The average power (P) consumed in an AC circuit is given by P = VI cos(φ), where φ is the phase angle between voltage and current.

In an inductor, the current lags behind the voltage by 90 degrees.

In an inductive circuit, the current lags behind the voltage by 90 degrees.

In an inductor, the current lags the voltage by 90 degrees.

In an inductive circuit, the current lags the voltage by 90 degrees.

The peak voltage in the equation V(t) = V0 sin(ωt) is V0.

The peak voltage V0 is given directly in the equation as 10V.

In a purely inductive AC circuit, the current lags the voltage by 90 degrees.

The average power (P) in an AC circuit is given by P = V_rms²/R, where R is the resistance.

Reactance is measured in Ohms, just like resistance.

In an AC generator, the induced EMF is maximum when the coil is positioned at 90 degrees to the magnetic field, as this is when the rate of change of magnetic flux is greatest.

In an adiabatic process, the relationship is given by PV^n = constant, where n is the heat capacity ratio.

In an adiabatic process, as the temperature decreases, the pressure also decreases due to the ideal gas law.

In an adiabatic process, as the temperature decreases, the pressure also decreases due to the ideal gas law.

In an adiabatic process, there is no heat exchange with the surroundings, meaning no heat is absorbed or released.

In an adiabatic process, there is no heat exchange, so the internal energy remains constant for an ideal gas.

Resistance in an electrical circuit is analogous to a narrow pipe that restricts the flow of water.

Let the first term be a and the common difference be d. From the equations a + 2d = 15 and a + 5d = 24, we can solve for d, which gives d = 3.

Let the first term be a and the common difference be d. From the equations a + 3d = 20 and a + 6d = 26, we can solve for a and find it to be 12.

Let the first term be a and the common difference be d. From the given terms, we have a + 4d = 20 and a + 9d = 35. Solving these gives a = 10.

Using the formula for the last term, 48 = 12 + (10-1)d. Solving gives d = 4.

The nth term of an AP is given by a + (n-1)d. Here, a = 5, d = 3, and n = 10. So, the 10th term = 5 + (10-1) * 3 = 5 + 27 = 32.

Using the formula S_n = n/2 * (2a + (n-1)d), we can substitute n = 10 and d = 5 to find a = 20.

Using the formula for the nth term: a_n = a + (n-1)d, we have 45 = 5 + 9d. Solving gives d = 4.

Herbivores are primary consumers as they feed directly on producers (plants).

Plants are primary producers as they convert sunlight into chemical energy through photosynthesis.

Power in an electric circuit is given by P = V * I. Here, P = 12 V * 3 A = 36 W.

Power in an electric circuit is given by P = V^2/R. If V is doubled, P becomes (2V)^2/R = 4V^2/R, which is quadrupled.

In an electrochemical cell, oxidation occurs at the anode.

In an endothermic reaction, the enthalpy of the products is higher than that of the reactants.