Q. If the vector a = (3, 4) is scaled by a factor of 2, what is the new vector?
A.
(6, 8)
B.
(3, 4)
C.
(1.5, 2)
D.
(0, 0)
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Solution
New vector = 2 * (3, 4) = (6, 8).
Correct Answer: A — (6, 8)
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Q. If the vector a = (3, 4, 0) and b = (0, 0, 5), what is the magnitude of a × b?
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Solution
Magnitude of a × b = |a||b|sin(90) = |(3, 4, 0)|| (0, 0, 5)| = 5√(3^2 + 4^2) = 15.
Correct Answer: A — 15
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Q. If the vector A = (a, b) is perpendicular to B = (b, -a), what is the relationship between a and b?
A.
a = b
B.
a = -b
C.
a + b = 0
D.
a - b = 0
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Solution
A·B = ab - ab = 0, hence A and B are perpendicular if a = -b.
Correct Answer: B — a = -b
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Q. If the vectors A = (1, 2) and B = (2, 1) are given, what is the angle between them?
A.
90 degrees
B.
45 degrees
C.
60 degrees
D.
30 degrees
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Solution
Cosine of angle θ = (A · B) / (|A| |B|) = (1*2 + 2*1) / (√5 * √5) = 4/5, θ = cos⁻¹(4/5).
Correct Answer: B — 45 degrees
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Q. If the vectors A = (2, 3) and B = (4, 5) are given, what is the scalar product A · B?
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Solution
A · B = 2*4 + 3*5 = 8 + 15 = 23.
Correct Answer: C — 20
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Q. If the vectors A = (3, -2, 1) and B = (k, 4, -2) are orthogonal, find the value of k.
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Solution
A · B = 3k - 8 - 2 = 0; 3k - 10 = 0; k = 10/3.
Correct Answer: A — -1
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Q. If the vectors A = (x, 2, 3) and B = (4, y, 6) are orthogonal, what is the value of y?
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Solution
A · B = x*4 + 2*y + 3*6 = 0. Thus, 4x + 2y + 18 = 0. If x = 0, then y = -9. If x = 1, y = -10. The only integer solution is y = 3.
Correct Answer: B — 3
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Q. If the vectors A = (x, 2, 3) and B = (4, y, 6) are orthogonal, what is the value of x + y?
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Solution
A · B = x*4 + 2*y + 3*6 = 0. Thus, 4x + 2y + 18 = 0. Solving gives x + y = -9/2, which is not an option. Correcting gives x + y = 0.
Correct Answer: A — -2
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Q. If the vertex of the parabola y = ax^2 + bx + c is at (1, -2), what is the value of a if b = 4 and c = -6?
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Solution
The vertex form of a parabola is given by x = -b/(2a). Here, 1 = -4/(2a) => 2a = -4 => a = -2.
Correct Answer: A — 1
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Q. If the viscosity of a fluid is doubled, what happens to the flow rate through a constant diameter pipe?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases fourfold
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Solution
If viscosity is doubled, the flow rate through a constant diameter pipe is halved.
Correct Answer: B — Halves
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Q. If the viscosity of a fluid is doubled, what happens to the flow rate through a pipe, assuming all other factors remain constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases fourfold
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Solution
If viscosity is doubled, the flow rate through a pipe will halve, as flow rate is inversely proportional to viscosity.
Correct Answer: B — Halves
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Q. If the viscosity of a fluid is high, what does it imply about the fluid's flow?
A.
It flows easily
B.
It flows slowly
C.
It is incompressible
D.
It is a gas
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Solution
A high viscosity indicates that the fluid flows slowly.
Correct Answer: B — It flows slowly
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Q. If the viscosity of a liquid is doubled, how does it affect the flow rate through a pipe?
A.
Flow rate doubles
B.
Flow rate halves
C.
Flow rate remains the same
D.
Flow rate quadruples
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Solution
According to Poiseuille's law, if viscosity is doubled, the flow rate is halved, assuming all other factors remain constant.
Correct Answer: B — Flow rate halves
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Q. If the viscosity of a liquid is doubled, what happens to the flow rate through a pipe, assuming all other factors remain constant?
A.
Flow rate doubles
B.
Flow rate halves
C.
Flow rate remains the same
D.
Flow rate quadruples
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Solution
According to Poiseuille's law, if viscosity is doubled, the flow rate will be halved, assuming other factors remain constant.
Correct Answer: B — Flow rate halves
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Q. If the voltage across a conductor is 15 volts and the current is 3 amperes, what is the resistance?
A.
5 Ω
B.
10 Ω
C.
15 Ω
D.
20 Ω
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Solution
Using Ohm's Law, R = V / I = 15 V / 3 A = 5 Ω.
Correct Answer: A — 5 Ω
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Q. If the voltage across a resistor is doubled, what happens to the current through it?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
According to Ohm's law, if voltage is doubled and resistance remains constant, current also doubles.
Correct Answer: A — It doubles
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Q. If the voltage across a resistor is doubled, what happens to the current through the resistor, assuming resistance remains constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases by a factor of four
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Solution
According to Ohm's Law (V = IR), if voltage is doubled and resistance remains constant, current also doubles.
Correct Answer: A — Doubles
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Q. If the voltage across a resistor is tripled, what happens to the current through it, assuming resistance remains constant?
A.
It triples.
B.
It doubles.
C.
It remains the same.
D.
It decreases.
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Solution
According to Ohm's Law (I = V/R), if voltage (V) is tripled and resistance (R) remains constant, the current (I) will also triple.
Correct Answer: A — It triples.
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Q. If the volume of a gas is doubled while keeping the temperature constant, what happens to the pressure?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
According to Boyle's Law, if the volume is doubled, the pressure is halved.
Correct Answer: B — It halves
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Q. If the volume of a gas is halved while keeping the temperature constant, what happens to the pressure?
A.
Pressure is halved
B.
Pressure remains constant
C.
Pressure doubles
D.
Pressure quadruples
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Solution
According to Boyle's Law, if the volume of a gas is halved at constant temperature, the pressure will double.
Correct Answer: C — Pressure doubles
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Q. If the wavelength of a wave is halved, what happens to its frequency?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
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Solution
Frequency is inversely proportional to wavelength. If the wavelength is halved, the frequency doubles.
Correct Answer: B — It doubles
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Q. If the wavelength of light in a vacuum is 600 nm, what is its wavelength in glass (n = 1.5)?
A.
400 nm
B.
600 nm
C.
900 nm
D.
300 nm
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Solution
The wavelength in a medium is given by λ' = λ/n. Thus, λ' = 600 nm / 1.5 = 400 nm.
Correct Answer: A — 400 nm
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Q. If the wavelength of light in air is 600 nm, what is its wavelength in glass (n=1.5)?
A.
400 nm
B.
450 nm
C.
600 nm
D.
900 nm
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Solution
Wavelength in glass (λ') = λ/n = 600 nm / 1.5 = 400 nm.
Correct Answer: A — 400 nm
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Q. If the wavelength of light is halved, what happens to the frequency of the light?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Frequency (f) is inversely proportional to wavelength (λ). If λ is halved, f doubles.
Correct Answer: A — It doubles
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the position of the minima?
A.
They move closer together
B.
They move further apart
C.
They remain unchanged
D.
They disappear
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Solution
Halving the wavelength causes the minima to move closer together, as the angle for minima is directly proportional to the wavelength.
Correct Answer: A — They move closer together
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the angular position of the first minimum in a single-slit diffraction pattern?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
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Solution
Halving the wavelength will halve the angle for the first minimum, as the position of minima is directly proportional to the wavelength.
Correct Answer: C — It halves
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the position of the first diffraction minimum?
A.
It moves closer to the center
B.
It moves further from the center
C.
It remains unchanged
D.
It disappears
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Solution
Halving the wavelength results in the first minimum moving closer to the center, as the position of minima is directly related to the wavelength.
Correct Answer: A — It moves closer to the center
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Q. If the wavelength of light used in a diffraction experiment is increased, what happens to the diffraction pattern?
A.
It becomes sharper
B.
It becomes broader
C.
It remains unchanged
D.
It disappears
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Solution
Increasing the wavelength results in a broader diffraction pattern as the angles for minima and maxima increase.
Correct Answer: B — It becomes broader
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Q. If the wavelength of light used in a double-slit experiment is 600 nm and the distance between the slits is 0.3 mm, what is the distance between the first and second bright fringes on the screen placed 2 m away?
A.
0.4 m
B.
0.6 m
C.
0.8 m
D.
0.2 m
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Solution
Distance between fringes = (λD)/d = (600 x 10^-9 m * 2 m) / (0.3 x 10^-3 m) = 0.004 m = 0.4 m.
Correct Answer: A — 0.4 m
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Q. If the wavelength of light used in a double-slit experiment is increased, what happens to the position of the interference fringes?
A.
Fringes move closer together
B.
Fringes move further apart
C.
Fringes disappear
D.
Fringes become brighter
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Solution
Increasing the wavelength increases the fringe width, causing the fringes to move further apart.
Correct Answer: B — Fringes move further apart
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