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Q. A circuit has a 24V battery and a total resistance of 12Ω. What is the current flowing through the circuit? (2020)

A. 2A
B. 4A
C. 6A
D. 8A

Solution

Using Ohm's law, I = V/R = 24V / 12Ω = 2A.

Correct Answer: B — 4A

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Q. A circuit has a 24V battery and a total resistance of 6Ω. What is the current flowing through the circuit? (2020)

A. 4A
B. 6A
C. 8A
D. 2A

Solution

Using Ohm's law, I = V/R = 24V / 6Ω = 4A.

Correct Answer: A — 4A

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Q. A circuit has a 9V battery and a 3Ω resistor. What is the voltage drop across the resistor? (2022)

A. 3V
B. 6V
C. 9V
D. 12V

Solution

The voltage drop across the resistor is equal to the battery voltage in a simple circuit: 9V.

Correct Answer: C — 9V

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Q. A circuit has a 9V battery and two resistors of 3Ω and 6Ω in series. What is the current flowing through the circuit? (2022)

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V / 9Ω = 1A.

Correct Answer: B — 2A

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Q. A circuit has a current of 2A and a resistance of 6Ω. What is the voltage across the circuit? (2020)

A. 6V
B. 12V
C. 8V
D. 10V

Solution

Using Ohm's Law, V = I * R = 2A * 6Ω = 12V.

Correct Answer: B — 12V

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Q. A circuit has a current of 3A and a resistance of 6Ω. What is the voltage across the circuit? (2019)

A. 9V
B. 18V
C. 3V
D. 6V

Solution

Using Ohm's Law, V = I * R = 3A * 6Ω = 18V.

Correct Answer: A — 9V

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Q. A circuit has a current of 5A and a resistance of 10Ω. What is the power consumed in the circuit? (2020)

A. 25W
B. 50W
C. 75W
D. 100W

Solution

Power (P) can be calculated using P = I^2 * R = (5A)^2 * 10Ω = 25 * 10 = 250W.

Correct Answer: B — 50W

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Q. A circuit has a current of 5A and a resistance of 2Ω. What is the power consumed in the circuit? (2020)

A. 10W
B. 25W
C. 50W
D. 100W

Solution

Power (P) can be calculated using the formula P = I^2 * R = (5A)^2 * 2Ω = 25W.

Correct Answer: B — 25W

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Q. A circuit has a resistance of 10 Ω and a reactance of 10 Ω. What is the impedance of the circuit? (2020)

A. 10 Ω
B. 14.14 Ω
C. 20 Ω
D. 5 Ω

Solution

The impedance Z = √(R² + X²) = √(10² + 10²) = √200 = 14.14 Ω.

Correct Answer: B — 14.14 Ω

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Q. A circuit has a resistance of 10Ω and a reactance of 5Ω. What is the impedance of the circuit? (2021)

A. 5Ω
B. 10Ω
C. √125Ω
D. √(10² + 5²)Ω

Solution

The impedance Z is calculated as Z = √(R² + X²) = √(10² + 5²) = √125Ω.

Correct Answer: D — √(10² + 5²)Ω

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Q. A circuit has a resistance of 10Ω and a reactance of 5Ω. What is the impedance? (2020)

A. 5Ω
B. 10Ω
C. √125Ω
D. √(10² + 5²)Ω

Solution

The impedance Z = √(R² + X²) = √(10² + 5²) = √125Ω.

Correct Answer: D — √(10² + 5²)Ω

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Q. A circuit has a resistance of 4 ohms and a current of 2 A. What is the voltage across the circuit?

A. 2 V
B. 4 V
C. 6 V
D. 8 V

Solution

Using Ohm's Law, V = I × R. Here, I = 2 A and R = 4 ohms. Thus, V = 2 × 4 = 8 V.

Correct Answer: D — 8 V

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Q. A circuit has a total resistance of 10 ohms and a current of 5 A. What is the total voltage in the circuit?

A. 50 V
B. 10 V
C. 5 V
D. 2 V

Solution

Using Ohm's law, V = I * R = 5 A * 10 ohms = 50 V.

Correct Answer: A — 50 V

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Q. A circuit has a total resistance of 12Ω and a current of 1.5A. What is the voltage across the circuit? (2021)

A. 18V
B. 12V
C. 15V
D. 9V

Solution

Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.

Correct Answer: A — 18V

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Q. A circuit has a total resistance of 12Ω and a current of 2A. What is the voltage across the circuit? (2021)

A. 24V
B. 12V
C. 6V
D. 48V

Solution

Using Ohm's law (V = IR), V = 2A * 12Ω = 24V.

Correct Answer: A — 24V

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Q. A circuit has a total resistance of 20Ω and a current of 2A flowing through it. What is the voltage across the circuit? (2023)

A. 30V
B. 40V
C. 20V
D. 10V

Solution

Using Ohm's law, V = I * R = 2A * 20Ω = 40V.

Correct Answer: B — 40V

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Q. A circuit has a total resistance of 5Ω and a current of 2A. What is the voltage across the circuit? (2023)

A. 10V
B. 5V
C. 2V
D. 1V

Solution

Using Ohm's law, V = I * R = 2A * 5Ω = 10V.

Correct Answer: A — 10V

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Q. A circuit has a total resistance of 8Ω and a current of 4A flowing through it. What is the voltage across the circuit? (2021)

A. 32V
B. 16V
C. 8V
D. 4V

Solution

Using Ohm's law, V = I * R = 4A * 8Ω = 32V.

Correct Answer: A — 32V

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Q. A circuit has a total resistance of 8Ω and a current of 4A. What is the voltage across the circuit? (2021)

A. 32V
B. 16V
C. 8V
D. 4V

Solution

Using Ohm's law, V = I * R = 4A * 8Ω = 32V.

Correct Answer: A — 32V

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Q. A circuit has a total voltage of 24V and a total current of 4A. What is the total resistance in the circuit? (2021)

A. 6Ω
B. 8Ω
C. 4Ω
D. 12Ω

Solution

Using Ohm's law, R = V/I = 24V / 4A = 6Ω.

Correct Answer: B — 8Ω

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Q. A circuit has a total voltage of 24V and a total resistance of 8Ω. What is the total current in the circuit? (2020)

A. 3A
B. 2A
C. 4A
D. 6A

Solution

Using Ohm's law, I = V/R = 24V / 8Ω = 3A.

Correct Answer: A — 3A

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Q. A circuit has a voltage of 12 volts and a resistance of 4 ohms. What is the current flowing through the circuit?

A. 3 A
B. 4 A
C. 2 A
D. 1 A

Solution

Using Ohm's Law, I = V / R = 12 V / 4 Ω = 3 A.

Correct Answer: A — 3 A

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Q. A circuit has a voltage of 12V and a resistance of 4Ω. What is the current flowing through the circuit?

A. 3A
B. 4A
C. 12A
D. 48A

Solution

Using Ohm's Law, I = V/R = 12V / 4Ω = 3A.

Correct Answer: A — 3A

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Q. A circuit has a voltage of 24 volts and a current of 6 amperes. What is the resistance?

A. 4 Ω
B. 6 Ω
C. 8 Ω
D. 12 Ω

Solution

Using Ohm's Law, R = V / I = 24 V / 6 A = 4 Ω.

Correct Answer: A — 4 Ω

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Q. A circular loop is placed in a uniform magnetic field. If the loop is rotated about its diameter, what happens to the induced EMF?

A. It increases
B. It decreases
C. It remains constant
D. It becomes zero

Solution

When the loop is rotated about its diameter, the angle between the magnetic field and the normal to the loop changes, but the magnetic flux remains constant. Therefore, the induced EMF becomes zero as there is no change in magnetic flux.

Correct Answer: D — It becomes zero

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Q. A circular loop of radius R carries a current I. What is the magnetic field at the center of the loop?

A. μ₀I/(2R)
B. μ₀I/R
C. μ₀I/(4R)
D. μ₀I/(8R)

Solution

The magnetic field at the center of a circular loop carrying current I is given by the formula B = (μ₀I)/(2R), where μ₀ is the permeability of free space.

Correct Answer: B — μ₀I/R

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Q. A circular loop of radius R carries a current I. What is the magnetic field at the center of the loop according to the Biot-Savart Law?

A. B = (μ₀I)/(2R)
B. B = (μ₀I)/(4R)
C. B = (μ₀I)/(R)
D. B = (μ₀I)/(πR)

Solution

The magnetic field at the center of a circular loop of radius R carrying current I is given by B = (μ₀I)/(2R).

Correct Answer: A — B = (μ₀I)/(2R)

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Q. A circular loop of radius r is placed in a uniform magnetic field B. If the magnetic field is perpendicular to the plane of the loop, what is the magnetic flux through the loop?

A. 0
B. πr²B
C. 2πrB
D. B/r

Solution

The magnetic flux Φ through a surface is given by Φ = B * A, where A is the area. For a circular loop, A = πr², so Φ = B * πr².

Correct Answer: B — πr²B

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Q. A circular loop of wire carries a current. What is the direction of the magnetic field at the center of the loop?

A. Out of the plane
B. Into the plane
C. Clockwise
D. Counterclockwise

Solution

Using the right-hand rule, the magnetic field at the center of a current-carrying circular loop is directed out of the plane of the loop.

Correct Answer: A — Out of the plane

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Q. A circular loop of wire carries a current. What is the shape of the magnetic field lines around the loop? (2021)

A. Straight lines
B. Concentric circles
C. Ellipses
D. Spirals

Solution

The magnetic field lines around a circular loop of wire carrying current are in the form of concentric circles.

Correct Answer: B — Concentric circles

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Major Competitive Exams

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