Using Ohm's Law, I = V/R = 24V / 6Ω = 4A.

Equivalent resistance R_eq = 1/(1/5 + 1/5) = 2.5Ω. Total current I = V/R_eq = 10V/2.5Ω = 4A.

Total resistance R = R1 + R2 = 5Ω + 5Ω = 10Ω. Using Ohm's law, I = V/R = 10V/10Ω = 1A.

Using Ohm's law, I = V/R = 9V / 3Ω = 3A.

According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving. Here, 5A = 3A + 2A.

Equivalent resistance R_eq = 1/(1/5 + 1/5) = 2.5 ohms. Total current I = V/R_eq = 10V / 2.5Ω = 4 A.

Using Ohm's law, I = V/R, we have I = 12V / 3 ohms = 4 A.

Total resistance R_total = 4 + 4 + 4 = 12 ohms. Current I = V/R_total = 12V / 12 ohms = 1A.

Total resistance R_eq = 1 / (1/R1 + 1/R2 + 1/R3) = 1 / (1/4 + 1/4 + 1/4) = 1.33Ω. Current I = V / R_eq = 12V / 1.33Ω ≈ 9A.

Total resistance R = R1 + R2 = 4 + 4 = 8 ohms. Current I = V/R = 12V / 8 ohms = 1.5 A.

Total resistance R = 6 + 6 = 12Ω. Current I = V/R = 12V/12Ω = 1A.

Total resistance R = 5Ω + 5Ω = 10Ω; I = V/R = 15V / 10Ω = 1.5A.

Total resistance R = R1 + R2 + R3 = 2Ω + 4Ω + 6Ω = 12Ω. Using Ohm's law, I = V/R = 24V / 12Ω = 2A.

Using Ohm's law, I = V/R = 9V/3Ω = 3A.

Total resistance R = 1/(1/3 + 1/3) = 1.5Ω; I = V/R = 9V/1.5Ω = 6A.

Total resistance R = 3Ω + 3Ω = 6Ω. Current I = V/R = 9V/6Ω = 1.5A.

Z = √(R² + Xl²) = √(20² + 30²) = √(400 + 900) = √1300 = 36.06 ohms. I = V/Z = 240/36.06 = 6.66 A.

In a parallel circuit, the total current is the sum of the currents in each branch: I_total = I1 + I2 = 2 A + 3 A = 5 A.

In parallel circuits, the total current is the sum of the currents in each branch: 3A + 5A = 8A.

In a parallel circuit, the total current (I_total) is the sum of the currents in each branch: I_total = 3A + 5A = 8A.

Total current in parallel = I1 + I2 = 5A + 3A = 8A.

Total impedance Z = √(R² + (ωL)²) = √(10² + (2π(50)(20))²). Calculate to find current.

The total electric flux through a closed surface is given by Φ = Q_enc/ε₀, where Q_enc is the enclosed charge.

The energy stored in an inductor is given by U = 0.5LI^2.

At maximum displacement, the total mechanical energy of a simple harmonic oscillator is at its maximum, as all energy is potential.

At the highest point of a projectile's trajectory, the kinetic energy is minimum (zero at the peak) and potential energy is maximum, thus total mechanical energy is maximum potential energy.

1 mole of CO2 contains 1 carbon atom and 2 oxygen atoms, totaling 3 atoms.

C2H5OH has 2 carbon, 6 hydrogen, and 1 oxygen atom, totaling 7 atoms.

C4H10 has 4 carbon atoms and 10 hydrogen atoms, totaling 14 atoms.

The sum of the angles in any triangle is always 180 degrees.