Q. If the radius of a circle is doubled, how does the area change? (2021)
A.
It doubles
B.
It triples
C.
It quadruples
D.
It remains the same
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Solution
Area = πr²; if r is doubled, area = π(2r)² = 4πr², so it quadruples.
Correct Answer: C — It quadruples
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Q. If the radius of a circle is doubled, what happens to its area? (2020)
A.
It remains the same
B.
It doubles
C.
It triples
D.
It quadruples
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Solution
The area of a circle is given by A = πr². If the radius is doubled (r becomes 2r), the new area is A' = π(2r)² = 4πr², which is four times the original area.
Correct Answer: D — It quadruples
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Q. If the radius of a circle is halved, by what factor does the circumference decrease? (2020)
A.
1/2
B.
1/4
C.
1/3
D.
1/6
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Solution
Circumference = 2πr; If r is halved, new circumference = πr; Factor = 1/2.
Correct Answer: A — 1/2
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Q. If the radius of a circle is halved, how does the circumference change? (2021)
A.
Halved
B.
Remains the same
C.
Doubled
D.
Tripled
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Solution
Circumference = 2πr. If radius is halved, new circumference = 2π(r/2) = πr, which is halved.
Correct Answer: A — Halved
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Q. If the radius of a circle is halved, how does the circumference change? (2022) 2022
A.
Halved
B.
Remains the same
C.
Doubled
D.
Quadrupled
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Solution
Circumference = 2πr. If radius is halved, new circumference = 2π(r/2) = πr, which is halved.
Correct Answer: A — Halved
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Q. If the radius of a circle is tripled, by what factor does the area increase? (2021)
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Solution
Area increases by a factor of (3r)²/r² = 9.
Correct Answer: C — 9
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Q. If the radius of a circle is tripled, how does the area change? (2019)
A.
Increases by 3 times
B.
Increases by 6 times
C.
Increases by 9 times
D.
Remains the same
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Solution
Area = πr². If radius is tripled, new area = π(3r)² = 9πr², which is 9 times the original area.
Correct Answer: C — Increases by 9 times
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Q. If the radius of a circular loop carrying current is doubled, how does the magnetic field at the center change?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
The magnetic field at the center of a circular loop is inversely proportional to the radius; thus, doubling the radius halves the magnetic field.
Correct Answer: B — It halves
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Q. If the radius of a circular loop carrying current is doubled, what happens to the magnetic field at the center of the loop?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
The magnetic field at the center of a circular loop is given by B = (μ₀I)/(2r). If the radius is doubled, the magnetic field strength is halved.
Correct Answer: B — It halves
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Q. If the radius of a circular loop carrying current is halved, how does the magnetic field at the center change?
A.
Remains the same
B.
Doubles
C.
Halves
D.
Quadruples
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Solution
The magnetic field at the center is inversely proportional to the radius, so it quadruples.
Correct Answer: D — Quadruples
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Q. If the radius of a disc is doubled while keeping its mass constant, how does its moment of inertia change?
A.
It remains the same
B.
It doubles
C.
It quadruples
D.
It halves
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Solution
The moment of inertia of a disc is I = 1/2 MR^2. If R is doubled, I becomes 1/2 M(2R)^2 = 2MR^2, which is quadrupled.
Correct Answer: C — It quadruples
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Q. If the radius of a disk is doubled while keeping its mass constant, how does its moment of inertia change?
A.
Increases by a factor of 2
B.
Increases by a factor of 4
C.
Remains the same
D.
Decreases by a factor of 4
Show solution
Solution
The moment of inertia of a disk is I = 1/2 MR^2. If R is doubled, I becomes 1/2 M(2R)^2 = 2MR^2, which is 4 times the original.
Correct Answer: B — Increases by a factor of 4
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Q. If the radius of a planet is halved while keeping its mass constant, how does the gravitational acceleration at its surface change?
A.
It becomes four times stronger
B.
It becomes twice stronger
C.
It remains the same
D.
It becomes half as strong
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Solution
If the radius is halved, the gravitational acceleration becomes four times stronger, as g is inversely proportional to the square of the radius.
Correct Answer: A — It becomes four times stronger
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Q. If the radius of a planet is halved, what happens to the gravitational acceleration on its surface?
A.
It doubles
B.
It halves
C.
It becomes one-fourth
D.
It remains the same
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Solution
g ∝ 1/R². If R is halved, g becomes 4 times greater.
Correct Answer: A — It doubles
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Q. If the radius of a rotating disc is doubled while keeping the mass constant, how does the angular momentum change if the angular velocity remains the same?
A.
It doubles
B.
It remains the same
C.
It quadruples
D.
It halves
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Solution
Angular momentum L = Iω; if radius is doubled, moment of inertia I increases by a factor of 4, hence L quadruples.
Correct Answer: C — It quadruples
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Q. If the radius of a rotating object is halved while keeping the angular velocity constant, what happens to the linear velocity at the edge?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It becomes zero
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Solution
Linear velocity v = rω. If r is halved and ω remains constant, v also halves.
Correct Answer: B — It halves
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Q. If the radius of a rotating object is halved while keeping the angular velocity constant, what happens to its linear velocity? (2022)
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Linear velocity v = rω, so if r is halved and ω remains constant, v also halves.
Correct Answer: B — It halves
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Q. If the radius of a rotating object is halved while keeping the mass constant, how does its moment of inertia change?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It reduces to one-fourth
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Solution
Moment of inertia I is proportional to the square of the radius, so halving the radius reduces I to one-fourth.
Correct Answer: D — It reduces to one-fourth
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Q. If the radius of a rotating wheel is halved while keeping the angular velocity constant, what happens to the linear velocity of a point on the edge of the wheel?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It becomes zero
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Solution
Linear velocity v = rω; if r is halved and ω remains constant, v is halved.
Correct Answer: B — It halves
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Q. If the radius of a solid disk is doubled while keeping its mass constant, how does its moment of inertia change?
A.
Increases by a factor of 2
B.
Increases by a factor of 4
C.
Remains the same
D.
Decreases by a factor of 2
Show solution
Solution
The moment of inertia of a solid disk is I = 1/2 MR^2. If R is doubled, I becomes 1/2 M(2R)^2 = 2MR^2, which is 4 times the original.
Correct Answer: B — Increases by a factor of 4
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Q. If the radius of a spherical Gaussian surface is doubled while keeping the charge inside constant, how does the electric field change?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
The electric field E due to a point charge decreases with the square of the distance from the charge, so if the radius is doubled, the electric field halves.
Correct Answer: B — It halves
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Q. If the radius of a spherical Gaussian surface is doubled, how does the electric field change if the enclosed charge remains constant?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
The electric field E due to a point charge decreases with the square of the distance from the charge, so if the radius is doubled, the electric field halves.
Correct Answer: B — It halves
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Q. If the radius of a spherical Gaussian surface is doubled, how does the electric field due to a point charge at its center change?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It becomes zero
Show solution
Solution
The electric field due to a point charge is independent of the radius of the Gaussian surface; it remains the same.
Correct Answer: C — It remains the same
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Q. If the radius of curvature of a concave mirror is 20 cm, what is its focal length? (2022)
A.
5 cm
B.
10 cm
C.
15 cm
D.
20 cm
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Solution
The focal length (f) of a concave mirror is given by f = R/2, where R is the radius of curvature. Thus, f = 20 cm / 2 = 10 cm.
Correct Answer: B — 10 cm
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Q. If the radius of curvature of a concave mirror is 40 cm, what is its focal length?
A.
10 cm
B.
20 cm
C.
30 cm
D.
40 cm
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Solution
The focal length f of a mirror is given by f = R/2. Thus, f = 40 cm / 2 = 20 cm.
Correct Answer: B — 20 cm
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Q. If the radius of curvature of a convex lens is 20 cm, what is its focal length? (2022)
A.
10 cm
B.
20 cm
C.
30 cm
D.
40 cm
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Solution
The focal length f of a lens is given by f = R/2. Therefore, f = 20 cm / 2 = 10 cm.
Correct Answer: B — 20 cm
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Q. If the radius of curvature of a convex mirror is 20 cm, what is its focal length? (2022)
A.
10 cm
B.
20 cm
C.
30 cm
D.
40 cm
Show solution
Solution
The focal length (f) of a mirror is given by f = R/2. For a convex mirror, R is positive, so f = 20 cm / 2 = 10 cm.
Correct Answer: A — 10 cm
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Q. If the radius of curvature of a convex mirror is 30 cm, what is its focal length?
A.
10 cm
B.
15 cm
C.
20 cm
D.
30 cm
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Solution
The focal length f of a mirror is given by f = R/2. For a convex mirror, R = 30 cm, so f = 30/2 = 15 cm.
Correct Answer: B — 15 cm
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Q. If the radius of curvature of a lens is 20 cm, what is the focal length of the lens assuming it is made of glass with a refractive index of 1.5?
A.
10 cm
B.
15 cm
C.
20 cm
D.
30 cm
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Solution
Using the lens maker's formula, f = R/(n-1) = 20/(1.5-1) = 40 cm.
Correct Answer: A — 10 cm
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Q. If the radius of curvature of a lens is 30 cm and the refractive index is 1.5, what is the focal length of the lens?
A.
10 cm
B.
15 cm
C.
20 cm
D.
25 cm
Show solution
Solution
Using the lens maker's formula, f = R/(n-1) = 30/(1.5-1) = 30/0.5 = 60 cm.
Correct Answer: B — 15 cm
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