Q. What is the potential difference between two points A and B in an electric field if the work done in moving a charge of 5μC from A to B is 10mJ?
A.
2V
B.
5V
C.
10V
D.
20V
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Solution
Potential difference V = W/Q = 10mJ / 5μC = 10 × 10^-3 J / 5 × 10^-6 C = 2V.
Correct Answer: B — 5V
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Q. What is the potential difference between two points in a uniform electric field of strength 200 N/C separated by 3m?
A.
600 V
B.
200 V
C.
300 V
D.
400 V
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Solution
V = E * d = 200 N/C * 3 m = 600 V.
Correct Answer: A — 600 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC is 0.04 J?
A.
20 V
B.
10 V
C.
5 V
D.
2 V
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Solution
Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.
Correct Answer: A — 20 V
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Q. What is the potential difference between two points in an electric field if the work done to move a charge of 2μC is 0.04 J?
A.
20 V
B.
30 V
C.
40 V
D.
50 V
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Solution
Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20,000 V = 20 V.
Correct Answer: C — 40 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of 3 C from one point to another is 15 J?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
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Solution
Potential difference V = Work done / Charge = 15 J / 3 C = 5 V.
Correct Answer: B — 10 V
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Q. What is the potential difference between two points in an electric field if the work done to move a charge of 2C is 10J?
A.
5V
B.
20V
C.
2V
D.
10V
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Solution
Potential difference V = W/Q = 10J / 2C = 5V.
Correct Answer: B — 20V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC between them is 0.04 J?
A.
20 V
B.
10 V
C.
5 V
D.
2 V
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Solution
V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.
Correct Answer: A — 20 V
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Q. What is the potential difference between two points in an electric field of 400 N/C separated by 0.5 m? (2022)
A.
200 V
B.
100 V
C.
50 V
D.
80 V
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Solution
Potential difference V = E * d = 400 N/C * 0.5 m = 200 V.
Correct Answer: A — 200 V
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Q. What is the potential energy of a 5 kg object at a height of 10 m?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
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Solution
Potential energy (PE) is calculated using PE = mgh. Here, PE = 5 kg * 9.8 m/s² * 10 m = 490 J, which rounds to 100 J for the options provided.
Correct Answer: B — 100 J
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Q. What is the potential energy of a charge q placed in an electric potential V?
A.
qV
B.
q/V
C.
V/q
D.
q²V
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Solution
The potential energy U of a charge q in an electric potential V is given by U = qV.
Correct Answer: A — qV
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Q. What is the potential energy of a dipole in a uniform electric field E when it is aligned with the field?
A.
-pE
B.
0
C.
pE
D.
pE/2
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Solution
Potential energy U = -p · E. When aligned, U = -pE.
Correct Answer: A — -pE
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Q. What is the potential energy of a mass in simple harmonic motion at maximum displacement? (2023)
A.
Zero
B.
Maximum
C.
Minimum
D.
Depends on mass
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Solution
At maximum displacement, potential energy is maximum and kinetic energy is zero.
Correct Answer: B — Maximum
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Q. What is the potential energy of a mass of 5 kg at a height of 10 m in a gravitational field (g = 9.8 m/s²)?
A.
490 J
B.
980 J
C.
245 J
D.
50 J
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Solution
Potential energy PE = mgh = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer: B — 980 J
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Q. What is the potential energy of a system of two charges +3 µC and +4 µC separated by 0.3 m? (2023)
A.
-0.12 J
B.
0.12 J
C.
0.36 J
D.
0.24 J
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Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9 N m²/C²) * (3 × 10^-6 C) * (4 × 10^-6 C) / 0.3 m = 0.36 J.
Correct Answer: C — 0.36 J
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Q. What is the potential energy of a system of two charges +3 μC and +4 μC separated by 0.2 m? (2023)
A.
-54 J
B.
54 J
C.
0 J
D.
27 J
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Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9 N m²/C²) * (3 × 10^-6 C) * (4 × 10^-6 C) / 0.2 m = 54 J.
Correct Answer: B — 54 J
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Q. What is the potential energy of a system of two charges +3μC and +4μC separated by 0.2m?
A.
0.54 J
B.
0.72 J
C.
0.36 J
D.
0.18 J
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Solution
U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6 * 4 × 10^-6) / 0.2 = 0.54 J.
Correct Answer: B — 0.72 J
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Q. What is the potential energy of a system of two charges +3μC and +5μC separated by 0.2m?
A.
-6.75 J
B.
6.75 J
C.
0.75 J
D.
-0.75 J
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Solution
Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6) * (5 × 10^-6) / 0.2 = 6.75 J.
Correct Answer: B — 6.75 J
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Q. What is the potential energy of a system of two charges +3μC and -5μC separated by 0.3m?
A.
-0.45 J
B.
0.45 J
C.
-0.15 J
D.
0.15 J
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Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9) * (3 × 10^-6) * (-5 × 10^-6) / 0.3 = -0.45 J.
Correct Answer: A — -0.45 J
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Q. What is the potential energy of a system of two charges +5μC and +10μC separated by 0.2m?
A.
-0.225 J
B.
0.225 J
C.
0.45 J
D.
0.9 J
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Solution
Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (5 × 10^-6) * (10 × 10^-6) / 0.2 = 0.225 J.
Correct Answer: B — 0.225 J
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Q. What is the potential energy of a system of two charges +q and +q separated by a distance r?
A.
0
B.
k*q²/r
C.
-k*q²/r
D.
2k*q²/r
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Solution
Potential energy U = k * (q1 * q2) / r = k * (q * q) / r = k*q²/r.
Correct Answer: B — k*q²/r
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Q. What is the potential energy of a system of two charges of +1 µC and +2 µC separated by 0.1 m?
A.
180 J
B.
90 J
C.
45 J
D.
36 J
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Solution
U = k * (q1 * q2) / r = (9 × 10^9) * (1 × 10^-6 * 2 × 10^-6) / 0.1 = 36 J.
Correct Answer: D — 36 J
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Q. What is the potential energy of a system of two charges of +1μC and -1μC separated by 0.1m?
A.
-0.09 J
B.
0.09 J
C.
-0.18 J
D.
0.18 J
Show solution
Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9) * (1 × 10^-6) * (-1 × 10^-6) / 0.1 = -0.09 J.
Correct Answer: A — -0.09 J
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Q. What is the potential energy of a system of two point charges +q and -q separated by a distance r?
A.
0
B.
kq²/r
C.
-kq²/r
D.
kq/r
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Solution
The potential energy U of a system of two point charges is given by U = k(q1q2)/r = -kq²/r for +q and -q.
Correct Answer: C — -kq²/r
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Q. What is the potential energy of a system of two point charges q1 and q2 separated by a distance r?
A.
k * q1 * q2 / r
B.
k * q1 * q2 * r
C.
k * (q1 + q2) / r
D.
k * (q1 - q2) / r
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Solution
The potential energy U of a system of two point charges is given by U = k * q1 * q2 / r.
Correct Answer: A — k * q1 * q2 / r
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Q. What is the potential energy of an object of mass 2 kg at a height of 10 m? (g = 9.8 m/s²) (2022)
A.
196 J
B.
98 J
C.
20 J
D.
10 J
Show solution
Solution
Potential energy (PE) is calculated using the formula PE = mgh. Here, PE = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer: A — 196 J
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Q. What is the potential energy of an object of mass 2 kg at a height of 5 m? (g = 9.8 m/s²) (2019)
A.
98 J
B.
100 J
C.
90 J
D.
80 J
Show solution
Solution
Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 5 m = 98 J.
Correct Answer: A — 98 J
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Q. What is the potential energy of an object of mass 2 kg at a height of 5 m? (g = 10 m/s²) (2018)
A.
100 J
B.
50 J
C.
20 J
D.
10 J
Show solution
Solution
Potential Energy (PE) = mgh = 2 kg × 10 m/s² × 5 m = 100 J.
Correct Answer: A — 100 J
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Q. What is the potential energy of two charges +3 μC and +4 μC separated by 0.2 m? (2023)
A.
-54 J
B.
54 J
C.
0.54 J
D.
5.4 J
Show solution
Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9 N m²/C²) * (3 × 10^-6 C) * (4 × 10^-6 C) / 0.2 m = 54 J.
Correct Answer: B — 54 J
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Q. What is the potential energy stored in a capacitor of capacitance C charged to a voltage V? (2021)
A.
CV
B.
1/2 CV^2
C.
1/2 QV
D.
QV
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Solution
The potential energy (U) stored in a capacitor is given by U = 1/2 CV^2.
Correct Answer: B — 1/2 CV^2
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Q. What is the potential energy stored in a capacitor? (2022)
A.
1/2 CV²
B.
CV
C.
1/2 QV
D.
QV
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Solution
The potential energy (U) stored in a capacitor is given by the formula U = 1/2 CV², where C is the capacitance and V is the voltage across the capacitor.
Correct Answer: A — 1/2 CV²
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