The total resistance is 9 ohms. The current is I = V/R = 9V / 9 ohms = 1 A. The voltage drop across the 6 ohm resistor is V = I * R = 1 A * 6 ohms = 6V.

Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V/9Ω = 1A.

Total resistance R_total = 3Ω + 6Ω = 9Ω. Current I = V/R_total = 9V/9Ω = 1A. Voltage across 6Ω = I * R = 1A * 6Ω = 6V.

Using Ohm's Law, R = V/I = 24V / 6A = 4Ω.

In a circuit with an inductor, the current increases gradually due to the inductor's opposition to changes in current.

For resistors in series, R_total = R1 + R2 + R3 = 2 + 3 + 5 = 10 ohms.

Total resistance in series is R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.

An OR gate outputs 1 if at least one input is 1. Since both inputs are 0, the output is 0.

According to Kirchhoff's current law, the total current entering a junction equals the total current leaving it. Therefore, total current = 2 A + 3 A = 5 A.

The current through the shared resistor is the difference of the currents in the loops, so 5 A - 3 A = 2 A.

Using the formula for resistors in parallel, 1/R_eq = 1/4 + 1/6, we find R_eq = 2.4 ohms.

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/12 = 1/3. R_eq = 3Ω. Then, I = V/R = 24V / 3Ω = 8A.

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω. Then, I = V/R = 12V/2Ω = 6A.

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

Total current I = V / Req; Req = 1/(1/6 + 1/3) = 2Ω; I = 12V / 2Ω = 6A.

The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.

Using the formula for resistors in series, R_total = R1 + R2, we have 12 = 4 + R2, thus R2 = 12 - 4 = 8 ohms.

Using the voltage divider rule, V1 = (R1 / (R1 + R2)) * Vtotal = (4 / (4 + 6)) * 12 = 4.8V.

Using the voltage divider rule, V1 = (R1 / (R1 + R2)) * Vtotal = (4 / (4 + 6)) * 12 = 4.8V.

The time constant (τ) of an RC circuit is given by τ = R * C.

When a capacitor is fully charged, the voltage across it is equal to the voltage of the source it was connected to.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which means power quadruples.

Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which is quadrupled.

According to Ohm's law, I = V/R. If R is doubled, I will be halved.

According to Ohm's law, I = V/R. If R is halved, I will double.

Using Ohm's law, R = V/I = 12V / 3A = 4 ohms.

According to Ohm's law, if voltage is doubled and resistance remains constant, current also doubles.