Q. What is the mass of 3 moles of carbon dioxide (CO2)?
A.
44 g
B.
66 g
C.
132 g
D.
22 g
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Solution
The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 3 moles of CO2 weigh 3 x 44 g = 132 g.
Correct Answer: A — 44 g
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Q. What is the mass of 3 moles of NaCl?
A.
87 g
B.
58.5 g
C.
174 g
D.
3 g
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Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.
Correct Answer: C — 174 g
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Q. What is the mass of 3 moles of sulfuric acid (H2SO4)?
A.
98 g
B.
196 g
C.
294 g
D.
392 g
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Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.
Correct Answer: B — 196 g
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Q. What is the mass of KCl produced when 10 g of K reacts with excess Cl2?
A.
74.5 g
B.
10 g
C.
20 g
D.
30 g
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Solution
10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.
Correct Answer: A — 74.5 g
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Q. What is the mass of water produced when 2 moles of hydrogen react with 1 mole of oxygen?
A.
18 g
B.
36 g
C.
54 g
D.
9 g
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Solution
2 moles of H2 produce 2 moles of H2O. Mass of H2O = 2 moles * 18 g/mole = 36 g.
Correct Answer: A — 18 g
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Q. What is the mass percent of a solution containing 20 g of NaCl in 180 g of water?
A.
10%
B.
20%
C.
25%
D.
15%
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Solution
Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.
Correct Answer: A — 10%
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Q. What is the mass percent of a solution containing 20 g of solute in 180 g of solution?
A.
10%
B.
20%
C.
25%
D.
15%
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Solution
Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.
Correct Answer: B — 20%
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Q. What is the mass percent of a solution containing 20 g of solute in 200 g of solution?
A.
10%
B.
20%
C.
5%
D.
15%
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Solution
Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.
Correct Answer: B — 20%
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Q. What is the maximum intensity ratio in interference of two waves of equal amplitude?
A.
1:1
B.
2:1
C.
4:1
D.
3:1
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Solution
Maximum intensity (I_max) = 4I_0 for two waves of equal amplitude (I_0). Thus, the ratio is 4:1.
Correct Answer: C — 4:1
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Q. What is the maximum kinetic energy of photoelectrons emitted if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?
A.
1 eV
B.
3 eV
C.
5 eV
D.
7 eV
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Solution
Maximum kinetic energy (K.E.) = hf - Φ = (6.626 x 10^-34 J·s)(8 x 10^14 Hz) - 3 eV = 5 eV.
Correct Answer: C — 5 eV
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Q. What is the maximum kinetic energy of photoelectrons emitted when light of frequency 8 x 10^14 Hz is incident on a metal with work function 3 eV?
A.
1 eV
B.
3 eV
C.
5 eV
D.
7 eV
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Solution
Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.
Correct Answer: C — 5 eV
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Q. What is the maximum kinetic energy of photoelectrons if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?
A.
1 eV
B.
3 eV
C.
5 eV
D.
7 eV
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Solution
Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.
Correct Answer: C — 5 eV
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Q. What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?
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Solution
The maximum number of observable maxima is given by d/λ, where d = 0.1 mm and λ = 500 nm. This gives approximately 10 maxima.
Correct Answer: B — 10
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Q. What is the maximum number of electrons in the d-subshell?
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Solution
The d-subshell can hold a maximum of 10 electrons.
Correct Answer: C — 10
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Q. What is the maximum number of electrons in the n=2 shell?
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Solution
The maximum number of electrons in the n=2 shell is 2(2^2) = 8.
Correct Answer: B — 4
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Q. What is the maximum number of electrons that can be accommodated in a shell with quantum number n=4?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=4, it is 2(4^2) = 32.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can be accommodated in a shell with principal quantum number n=5?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can be accommodated in a shell with n=3?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer: B — 18
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Q. What is the maximum number of electrons that can be accommodated in a subshell with the quantum number l = 2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can be accommodated in the n=2 shell?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=2, this is 2(2^2) = 8.
Correct Answer: B — 4
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Q. What is the maximum number of electrons that can be accommodated in the n=5 shell?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can occupy a p subshell?
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Solution
A p subshell can hold a maximum of 6 electrons.
Correct Answer: B — 6
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Q. What is the maximum number of electrons that can occupy a single orbital?
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Solution
A single orbital can hold a maximum of 2 electrons, with opposite spins.
Correct Answer: B — 2
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Q. What is the maximum number of electrons that can occupy a single p subshell?
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Solution
A p subshell can hold a maximum of 6 electrons, as it has three orbitals each capable of holding 2 electrons.
Correct Answer: B — 6
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Q. What is the maximum number of electrons that can occupy a single p-orbital?
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Solution
A single p-orbital can hold a maximum of 2 electrons.
Correct Answer: A — 2
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum number l = 2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, this gives 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum numbers n=3 and l=2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l=2, this gives 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can occupy the 3rd energy level?
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Solution
The maximum number of electrons in an energy level is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer: C — 18
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Q. What is the maximum number of electrons that can occupy the d subshell?
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Solution
The d subshell can hold a maximum of 10 electrons.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can occupy the f subshell?
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Solution
The f subshell can hold a maximum of 14 electrons (7 orbitals, each can hold 2).
Correct Answer: D — 14
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