Q. What is the hybridization of the carbon atoms involved in the double bond of alkenes?
A.
sp
B.
sp2
C.
sp3
D.
sp3d
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Solution
The carbon atoms in the double bond of alkenes are sp2 hybridized.
Correct Answer: B — sp2
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Q. What is the hybridization of the central atom in a molecule with a tetrahedral shape?
A.
sp
B.
sp2
C.
sp3
D.
sp3d
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Solution
A tetrahedral shape corresponds to sp3 hybridization.
Correct Answer: C — sp3
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Q. What is the hybridization of the central atom in CH4?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
In CH4, the central carbon atom forms four equivalent bonds with hydrogen atoms, indicating sp3 hybridization.
Correct Answer: C — sp3
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Q. What is the hybridization of the central atom in CO2?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
The carbon atom in CO2 is sp hybridized, forming two double bonds with oxygen atoms.
Correct Answer: A — sp
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Q. What is the hybridization of the central atom in H2O?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
Oxygen in H2O is sp3 hybridized, forming two bonds and two lone pairs.
Correct Answer: C — sp3
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Q. What is the hybridization of the central atom in N2O?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
The central nitrogen atom in N2O is sp hybridized, leading to a linear arrangement.
Correct Answer: A — sp
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Q. What is the hybridization of the central atom in NH3?
A.
sp
B.
sp2
C.
sp3
D.
sp3d
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Solution
The central nitrogen atom in NH3 is sp3 hybridized due to three bonding pairs and one lone pair.
Correct Answer: C — sp3
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Q. What is the hybridization of the central atom in NH4+?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
The central atom nitrogen in NH4+ undergoes sp3 hybridization to form four equivalent bonds with hydrogen.
Correct Answer: C — sp3
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Q. What is the hybridization of the central atom in O3 (ozone)?
A.
sp
B.
sp2
C.
sp3
D.
dsp2
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Solution
The central oxygen atom in O3 is sp2 hybridized, leading to a bent molecular shape.
Correct Answer: B — sp2
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Q. What is the hybridization of the central atom in ozone (O3)?
A.
sp
B.
sp2
C.
sp3
D.
dsp2
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Solution
In ozone (O3), the central oxygen atom is sp2 hybridized, resulting in a bent molecular shape.
Correct Answer: B — sp2
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Q. What is the hybridization of the central atom in PCl5?
A.
sp
B.
sp2
C.
sp3
D.
sp3d
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Solution
In PCl5, phosphorus is sp3d hybridized, allowing for five bonding pairs.
Correct Answer: D — sp3d
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Q. What is the hybridization of the central atom in SF6?
A.
sp
B.
sp2
C.
sp3
D.
sp3d2
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Solution
The central sulfur atom in SF6 is surrounded by six fluorine atoms, leading to an octahedral geometry and sp3d2 hybridization.
Correct Answer: D — sp3d2
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Q. What is the hybridization of the central atom in SO2?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
The sulfur atom in SO2 is sp2 hybridized, forming one double bond and one single bond.
Correct Answer: B — sp2
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Q. What is the hybridization of the central atom in XeF4?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
The xenon atom in XeF4 is dsp3 hybridized, resulting in a square planar geometry.
Correct Answer: D — dsp3
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Q. What is the hybridization of the central atom in [Ni(CN)4]2-?
A.
sp
B.
sp2
C.
sp3
D.
dsp2
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Solution
In [Ni(CN)4]2-, nickel is in the +2 oxidation state and undergoes dsp2 hybridization to accommodate the four cyanide ligands.
Correct Answer: D — dsp2
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Q. What is the hybridization of the central metal ion in the complex [Cu(NH3)4]2+?
A.
sp
B.
sp2
C.
sp3
D.
dsp2
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Solution
In [Cu(NH3)4]2+, the copper ion undergoes dsp2 hybridization to accommodate four ligands.
Correct Answer: D — dsp2
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Q. What is the hybridization of the central metal ion in [Ni(CO)4]?
A.
sp
B.
sp2
C.
sp3
D.
d2sp3
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Solution
In [Ni(CO)4], the nickel ion undergoes sp3 hybridization to accommodate four CO ligands.
Correct Answer: C — sp3
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Q. What is the hybridization of the nitrogen atom in a primary amine?
A.
sp
B.
sp2
C.
sp3
D.
sp3d
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Solution
The nitrogen atom in a primary amine is sp3 hybridized.
Correct Answer: C — sp3
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Q. What is the hybridization of the nitrogen atom in an amine?
A.
sp
B.
sp2
C.
sp3
D.
sp3d
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Solution
The nitrogen atom in amines is sp3 hybridized, having a tetrahedral geometry with one lone pair.
Correct Answer: C — sp3
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Q. What is the hybridization of the nitrogen atom in NH3?
A.
sp
B.
sp2
C.
sp3
D.
dsp3
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Solution
In NH3, nitrogen has three bonds and one lone pair, leading to sp3 hybridization.
Correct Answer: C — sp3
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Q. What is the hybridization of the phosphorus atom in PCl5?
A.
sp
B.
sp2
C.
sp3
D.
d2sp3
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Solution
In PCl5, phosphorus is surrounded by five chlorine atoms, indicating d2sp3 hybridization.
Correct Answer: D — d2sp3
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Q. What is the ideal gas equation?
A.
PV = nRT
B.
PV = nRT^2
C.
PV = nR/T
D.
PV = nRT^3
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Solution
The ideal gas equation is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Correct Answer: A — PV = nRT
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Q. What is the image distance for a concave lens with a focal length of -12 cm when the object is placed at 24 cm?
A.
-8 cm
B.
8 cm
C.
-12 cm
D.
12 cm
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Solution
Using the lens formula, 1/f = 1/v - 1/u, we find v = -8 cm.
Correct Answer: A — -8 cm
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Q. What is the image distance for a convex lens if the object is placed at 10 cm and the focal length is 5 cm?
A.
-15 cm
B.
15 cm
C.
5 cm
D.
10 cm
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Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 15 cm.
Correct Answer: A — -15 cm
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Q. What is the image distance for a convex lens if the object is placed at 30 cm and the focal length is 10 cm?
A.
15 cm
B.
20 cm
C.
25 cm
D.
30 cm
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Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 15 cm.
Correct Answer: B — 20 cm
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Q. What is the image distance for a convex lens with a focal length of 10 cm when the object is placed 30 cm from the lens?
A.
5 cm
B.
10 cm
C.
15 cm
D.
20 cm
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Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 20 cm.
Correct Answer: D — 20 cm
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Q. What is the impedance of a series circuit containing a resistor (R) and an inductor (L)?
A.
R
B.
√(R^2 + (ωL)^2)
C.
R + ωL
D.
R - ωL
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Solution
The impedance Z = √(R^2 + (ωL)^2) in a series R-L circuit.
Correct Answer: B — √(R^2 + (ωL)^2)
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Q. What is the impedance of a series circuit containing a resistor and an inductor?
A.
R
B.
√(R^2 + (ωL)^2)
C.
R + jωL
D.
R - jωL
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Solution
The impedance Z in a series R-L circuit is given by Z = √(R^2 + (ωL)^2).
Correct Answer: B — √(R^2 + (ωL)^2)
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Q. What is the impedance of a series RLC circuit at resonance?
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Solution
At resonance, the impedance of a series RLC circuit is equal to the resistance R.
Correct Answer: A — R
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Q. What is the induced EMF in a loop of wire if the magnetic field through the loop changes at a rate of dB/dt?
A.
-A(dB/dt)
B.
A(dB/dt)
C.
-L(dB/dt)
D.
L(dB/dt)
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Solution
The induced EMF (ε) is given by Faraday's law as ε = -A(dB/dt), where A is the area of the loop.
Correct Answer: A — -A(dB/dt)
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