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If the radius of curvature of a lens is 30 cm and the refractive index is 1.5, w
If the radius of curvature of a lens is 30 cm and the refractive index is 1.5, what is the focal length of the lens?
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Q1
If the radius of curvature of a lens is 30 cm and the refractive index is 1.5, what is the focal length of the lens?
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Using the lens maker's formula, f = R/(n-1) = 30/(1.5-1) = 30/0.5 = 60 cm.
Questions & Step-by-step Solutions
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Q
Q: If the radius of curvature of a lens is 30 cm and the refractive index is 1.5, what is the focal length of the lens?
Solution:
Using the lens maker's formula, f = R/(n-1) = 30/(1.5-1) = 30/0.5 = 60 cm.
Steps: 7
Show Steps
Step 1: Identify the given values. The radius of curvature (R) is 30 cm and the refractive index (n) is 1.5.
Step 2: Write down the lens maker's formula: f = R / (n - 1).
Step 3: Substitute the values into the formula: f = 30 / (1.5 - 1).
Step 4: Calculate the value inside the parentheses: 1.5 - 1 = 0.5.
Step 5: Substitute this value back into the formula: f = 30 / 0.5.
Step 6: Perform the division: 30 divided by 0.5 equals 60.
Step 7: Conclude that the focal length (f) of the lens is 60 cm.
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