 640
B.
Rs. 480
C.
Rs. 320
D.
Rs. 560
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Solution
Simple Interest = P * r * t = 2000 * 0.08 * 4 = 640.
Correct Answer: B — Rs. 480
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Q. A location at 30° N latitude experiences a temperature of 25°C. If the same temperature is recorded at 30° S latitude, what can be inferred about the climate? (2019)
A.
Identical climate
B.
Different climate
C.
Warmer in the North
D.
Colder in the South
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Solution
At the same latitude, the climate is generally similar, although local factors can cause variations.
Correct Answer: A — Identical climate
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Q. A location at 45° North latitude experiences a time difference of how many hours from a location at 45° South latitude when both are at the same longitude? (2019)
A.
0 hours
B.
1 hour
C.
2 hours
D.
3 hours
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Solution
Latitude does not affect time; both locations at the same longitude will have the same time.
Correct Answer: A — 0 hours
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Q. A location at 90 degrees West longitude is how many hours behind GMT?
A.
3 hours
B.
5 hours
C.
6 hours
D.
7 hours
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Solution
90 degrees West is 90/15 = 6 hours behind GMT.
Correct Answer: B — 5 hours
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Q. A long straight conductor carries a current I. What is the magnetic field at a distance r from the wire?
A.
μ₀I/(2πr)
B.
μ₀I/(4πr)
C.
μ₀I/(πr)
D.
μ₀I/(2r)
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Solution
The magnetic field around a long straight conductor is given by B = μ₀I/(2πr).
Correct Answer: A — μ₀I/(2πr)
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Q. A long straight conductor carrying current I produces a magnetic field B at a distance r from it. What is the expression for B?
A.
μ₀I/(2πr)
B.
μ₀I/(4πr)
C.
μ₀I/(πr)
D.
μ₀I/(8πr)
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Solution
The magnetic field due to a long straight conductor is given by B = μ₀I/(2πr).
Correct Answer: A — μ₀I/(2πr)
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Q. A long straight wire carries a current I. What is the direction of the magnetic field at a point located directly above the wire? (2020)
A.
Towards the wire
B.
Away from the wire
C.
Clockwise
D.
Counterclockwise
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Solution
Using the right-hand rule, the magnetic field direction at a point above the wire is away from the wire.
Correct Answer: B — Away from the wire
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Q. A long straight wire carries a current I. What is the magnetic field at a distance r from the wire?
A.
μ₀I/(2πr)
B.
μ₀I/(4πr)
C.
μ₀I/(8πr)
D.
μ₀I/(πr)
Show solution
Solution
The magnetic field around a long straight wire is given by B = μ₀I/(2πr).
Correct Answer: A — μ₀I/(2πr)
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Q. A long straight wire carries a uniform linear charge density λ. What is the electric field at a distance r from the wire?
A.
λ/(2πε₀r)
B.
λ/(4πε₀r²)
C.
λ/(2πε₀r²)
D.
0
Show solution
Solution
Using Gauss's law for a cylindrical surface around the wire, the electric field E at a distance r is E = λ/(2πε₀r).
Correct Answer: A — λ/(2πε₀r)
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Q. A loop of wire is moved into a magnetic field at a constant speed. What happens to the induced EMF as it enters the field?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes zero
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Solution
As the loop enters the magnetic field, the rate of change of magnetic flux increases, leading to an increase in induced EMF.
Correct Answer: A — It increases
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Q. A loop of wire is moved into a magnetic field at a constant speed. What happens to the induced EMF as the loop enters the field?
A.
Induced EMF increases
B.
Induced EMF decreases
C.
Induced EMF remains constant
D.
Induced EMF becomes zero
Show solution
Solution
As the loop enters the magnetic field, the magnetic flux through the loop increases, leading to an increase in induced EMF.
Correct Answer: A — Induced EMF increases
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Q. A loop of wire is moved into a magnetic field at a constant speed. What happens to the induced current as the loop enters the magnetic field? (2023)
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes zero
Show solution
Solution
As the loop enters the magnetic field, the change in magnetic flux increases, leading to an increase in the induced current.
Correct Answer: A — It increases
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Q. A loop of wire is moved into a magnetic field at a constant speed. What is the effect on the induced current as the loop enters the field?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes zero
Show solution
Solution
As the loop enters the magnetic field, the area of the loop within the field increases, leading to an increase in magnetic flux and thus an increase in the induced current according to Faraday's law.
Correct Answer: A — It increases
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Q. A loop of wire is moved into a uniform magnetic field at a constant speed. What happens to the induced EMF as it enters the field?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes zero
Show solution
Solution
As the loop enters the magnetic field, the area exposed to the magnetic field increases, leading to an increase in the induced EMF.
Correct Answer: A — It increases
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Q. A loop of wire is placed in a changing magnetic field. What phenomenon is observed?
A.
Electromagnetic induction
B.
Magnetic resonance
C.
Electrolysis
D.
Thermal conduction
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Solution
A changing magnetic field induces an electromotive force (EMF) in the loop, a phenomenon known as electromagnetic induction.
Correct Answer: A — Electromagnetic induction
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Q. A loop of wire is placed in a changing magnetic field. What phenomenon is this an example of?
A.
Electromagnetic induction
B.
Magnetic resonance
C.
Electrostatics
D.
Magnetic hysteresis
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Solution
This is an example of electromagnetic induction, where a changing magnetic field induces an electromotive force (EMF) in the loop of wire.
Correct Answer: A — Electromagnetic induction
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Q. A loop of wire is placed in a changing magnetic field. What phenomenon occurs? (2021)
A.
Electromagnetic induction
B.
Magnetic resonance
C.
Electrolysis
D.
Magnetic levitation
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Solution
When a loop of wire is placed in a changing magnetic field, electromagnetic induction occurs, generating an electromotive force (EMF) in the loop.
Correct Answer: A — Electromagnetic induction
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Q. A loop of wire is placed in a uniform magnetic field. If the angle between the field and the normal to the loop is 60 degrees, what is the effective magnetic flux?
A.
0.5 B A
B.
0.866 B A
C.
0.866 B A²
D.
B A
Show solution
Solution
Effective magnetic flux (Φ) = B * A * cos(θ) = B * A * cos(60°) = 0.5 B A.
Correct Answer: B — 0.866 B A
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