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A liquid has a surface tension of 0.03 N/m. What is the pressure difference acro
A liquid has a surface tension of 0.03 N/m. What is the pressure difference across a curved surface of radius 0.1 m?
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Practice Questions
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Q1
A liquid has a surface tension of 0.03 N/m. What is the pressure difference across a curved surface of radius 0.1 m?
0.15 Pa
0.3 Pa
0.6 Pa
0.9 Pa
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Using the formula ΔP = 2γ/r, ΔP = 2 × 0.03 N/m / 0.1 m = 0.6 Pa.
Questions & Step-by-step Solutions
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Q
Q: A liquid has a surface tension of 0.03 N/m. What is the pressure difference across a curved surface of radius 0.1 m?
Solution:
Using the formula ΔP = 2γ/r, ΔP = 2 × 0.03 N/m / 0.1 m = 0.6 Pa.
Steps: 6
Show Steps
Step 1: Identify the given values. The surface tension (γ) is 0.03 N/m and the radius (r) is 0.1 m.
Step 2: Write down the formula for pressure difference (ΔP) across a curved surface: ΔP = 2γ/r.
Step 3: Substitute the values into the formula: ΔP = 2 × 0.03 N/m / 0.1 m.
Step 4: Calculate the numerator: 2 × 0.03 N/m = 0.06 N/m.
Step 5: Divide the result by the radius: 0.06 N/m ÷ 0.1 m = 0.6 Pa.
Step 6: Conclude that the pressure difference across the curved surface is 0.6 Pa.
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