Major Competitive Exams

Civil Services Defence Exams Engineering & Architecture Admissions Government Jobs Management Admissions Undergraduate

Q. A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. How fast does the cyclist appear to be moving to the pedestrian?

A. 10 m/s
B. 15 m/s
C. 20 m/s
D. 5 m/s

Solution

Relative speed = Speed of cyclist - Speed of pedestrian = 15 m/s - 5 m/s = 10 m/s.

Correct Answer: A — 10 m/s

Learn More →

Q. A cyclist is moving at 15 m/s and a pedestrian is walking at 5 m/s in the same direction. What is the relative speed of the pedestrian with respect to the cyclist?

A. 10 m/s
B. 5 m/s
C. 20 m/s
D. 15 m/s

Solution

Relative speed = Speed of pedestrian - Speed of cyclist = 5 m/s - 15 m/s = -10 m/s (10 m/s behind).

Correct Answer: A — 10 m/s

Learn More →

Q. A cyclist is moving at 15 m/s and a pedestrian is walking at 5 m/s in the same direction. What is the speed of the cyclist relative to the pedestrian?

A. 10 m/s
B. 15 m/s
C. 5 m/s
D. 20 m/s

Solution

Relative speed = Speed of cyclist - Speed of pedestrian = 15 m/s - 5 m/s = 10 m/s.

Correct Answer: A — 10 m/s

Learn More →

Q. A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?

A. 10 m/s
B. 15 m/s
C. 20 m/s
D. 5 m/s

Solution

Relative speed = Speed of cyclist - Speed of observer = 15 m/s - 5 m/s = 10 m/s.

Correct Answer: A — 10 m/s

Learn More →

Q. A cyclist is moving at 15 m/s towards the east while a car is moving at 25 m/s towards the west. What is the relative speed of the cyclist with respect to the car?

A. 10 m/s
B. 15 m/s
C. 40 m/s
D. 25 m/s

Solution

Relative speed = Speed of cyclist + Speed of car = 15 m/s + 25 m/s = 40 m/s.

Correct Answer: C — 40 m/s

Learn More →

Q. A cyclist is moving at 15 m/s while a car is moving at 25 m/s in the same direction. What is the speed of the cyclist relative to the car?

A. 10 m/s
B. 15 m/s
C. 25 m/s
D. 40 m/s

Solution

Relative speed = Speed of car - Speed of cyclist = 25 m/s - 15 m/s = 10 m/s.

Correct Answer: A — 10 m/s

Learn More →

Q. A cyclist is moving at a speed of 10 m/s. If he doubles his speed, how much more kinetic energy will he have? (2023)

A. 4 times
B. 2 times
C. 3 times
D. 1.5 times

Solution

Kinetic Energy is proportional to the square of the speed. If speed is doubled, KE increases by a factor of 2^2 = 4.

Correct Answer: A — 4 times

Learn More →

Q. A cyclist is moving at a speed of 15 km/h. If a car is moving in the same direction at 30 km/h, what is the relative speed of the car with respect to the cyclist?

A. 15 km/h
B. 30 km/h
C. 45 km/h
D. 0 km/h

Solution

Relative speed = speed of car - speed of cyclist = 30 - 15 = 15 km/h.

Correct Answer: A — 15 km/h

Learn More →

Q. A cyclist is moving at a speed of 15 m/s. If the mass of the cyclist and the bicycle is 75 kg, what is the total kinetic energy?

A. 800 J
B. 900 J
C. 1000 J
D. 1200 J

Solution

KE = 0.5 × m × v² = 0.5 × 75 kg × (15 m/s)² = 0.5 × 75 × 225 = 8437.5 J.

Correct Answer: C — 1000 J

Learn More →

Q. A cyclist is moving at a speed of 15 m/s. If the total mass of the cyclist and the bicycle is 75 kg, what is the kinetic energy?

A. 843.75 J
B. 562.5 J
C. 1687.5 J
D. 1125 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 75 kg × (15 m/s)² = 0.5 × 75 × 225 = 8437.5 J.

Correct Answer: A — 843.75 J

Learn More →

Q. A cyclist is moving in a circular path of radius 10 m at a speed of 5 m/s. What is the angle of banking required to prevent slipping?

A. 30°
B. 45°
C. 60°
D. 90°

Solution

tan(θ) = v²/(rg) = (5²)/(10*9.8) = 0.25. θ = tan⁻¹(0.25) ≈ 14°.

Correct Answer: A — 30°

Learn More →

Q. A cyclist is moving in a circular path of radius 15 m with a speed of 5 m/s. What is the angular velocity of the cyclist?

A. 0.2 rad/s
B. 0.5 rad/s
C. 1 rad/s
D. 2 rad/s

Solution

Angular velocity (ω) = v/r = 5 m/s / 15 m = 1/3 rad/s.

Correct Answer: B — 0.5 rad/s

Learn More →

Q. A cyclist is moving in a circular path of radius 15 m with a speed of 6 m/s. What is the angular velocity of the cyclist?

A. 0.4 rad/s
B. 0.6 rad/s
C. 0.8 rad/s
D. 1.0 rad/s

Solution

Angular velocity (ω) = v/r = 6 m/s / 15 m = 0.4 rad/s.

Correct Answer: B — 0.6 rad/s

Learn More →

Q. A cyclist is moving in a circular track of radius 30 m with a speed of 15 m/s. What is the net force acting on the cyclist if the mass of the cyclist is 60 kg?

A. 180 N
B. 120 N
C. 90 N
D. 60 N

Solution

Centripetal force F = mv²/r = 60 kg * (15 m/s)² / 30 m = 180 N.

Correct Answer: A — 180 N

Learn More →

Q. A cyclist is moving in a circular track of radius 30 m. If he completes one round in 12 seconds, what is his average speed?

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Circumference = 2πr = 2π(30) = 60π m. Average speed = distance/time = 60π m / 12 s = 5 m/s.

Correct Answer: B — 10 m/s

Learn More →

Q. A cyclist is moving in a circular track of radius 30 m. If the cyclist completes one round in 12 seconds, what is the angular velocity of the cyclist?

A. π/6 rad/s
B. π/3 rad/s
C. 2π/6 rad/s
D. 2π/3 rad/s

Solution

Angular velocity (ω) = 2π/T = 2π/12 = π/6 rad/s.

Correct Answer: B — π/3 rad/s

Learn More →

Q. A cyclist is moving in a circular track of radius 30 m. If the cyclist completes one round in 12 seconds, what is the average speed of the cyclist?

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Circumference = 2πr = 2π(30 m). Average speed = distance/time = (2π(30 m))/12 s ≈ 5 m/s.

Correct Answer: B — 10 m/s

Learn More →

Q. A cyclist is moving up a hill and gains 3000 J of potential energy. If the mass of the cyclist and the bicycle is 75 kg, what is the height of the hill? (g = 9.8 m/s²)

A. 4.08 m
B. 3.06 m
C. 2.04 m
D. 1.5 m

Solution

Height (h) = PE / (mg) = 3000 J / (75 kg * 9.8 m/s²) = 4.08 m.

Correct Answer: A — 4.08 m

Learn More →

Q. A cyclist is moving with a speed of 10 m/s. If he doubles his speed, how much more kinetic energy will he have? (2023)

A. 4 times
B. 2 times
C. 3 times
D. 1.5 times

Solution

Kinetic Energy is proportional to the square of the speed. If speed is doubled, KE increases by a factor of 2^2 = 4.

Correct Answer: A — 4 times

Learn More →

Q. A cyclist is moving with a speed of 15 m/s. If the mass of the cyclist and the bicycle is 75 kg, what is the kinetic energy? (2022)

A. 8437.5 J
B. 1687.5 J
C. 5625 J
D. 2250 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 75 kg * (15 m/s)^2 = 8437.5 J.

Correct Answer: A — 8437.5 J

Learn More →

Q. A cyclist is negotiating a circular track of radius 30 m. If the cyclist's speed is 15 m/s, what is the net force acting on the cyclist towards the center of the track?

A. 50 N
B. 75 N
C. 100 N
D. 125 N

Solution

Centripetal force (F_c) = mv²/r. Assuming mass m = 100 kg, F_c = (100 kg)(15 m/s)² / (30 m) = 75 N.

Correct Answer: C — 100 N

Learn More →

Q. A cyclist is negotiating a circular track of radius 30 m. If the cyclist's speed is 15 m/s, what is the net force acting on the cyclist if the mass of the cyclist is 60 kg?

A. 180 N
B. 120 N
C. 90 N
D. 60 N

Solution

Centripetal force F_c = mv²/r = 60 kg * (15 m/s)² / 30 m = 180 N.

Correct Answer: A — 180 N

Learn More →

Q. A cyclist is negotiating a circular turn of radius 30 m at a speed of 15 m/s. What is the minimum coefficient of friction required to prevent slipping?

A. 0.25
B. 0.5
C. 0.75
D. 1

Solution

Frictional force = m * a_c; μmg = mv²/r; μ = v²/(rg) = (15²)/(30*9.8) = 0.25.

Correct Answer: B — 0.5

Learn More →

Q. A cyclist is pedaling at a constant speed and exerts a power of 200 W. If the cyclist increases their power output to 400 W, what happens to their speed assuming no other forces act?

A. Speed remains the same
B. Speed doubles
C. Speed increases by 41%
D. Speed increases by 100%

Solution

Power is proportional to the cube of the speed in cycling. If power doubles, speed increases by a factor of (2)^(1/3) which is approximately 1.26, or about a 41% increase.

Correct Answer: C — Speed increases by 41%

Learn More →

Q. A cyclist of mass 70 kg accelerates at 2 m/s². What is the force exerted by the cyclist on the ground? (2021)

A. 70 N
B. 140 N
C. 210 N
D. 280 N

Solution

Using F = ma, F = 70 kg * 2 m/s² = 140 N.

Correct Answer: B — 140 N

Learn More →

Q. A cyclist travels 100 m in 5 seconds. What is the average speed of the cyclist?

A. 10 m/s
B. 15 m/s
C. 20 m/s
D. 25 m/s

Solution

Average speed = total distance / total time = 100 m / 5 s = 20 m/s.

Correct Answer: A — 10 m/s

Learn More →

Q. A cyclist travels 100 m north and then 100 m east. What is the magnitude of the displacement from the starting point?

A. 100 m
B. 141.4 m
C. 200 m
D. 50 m

Solution

Displacement = √(100² + 100²) = √20000 = 141.4 m.

Correct Answer: B — 141.4 m

Learn More →

Q. A cyclist travels 100 m north and then 100 m east. What is the magnitude of the displacement? (2000)

A. 100 m
B. 141.42 m
C. 200 m
D. 250 m

Solution

Displacement = √(100² + 100²) = √20000 = 141.42 m.

Correct Answer: B — 141.42 m

Learn More →

Q. A cyclist travels 15 km in 30 minutes. What is the speed of the cyclist in km/h? (2019)

A. 25 km/h
B. 30 km/h
C. 35 km/h
D. 40 km/h

Solution

Speed = Distance / Time = 15 km / 0.5 hours = 30 km/h.

Correct Answer: A — 25 km/h

Learn More →

Q. A cyclist travels at a speed of 10 m/s for 15 seconds. What distance does he cover? (2022)

A. 100 m
B. 150 m
C. 200 m
D. 250 m

Solution

Distance = speed * time = 10 m/s * 15 s = 150 m.

Correct Answer: B — 150 m

Learn More →

Showing 871 to 900 of 19963 (666 Pages)

Major Competitive Exams

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?