What is the magnetic field due to a straight conductor at a point 1 meter away carrying a current of 5 A?
Practice Questions
1 question
Q1
What is the magnetic field due to a straight conductor at a point 1 meter away carrying a current of 5 A?
0.01 T
0.02 T
0.03 T
0.04 T
Using Biot-Savart Law, B = μ₀I/(2πr) = (4π × 10^-7 Tm/A)(5 A)/(2π(1 m)) = 0.01 T.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the magnetic field due to a straight conductor at a point 1 meter away carrying a current of 5 A?
Solution: Using Biot-Savart Law, B = μ₀I/(2πr) = (4π × 10^-7 Tm/A)(5 A)/(2π(1 m)) = 0.01 T.
Steps: 7
Step 1: Identify the formula to calculate the magnetic field (B) due to a straight conductor. The formula is B = (μ₀ * I) / (2 * π * r).
Step 2: Determine the values needed for the formula. Here, μ₀ (the permeability of free space) is 4π × 10^-7 Tm/A, I (the current) is 5 A, and r (the distance from the conductor) is 1 m.
Step 3: Substitute the values into the formula. B = (4π × 10^-7 Tm/A * 5 A) / (2 * π * 1 m).
Step 4: Simplify the equation. The π in the numerator and denominator cancels out, so we have B = (4 × 10^-7 Tm/A * 5 A) / (2 * 1 m).
Step 5: Calculate the numerator: 4 × 5 = 20, so we have B = (20 × 10^-7 T) / 2.
Step 6: Divide 20 by 2 to get 10, so B = 10 × 10^-7 T.
Step 7: Convert 10 × 10^-7 T to a more standard form: B = 0.01 T.
