Q. If the distance between the plates of a capacitor is halved, what happens to its capacitance?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Capacitance is inversely proportional to the distance between the plates. If the distance is halved, the capacitance doubles.
Correct Answer: A — It doubles
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Q. If the distance between the plates of a capacitor is halved, what happens to the capacitance? (2019)
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
If the distance d is halved, the capacitance C = εA/d will double.
Correct Answer: A — It doubles
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Q. If the distance between the slits in a double-slit experiment is halved, what happens to the angular position of the first-order maximum? (2023)
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
If the slit separation d is halved, the angle θ for the first-order maximum (d sin θ = λ) will increase, effectively doubling the angle.
Correct Answer: A — It doubles
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Q. If the distance between the slits in a double-slit experiment is increased, what happens to the interference pattern?
A.
Fringe width increases
B.
Fringe width decreases
C.
Fringe intensity increases
D.
Fringe intensity decreases
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Solution
Increasing the distance between the slits decreases the fringe width, as fringe width is inversely proportional to the slit separation.
Correct Answer: B — Fringe width decreases
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Q. If the distance between two charges is doubled, how does the electrostatic force between them change?
A.
It doubles
B.
It halves
C.
It quadruples
D.
It reduces to one-fourth
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Solution
According to Coulomb's law, F ∝ 1/r^2. If r is doubled, F becomes F/4.
Correct Answer: D — It reduces to one-fourth
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Q. If the distance between two charges is doubled, how does the force between them change?
A.
It doubles
B.
It halves
C.
It quadruples
D.
It reduces to one-fourth
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Solution
According to Coulomb's law, force is inversely proportional to the square of the distance. If the distance is doubled, the force reduces to one-fourth.
Correct Answer: D — It reduces to one-fourth
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Q. If the distance between two charges is halved, how does the force between them change?
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It halves
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Solution
According to Coulomb's law, the force F between two charges is inversely proportional to the square of the distance. If the distance is halved, the force becomes four times greater.
Correct Answer: B — It quadruples
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Q. If the distance between two charges is halved, what happens to the force between them?
A.
It doubles
B.
It halves
C.
It quadruples
D.
It remains the same
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Solution
According to Coulomb's law, F ∝ 1/r^2; halving the distance increases the force by a factor of 4.
Correct Answer: C — It quadruples
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Q. If the distance between two masses is doubled, how does the gravitational force between them change?
A.
It becomes four times weaker
B.
It becomes twice as strong
C.
It remains the same
D.
It becomes half as strong
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Solution
According to the inverse square law, if the distance is doubled, the force becomes 1/(2^2) = 1/4 of the original force.
Correct Answer: A — It becomes four times weaker
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Q. If the distance between two masses is doubled, how does the gravitational force change?
A.
It becomes four times weaker
B.
It becomes twice weaker
C.
It remains the same
D.
It becomes four times stronger
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Solution
According to the inverse square law, if the distance is doubled, the force becomes 1/(2^2) = 1/4, or four times weaker.
Correct Answer: A — It becomes four times weaker
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Q. If the distance between two masses is doubled, what happens to the gravitational force between them? (2020)
A.
It doubles
B.
It halves
C.
It becomes one-fourth
D.
It becomes four times
Show solution
Solution
According to the inverse square law, if the distance is doubled, the force becomes 1/(2^2) = 1/4 of the original force.
Correct Answer: C — It becomes one-fourth
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Q. If the distance between two masses is halved, how does the gravitational force between them change?
A.
It remains the same
B.
It doubles
C.
It quadruples
D.
It halves
Show solution
Solution
F = G * (m1 * m2) / r², if r is halved, F increases by a factor of 4.
Correct Answer: C — It quadruples
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Q. If the distance between two masses is halved, how does the gravitational force change?
A.
It becomes four times stronger
B.
It becomes twice stronger
C.
It remains the same
D.
It becomes half as strong
Show solution
Solution
If the distance is halved, the force becomes 1/(1/2)^2 = 4 times stronger.
Correct Answer: A — It becomes four times stronger
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Q. If the distance between two masses is tripled, how does the gravitational force change?
A.
It becomes 1/3
B.
It becomes 1/9
C.
It becomes 1/6
D.
It remains the same
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Solution
F ∝ 1/r²; if r is tripled, F becomes F/9.
Correct Answer: B — It becomes 1/9
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Q. If the distance between two objects is doubled, how does the gravitational force between them change?
A.
It doubles
B.
It halves
C.
It becomes one-fourth
D.
It remains the same
Show solution
Solution
Gravitational force F ∝ 1/r². If r is doubled, F becomes F/4.
Correct Answer: C — It becomes one-fourth
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Q. If the distance between two point charges is tripled, how does the electrostatic force between them change? (2020)
A.
It triples
B.
It halves
C.
It becomes one-ninth
D.
It remains the same
Show solution
Solution
According to Coulomb's law, the force F is inversely proportional to the square of the distance (F ∝ 1/r^2). If r is tripled, F becomes 1/9 of its original value.
Correct Answer: C — It becomes one-ninth
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Q. If the distance from a mass is doubled, how does the gravitational field strength change?
A.
It doubles.
B.
It halves.
C.
It becomes one-fourth.
D.
It becomes one-eighth.
Show solution
Solution
The gravitational field strength is inversely proportional to the square of the distance, so it becomes one-fourth.
Correct Answer: C — It becomes one-fourth.
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Q. If the distance from the center of the Earth is doubled, how does the gravitational field strength change?
A.
It doubles.
B.
It halves.
C.
It becomes zero.
D.
It quadruples.
Show solution
Solution
The gravitational field strength varies inversely with the square of the distance, so if the distance is doubled, the field strength becomes 1/4.
Correct Answer: B — It halves.
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Q. If the distance from the center of the Earth is doubled, how does the gravitational potential change?
A.
It doubles.
B.
It halves.
C.
It becomes zero.
D.
It quadruples.
Show solution
Solution
The gravitational potential is inversely proportional to the distance, so if the distance is doubled, the potential halves.
Correct Answer: B — It halves.
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Q. If the distance from the center of the Earth is doubled, what happens to the gravitational field strength?
A.
It doubles.
B.
It halves.
C.
It becomes one-fourth.
D.
It becomes zero.
Show solution
Solution
The gravitational field strength varies inversely with the square of the distance from the center of the Earth, so if the distance is doubled, the field strength becomes one-fourth.
Correct Answer: C — It becomes one-fourth.
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Q. If the distance from the slits to the screen in a double-slit experiment is increased, what happens to the fringe pattern? (2023)
A.
Fringe width decreases
B.
Fringe width increases
C.
Fringe visibility decreases
D.
Fringe pattern disappears
Show solution
Solution
Increasing the distance from the slits to the screen increases the fringe width, as fringe width β is proportional to the distance.
Correct Answer: B — Fringe width increases
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Q. If the Earth were to suddenly shrink in size but maintain its mass, what would happen to the gravitational force at its surface?
A.
It would increase
B.
It would decrease
C.
It would remain the same
D.
It would become zero
Show solution
Solution
If the Earth shrinks in size while maintaining its mass, the gravitational force at the surface would increase due to the decrease in radius.
Correct Answer: A — It would increase
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Q. If the Earth were to suddenly shrink to half its radius while keeping its mass constant, what would happen to the gravitational acceleration at its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would quadruple
Show solution
Solution
If the radius is halved, the gravitational acceleration would increase by a factor of 4 (g ∝ 1/R²).
Correct Answer: A — It would double
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Q. If the Earth were to suddenly shrink to half its radius while keeping its mass constant, what would happen to the gravitational force at its surface?
A.
It would remain the same
B.
It would double
C.
It would become half
D.
It would become four times stronger
Show solution
Solution
If the radius is halved, the gravitational force increases by a factor of 4, since F = GM/R^2.
Correct Answer: D — It would become four times stronger
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Q. If the Earth were to suddenly shrink to half its radius while maintaining its mass, what would happen to the gravitational force at its surface?
A.
It would double
B.
It would remain the same
C.
It would become half
D.
It would become four times stronger
Show solution
Solution
The gravitational force at the surface is inversely proportional to the square of the radius. If the radius is halved, the force becomes four times stronger.
Correct Answer: D — It would become four times stronger
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Q. If the eccentricity of a parabola is e, what is the value of e?
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Solution
The eccentricity of a parabola is always equal to 1.
Correct Answer: B — 1
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Q. If the electric field at a point is 100 N/C and the charge at that point is +5μC, what is the force experienced by the charge?
A.
0.5 N
B.
0.2 N
C.
0.1 N
D.
0.4 N
Show solution
Solution
Force F = E * q = 100 N/C * 5 × 10^-6 C = 0.0005 N = 0.5 N.
Correct Answer: A — 0.5 N
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Q. If the electric field at a point is 1000 N/C and the charge at that point is 5 µC, what is the force experienced by the charge?
A.
0.005 N
B.
0.05 N
C.
0.5 N
D.
5 N
Show solution
Solution
F = E * q = 1000 N/C * 5 × 10^-6 C = 0.005 N.
Correct Answer: B — 0.05 N
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Q. If the electric field at a point is 200 N/C and the charge at that point is +5μC, what is the force experienced by the charge?
A.
0.1 N
B.
1 N
C.
0.5 N
D.
2 N
Show solution
Solution
F = E * q = 200 N/C * 5 × 10^-6 C = 1 N.
Correct Answer: B — 1 N
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Q. If the electric field at a point is 200 N/C directed towards the charge, what is the nature of the charge?
A.
Positive
B.
Negative
C.
Neutral
D.
Cannot be determined
Show solution
Solution
The electric field is directed towards the charge, indicating that the charge is negative.
Correct Answer: B — Negative
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