(1 + i)(1 - i) = 1^2 - i^2 = 1 - (-1) = 2.

(1 + i)(1 - i) = 1^2 - i^2 = 1 - (-1) = 2.

(2 + 3i)(4 - i) = 8 - 2i + 12i - 3i^2 = 8 + 10i + 3 = 11 + 10i.

z1 * z2 = (1 + i)(1 - i) = 1 - i^2 = 1 + 1 = 2.

Decarboxylation of sodium acetate produces methane.

Dehydration of 2-butanol leads to the formation of butene as the major product.

Dehydration of ethanol leads to the formation of ethylene (ethene) by elimination of water.

The reaction between acetic acid and ethanol produces ethyl acetate.

The hydration of ethene in the presence of sulfuric acid produces ethanol.

The hydrolysis of 1-chloropropane in the presence of water yields propan-1-ol as the main product.

Hydrolysis of ethyl acetate in acid gives ethanol and acetic acid.

2-Propanol oxidizes to form Acetone, which is a ketone.

The oxidation of a primary alcohol results in the formation of an aldehyde.

The oxidation of a primary alcohol first produces an aldehyde, which can further oxidize to a carboxylic acid.

The oxidation of a primary alcohol results in the formation of an aldehyde.

The oxidation of an aldehyde results in the formation of a carboxylic acid.

Ethanol oxidizes to acetic acid when reacted with an oxidizing agent.

Propan-2-ol oxidizes to form Acetone (CH3COCH3).

Ozonolysis of 1-pentene yields pentanal as one of the products.

The reaction of 1-bromobutane with sodium ethoxide leads to the formation of butyl ethyl ether through an SN2 mechanism.

The reaction of 1-bromobutane with sodium hydroxide in ethanol leads to the formation of butanol through nucleophilic substitution.

The reaction of 1-bromopropane with sodium ethoxide leads to the formation of ethyl propyl ether through nucleophilic substitution.

1-bromopropane reacts with sodium hydroxide in ethanol to form 1-Propanol via nucleophilic substitution.

The reaction of 1-butyne with HBr leads to the formation of 2-bromobutane due to Markovnikov's rule.

1-cyanobutane is formed through nucleophilic substitution where the cyanide ion acts as a nucleophile.

The reaction between a carboxylic acid and an alcohol produces an ester.

The reaction produces sodium acetate, carbon dioxide, and water, making 'All of the above' the correct answer.

The product is Iodoform, formed from the reaction of acetone with iodine in the presence of a base.

The reaction produces Ethylamine as ammonia acts as a nucleophile and replaces the bromine atom.

The reaction between an alcohol and a carboxylic acid produces an ester through a process called esterification.