The peak voltage V0 is given directly in the equation as 10V.

In a purely inductive AC circuit, the current lags the voltage by 90 degrees.

The average power (P) in an AC circuit is given by P = V_rms²/R, where R is the resistance.

Reactance is measured in Ohms, just like resistance.

In an adiabatic process, the relationship is given by PV^n = constant, where n is the heat capacity ratio.

In an adiabatic process, as the temperature decreases, the pressure also decreases due to the ideal gas law.

In an adiabatic process, there is no heat exchange with the surroundings, meaning no heat is absorbed or released.

In an adiabatic process, there is no heat exchange, so the internal energy remains constant for an ideal gas.

Plants are primary producers as they convert sunlight into chemical energy through photosynthesis.

In an electrochemical cell, oxidation occurs at the anode.

In an isochoric process, the volume of the system remains constant.

In an isochoric process, the volume remains constant.

For an ideal gas, the internal energy depends only on temperature. Since the temperature remains constant in an isothermal process, the internal energy also remains constant.

In an isothermal process, the temperature of the system remains constant.

Net reactance X = XL - XC = 30Ω - 20Ω = 10Ω.

Calculate XL = 2πfL = 31.42Ω and XC = 1/(2πfC) = 159.15Ω. Z = √(R² + (XL - XC)²) = √(10² + (31.42 - 159.15)²) = 15.81Ω.

Total impedance Z = √(R² + (XL - XC)²) = √(6² + (8 - 4)²) = √(36 + 16) = √52 ≈ 10Ω.

The quality factor Q is inversely proportional to resistance. Increasing resistance decreases Q.

Resonance in an RLC circuit occurs when the inductive reactance equals the capacitive reactance, resulting in maximum current at a specific frequency.

At resonance, the impedance in an RLC circuit is at a minimum.

If the inductive reactance (XL) is greater than the capacitive reactance (XC), the circuit is inductive.

The resonant frequency f0 = 1/(2π√(LC)) = 1/(2π√(0.1 * 100e-6)) = 159 Hz.

Using f = 1/(2π√(LC)), we find f = 1/(2π√(0.1 * 100e-6)) ≈ 159 Hz.

Using Z = √(R² + X²), we find X = √(Z² - R²). Here, Z = 20Ω, R = 15Ω.

Using Z = √(R² + (XL)²), solve for XL.

Using Z = √(R² + X²), we find X = √(Z² - R²) = √(50² - 30²) = √(2500 - 900) = √1600 = 40 ohms.

At resonance in an RLC series circuit, the impedance is equal to the resistance.

Pioneer species are the first organisms to colonize previously uninhabited or disturbed environments.

1 mole of Cu²⁺ deposits 63.5 g of copper.

Using the formula: moles = (current × time) / (n × F), where n=1 for electrons and F=96500 C/mol.