In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?
Practice Questions
1 question
Q1
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?
2A
4A
6A
8A
Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?
Solution: Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.
Steps: 11
Step 1: Identify the resistors in the circuit. We have one resistor of 6Ω and another of 3Ω.
Step 2: Use the formula for total resistance in parallel: 1/Rtotal = 1/R1 + 1/R2.
Step 3: Substitute the values into the formula: 1/Rtotal = 1/6 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
Step 5: Rewrite 1/3 as 2/6, so now we have: 1/Rtotal = 1/6 + 2/6.
Step 6: Add the fractions: 1/Rtotal = 3/6.
Step 7: Simplify the fraction: 1/Rtotal = 1/2.
Step 8: Invert the fraction to find Rtotal: Rtotal = 2Ω.
Step 9: Use Ohm's Law to find the total current: I = V/R.
