The last term of an AP is given by a + (n-1)d. Here, 100 = 10 + (20-1)d. Solving gives d = 5.

The first term a = 2 and the common difference d = 3. The 15th term = a + (15-1)d = 2 + 42 = 44.

The passage clarifies that inequality is multifaceted and not limited to economic factors.

The passage does not mention government negligence as a reason for the persistence of inequalities.

The passage does not support the idea of promoting unregulated economic growth as a method to address inequalities.

Since 1000 can be expressed as 10^3, we have 10^x = 10^3, thus x = 3.

Since 1000 can be expressed as 10^3, we have 10^(x+2) = 10^3, thus x + 2 = 3, leading to x = 1.

Since 64 can be expressed as 4^3, we have 4^(x-1) = 4^3, thus x - 1 = 3, leading to x = 4.

Since 1/49 can be expressed as 7^(-2), we have 7^x = 7^(-2), thus x = -2.

To find f(4), substitute x with 4: f(4) = 3(4) + 2 = 12 + 2 = 14.

In the linear function f(x) = mx + b, 'm' represents the slope. Here, the slope is 2.

In the linear function f(x) = mx + b, 'm' represents the slope. Here, m = 2.

In the polynomial P(x), the coefficient of x^2 is -4.

In the polynomial P(x), the coefficient of the x^2 term is -4.

The exponent zero indicates the multiplicative identity, meaning any non-zero number raised to the power of zero equals one.

Using the property of exponents, a^3 * a^(-2) = a^(3 - 2) = a^1, hence x = 1.

Substituting a = 2, we have 2^3 * b^2 = 64, which simplifies to 8b^2 = 64. Thus, b^2 = 8, leading to b = 4.

If a = b, then a^x = b^y implies x must equal y for the equality to hold.

The definition of logarithms states that if log_a(b) = c, then a raised to the power of c equals b, hence a^c = b.

Let the first term be a and the common ratio be r. Then, 2nd term = ar = 8 and 4th term = ar^3 = 32. Dividing gives r^2 = 4, so r = 2.

Let the first term be a and the common difference be d. From the equations a + d = 8 and a + 4d = 14, we can find the 3rd term a + 2d = 10.

Let the first term be a. Then, the 3rd term is ar^2 = 27. Thus, a * 3^2 = 27, giving a = 3.

Let the first term be a and the common difference be d. From the equations a + 4d = 15 and a + 9d = 30, we can find d = 3.

Let the first term be a and the common difference be d. From the equations a + 5d = 30 and a + 8d = 45, we can find d = 5.

Using the formula for the nth term, a + 6d = 50. Substituting d = 5 gives a + 30 = 50, hence a = 20.

Rearranging the equation to y = -2/3x + 2 shows that the slope is -2/3.

'm' represents the slope of the line in the slope-intercept form of a linear equation.

The 6th term is given by 7 * 3^(6-1) = 7 * 243 = 1701.

The first term is 1, and the second term's reciprocal will be 1 + 2 = 3. Therefore, the second term is 1/3.

The reciprocals of the terms are 1, 3, and 1/x. The common difference is 2, so 1/x = 3 + 2 = 5, thus x = 1/5.