The length of the latus rectum is given by (2b^2/a). Here, b^2 = 16, a^2 = 36, so length = (2*16/6) = 12.

The length of the latus rectum of the ellipse is given by 2a^2/b.

The length of the latus rectum of a parabola given by the equation y^2 = 4px is 4p. Here, 4p = 12, so p = 3. Therefore, the length of the latus rectum is 4p = 12.

The length of the latus rectum of the parabola y^2 = 4ax is 4a.

The length of the latus rectum of the parabola y^2 = 8x is 4.

Length = √[(2 - (-1))² + (3 - (-1))²] = √[3² + 4²] = √25 = 5.

Length = |5 - 2| = 3.

Median length m_a = 1/2 * √(2b^2 + 2c^2 - a^2) = 1/2 * √(2*8^2 + 2*10^2 - 6^2) = 1/2 * √(128 + 200 - 36) = 1/2 * √292 = 7.

The x-intercept is (4, 0) and the y-intercept is (0, 3). The length of the segment is sqrt((4-0)^2 + (0-3)^2) = sqrt(16 + 9) = 5.

As x approaches infinity, (1/x) approaches 0.

Using L'Hôpital's Rule, lim (x -> 1) (x^2 - 1)/(x - 1) = lim (x -> 1) (2x)/(1) = 2.

As x approaches 0 from the right, f(x) approaches infinity, indicating a discontinuity at x = 0.

The reaction requires 1.5 moles of B for 3 moles of A. Since only 2 moles of B are available, B is the limiting reagent.

The reaction requires 2 moles of B for every mole of A. For 5 moles of A, 10 moles of B are needed. Since only 3 moles of B are available, B is the limiting reagent.

Using Ampere's Law, B = μ₀I/2πr for an infinitely long straight wire.

The magnetic field B at a distance r from a long straight conductor carrying current I is given by B = μ₀I/(2πr) according to Biot-Savart Law.

The magnetic field on the axis of a circular loop is given by B = (μ₀I/(2R)) * (1/(1 + (z/R)²)^(3/2)) where z is the distance along the axis.

The magnetic field on the axis of a circular loop is given by B = (μ₀I)/(2R) * (R²/(R²+x²)^(3/2)).

The magnetic field at the center of a circular loop is given by B = μ₀I/2R.

The magnetic field at the center of a circular loop is given by B = μ₀I/(2R).

The magnetic field at the center of a square loop is B = μ₀I/4a.

At the midpoint, the magnetic fields due to the two currents cancel each other out, resulting in zero net magnetic field.

The magnetic field at a point on the axis of a circular loop at a distance x from the center is given by B = μ₀I/(2(x² + R²)^(3/2)).

The magnetic field B at a distance d from a straight wire carrying current I is given by B = μ₀I/(2πd).

Using Ampere's Law, B = μ₀I/2R² at a point on the axis of a current loop.

The magnetic field due to a long straight wire is given by B = (μ₀I)/(2πr).

The magnetic field due to a magnetic dipole at a point along its axial line is given by B = (μ₀/4π) * (2m/r³).

The magnetic field inside a long solenoid is B = μ₀nI.

Using Biot-Savart Law, B = μ₀I/(2πr) = (4π × 10^-7 Tm/A)(5 A)/(2π(1 m)) = 0.01 T.

Using B = μ₀I/(2πr), substituting μ₀ = 4π × 10⁻⁷ Tm/A, I = 10 A, and r = 0.5 m gives B = 0.4 μT.